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    Q&A - P5 Math

    Scheduled Pinned Locked Moved Primary 5
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    • T Offline
      tianzhu
      last edited by

      Chan09:

      1) mr tan monthly salary is twice mr lee. His monthly savings is 6 times mr lee. Given both of them spend $1000 monthly, how much money does mr tan earn?
      Ans 2500
      Hi

      You may use MD or Units Method.

      Salary
      Mr Tan ----- 2 --------- 10
      Mr Lee ----- 1---------- 5
      Difference -----1------ 5

      Monthly savings
      Mr Tan ----- 6
      Mr Lee ----- 1
      Difference ----- 5 ------ 5

      Since they spent the same amount of $1000 monthly, the difference in the amount of money stays the same (Constant Difference)

      Make the difference in number of units the same.

      10 - 6 ----- 4
      (5 - 1 ----- 4)

      4 units ----- 1000

      1 unit ----- 250

      10 units ------ 2500 (Mr Tan’s salary)

      Best wishes

      1 Reply Last reply Reply Quote 0
      • T Offline
        tianzhu
        last edited by

        Chan09:

        2) out of the 40000 people, 30% were women, 10% children and rest men. Some women left the show with half the no. Of children before it ended. As a result the % of men increased to 75% of the people at the show at the end. How many women were at the show at the end?
        Ans 6000
        At first
        Women ----- 30% ------ 12000
        Children ----- 10% ------ 4000
        Men ------ 60% ------- 24000

        In the end
        Children ------ 2000
        Men ------ 24000 (75%)

        75% ------ 24000
        1% ------ 320

        Women ------ 25% ------- 8000

        Number of women at the end of the show ------ 8000 – 2000 ------ 6000

        Best wishes

        1 Reply Last reply Reply Quote 0
        • P Offline
          peggy
          last edited by

          Hi,


          kindly assist this question from school.

          Salmah, Titus and Umi shared a box of cards.
          Salmah received 25% of what Titus and Umi received altogether.
          Umi received 35% of the cards. If Salmah and Umi received 66 cards altogether, how many cards did Titus receive ?

          I think I had seen similar question here somewhere but don’t seems to be able to locate it…

          1 Reply Last reply Reply Quote 0
          • L Offline
            lizawa
            last edited by

            peggy:
            Hi,


            kindly assist this question from school.

            Salmah, Titus and Umi shared a box of cards.
            Salmah received 25% of what Titus and Umi received altogether.
            Umi received 35% of the cards. If Salmah and Umi received 66 cards altogether, how many cards did Titus receive ?

            I think I had seen similar question here somewhere but don't seems to be able to locate it.....
            Use ratio to solve.

            S : T+U
            = 25 : 100
            = 1 : 4

            U : S+T
            = 35 : 65
            = 7 : 13

            Total units received by 3 of them should be the same. So convert
            S : T+ U
            = 1 : 4
            = 4 : 16
            (because 7 + 13 = 20 )

            S : T : U
            = 4 : 9 : 7
            4u + 7u = 11u (S and U)
            11u -> 66
            1u -> 6
            T: 9u -> 9 x 6 = 54.

            1 Reply Last reply Reply Quote 0
            • P Offline
              peggy
              last edited by

              Hi Lizawa,


              Thanks for your prompt reply and clear explanations !!!

              1 Reply Last reply Reply Quote 0
              • E Offline
                Essential
                last edited by

                Hello Tian Zhu , hope you are there to help me.

                I need your help to solve this question:-
                1) Renjie has three ropes with length of 144cm , 168 cm and 252 cm. He wants to cut the three ropes into shorter pieces of equal length with no remainders. a) What is the greatest possible length of each of the shorter pieces ? b) how many of the shorter pieces of equal length can he get?

                1 Reply Last reply Reply Quote 0
                • T Offline
                  tianzhu
                  last edited by

                  Essential:
                  Hello Tian Zhu , hope you are there to help me.

                  I need your help to solve this question:-
                  1) Renjie has three ropes with length of 144cm , 168 cm and 252 cm. He wants to cut the three ropes into shorter pieces of equal length with no remainders. a) What is the greatest possible length of each of the shorter pieces ? b) how many of the shorter pieces of equal length can he get?
                  Hi

                  Where is your question from?

                  The greatest possible length of each of the shorter pieces must be divisible by 144, 168 and 252.

                  So we are talking about the Highest common factor (HCF).

                  In this case, the greatest possible shorter length is 12.

                  (a)12 ----- for P5 syllabus, I think generally GC/ Logical reasoning is used to find the common factor.

                  Consider the shorter piece of 144cm; the possible shorter lengths are 144*1, 72*2, 36*4, 24*6, 12*12, 6*24.
                  Out of 144, 72,36,24,12, only 12 is divisible by 144, 168 and 252.

                  (b) 252/12 ------ 21, 168/12 ----- 14 and 144/12 ----- 12

                  Number of shorter pieces -----21+14+12 ------ 47

                  Best wishes

                  PS ----- HCF is covered in Secondary One Maths.

                  A good website to learn more about HCF.

                  http://mssia.wordpress.com/2009/05/11/more-practicehelp-on-hcf-lcm-problem-sums/#more-221

                  1 Reply Last reply Reply Quote 0
                  • T Offline
                    tianzhu
                    last edited by

                    Hi Essential


                    Good Morning.

                    To add to my earlier post, I’ve managed to find some sites which may add to our understanding of HCF.

                    In this question, students are expected to find the divisor that exactly divides 144,168 and 252 without remainder.

                    Such a divisor is known as HCF or HCD.

                    HCF or HCD of two or more numbers is the greatest number that can exactly divide each one of the number. It is covered in greater details in secondary one maths.

                    You may read more about HCF from these links.

                    http://www.mathsisfun.com/greatest-common-factor.html

                    Some useful online tools to calculate HCF.

                    http://easycalculation.com/hcf.php
                    http://www.calculatorsoup.com/calculators/math/gcf.php
                    http://www.free-online-calculator-use.com/greatest-common-factor-calculator.html

                    Best wishes

                    1 Reply Last reply Reply Quote 0
                    • P Offline
                      peggy
                      last edited by

                      Please help with this qtn from school.


                      In 3 years’ time, Kenneth will be thrice as old as Richie.
                      Last year, Kenneth was four times as old as Richie.
                      What will be the sum of their ages next year?

                      Thank you.

                      1 Reply Last reply Reply Quote 0
                      • T Offline
                        tianzhu
                        last edited by

                        peggy:
                        Please help with this qtn from school.


                        In 3 years' time, Kenneth will be thrice as old as Richie.
                        Last year, Kenneth was four times as old as Richie.
                        What will be the sum of their ages next year?

                        Thank you.
                        Hi

                        I think many students are familiar with this question.

                        Ming Ming is 6 times as old as her daughter now. Ming Ming will be 4 times as old as her daughter in 4 years’ time. How old is Ming Ming now?

                        Your question is slightly tweaked from the more familiar version.

                        The difference in their ages remains the same. Hence, we are talking about “Constant Difference.”

                        You may use MD. Due to time constraints, I’ll only be providing the pointers for you to draw the MD.

                        Consider their ages one year ago (last year).
                        Draw 4 boxes (4 units) to show Kenneth’s age and 1 box (1 unit) to show Richie’s age.

                        Now, consider their age in 3 years’ time, in this case we need to add a box showing 4 years to the existing unit as we are taking reference from their age one year ago.

                        Kenneth’s age ------- (4+1 unit) + (4+1 unit) + (4+1 unit)
                        Richie’s age ------ (4+1 unit)

                        Compare the MD
                        3 units ------ 2 units + 8
                        1 unit -------8

                        Richie’s age now ------- 8+1 --------9
                        Kenneth’s age now ------- 9+24 ------33

                        The question asks for their combined age next year, so the answer is 44.

                        If you need the MD, please let me know, I'll draw it at a later time.

                        Best wishes.

                        1 Reply Last reply Reply Quote 0

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