O-Level Additional Math

[rubydoll]

Dear sir


Could you please help in the Indices sum attached.

Thannk you.
Ruby doll

[rubydoll]

Dear sir


Very sorry the attachment did not come in.

The sum is (1/2) x = (8) x-2

It is Half to the power of x = 8 to the power of x minus 2.

Thanks
Regards
Rubydoll

[chrisu]

Anyone can help with this Sec.1 Maths;


Q. During an Art & Craft lesson, Ms Yuen asks everyone to cover her own tabletop with pieces of coloured paper. Each piece of coloured paper is rectangular in shape and measures 8cm by 6cm. The tabletop is also rectangular in shape and measures 50cm by 33cm. How many pieces of coloured paper would be needed to cover as much of the tabletop as possible with whole pieces of coloured paper without overlapping if
(i) all the pieces of the coloured paper are to be in the same orientations;
(ii) all the piececs of the coloured paper can be in any orientations.
Explain your solutions with detailed diagrams if possible and using problem solving heuristics, PSH.

Thank you.

[JadeDry]

@ Eddow & Pinkapple


I checked the question, it still is: 9(x to the power of ab) - ((xy) to the power of ab) - 9(y to the power of ab) - 81

I would appreciate more help if you do not mind.

Which is the simplest form?:

(4X- 8Y) or 4(X-2Y)

And why?

Thanks in advance.

[mum_sugoku]

JadeDry:

@ Eddow & Pinkapple


I checked the question, it still is: 9(x to the power of ab) - ((xy) to the power of ab) - 9(y to the power of ab) - 81

I would appreciate more help if you do not mind.

Which is the simplest form?:

(4X- 8Y) or 4(X-2Y)

And why?

Thanks in advance.

If question is .... \"+\" ((xy) to the power of ab).... instead of \"-\", then solution is (x^ab -9) (y^ab +9)..

[mum_sugoku]

rubydoll:

Dear sir


Very sorry the attachment did not come in.

The sum is (1/2) x = (8) x-2

It is Half to the power of x = 8 to the power of x minus 2.

Thanks
Regards
Rubydoll

(1/2)^x ==> (2^-1)^x, or 2^(-x)
8^(x-2) ==> (2^3)^(x-2), or 2^[3(x-2)]

therefore 2^(-x) = 2^[3(x-2)]
==> -x=3(x-2)
solving for x, you'll get x=3/2

[Eddow]

mum_sugoku:

JadeDry:

@ Eddow & Pinkapple


I checked the question, it still is: 9(x to the power of ab) - ((xy) to the power of ab) - 9(y to the power of ab) - 81

I would appreciate more help if you do not mind.

Which is the simplest form?:

(4X- 8Y) or 4(X-2Y)

And why?

Thanks in advance.

If question is .... \"+\" ((xy) to the power of ab).... instead of \"-\", then solution is (x^ab -9) (y^ab +9)..

I suspect printing error in the question. If it's ....+81, then answer should be (x^ab +9) (9 - y^ab)

For question like this...Which is the simplest form?:
(4X- 8Y) or 4(X-2Y) .
If the question is asking you to FACTORISE, then correct ans is 4(x-2y).

[Eddow]

[quote]

If question is .... \"+\" ((xy) to the power of ab).... instead of \"-\", then solution is (x^ab -9) (y^ab +9)..[/quote](x^ab -9) (y^ab +9) is not the ans as this is a diff of 2 sq, which will results in x^(2ab) -81, which is not the question.

[mum_sugoku]

Eddow:

[quote]

If question is .... \"+\" ((xy) to the power of ab).... instead of \"-\", then solution is (x^ab -9) (y^ab +9)..

(x^ab -9) (y^ab +9) is not the ans as this is a diff of 2 sq, which will results in x^(2ab) -81, which is not the question.[/quote]Haha x^ab times y^ab will not give you x^2ab mah..

(x^ab-9)(y^ab+9)= (x^ab)(y^ab) - (9)(y^ab) + (9)(x^ab) -(9)(9)

=(xy)^ab -9(y^ab) +9(x^ab) - 81

[mum_sugoku]

Eddow:

[quote]

If question is .... \"+\" ((xy) to the power of ab).... instead of \"-\", then solution is (x^ab -9) (y^ab +9)..

(x^ab -9) (y^ab +9) is not the ans as this is a diff of 2 sq, which will results in x^(2ab) -81, which is not the question.[/quote]Haha x^ab times y^ab will not give you x^2ab mah..

(x^ab-9)(y^ab+9)= (x^ab)(y^ab) - (9)(y^ab) + (9)(x^ab) -(9)(9)

=(xy)^ab -9(y^ab) +9(x^ab) - 81 !!!