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    Q&A - P4 Math

    Scheduled Pinned Locked Moved Primary 4
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    • K Offline
      KSP
      last edited by

      1. If I distribute 10 oranges to each of the children, I will be short of 30 oranges and if I distribute 8 oranges to each of them, I will be short of 6 oranges. How many oranges and children are there?


      2. A had 6 times as much money as B at first. After both received $300 each, A has thrice as much money as B. How much did A and B have at first?

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      • T Offline
        tianzhu
        last edited by

        KSP:
        1. If I distribute 10 oranges to each of the children, I will be short of 30 oranges and if I distribute 8 oranges to each of them, I will be short of 6 oranges. How many oranges and children are there?
        Hi

        First question touches on Gap and Difference.

        Gap ----- 30 - 6 ------ 24
        Difference ------ 10 - 8 ------- 2

        Number of children ------- 24/2 ------ 12

        Number of oranges -------- (12*10) - 30 ------ 90 or (12*8) - 6 ------90

        You can see more examples of such questions in previous posts.

        Best wishes

        1 Reply Last reply Reply Quote 0
        • T Offline
          tianzhu
          last edited by

          KSP:

          2. A had 6 times as much money as B at first. After both received $300 each, A has thrice as much money as B. How much did A and B have at first?
          Hi

          Due to time constraints, I'll give some pointers to draw the MD.

          Draw 6 boxes to show A’s money.
          Draw 1 box to show B’s money.

          A ------ (1unit)(1unit)(1unit)(1unit)(1unit)(1unit)
          B ------ (1unit)

          Add 300 to the first 6 boxes.
          Add 300 to the 1 box (B)

          Now,1 big box ------ 1 unit + 300

          A ------ (1unit + 300)(1unit + 300)( (1unit + 300)
          B ------ (1unit + 300)

          Compare A’s money

          3 units + 900 ------ 6 units +300
          3 units ----- 600
          1 unit ------ 200

          A+B ------ 7 units ------- 7*200 ------1400

          Best wishes

          For P5/6 ----- In addition to MD, students may also use the Units Method.

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          • T Offline
            ttyh
            last edited by

            2 boys can sell as many durains as 3 girls. If 6 boys and 7 girls sold 192 durians altogether, how many durians did each boy sell?

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            • T Offline
              tianzhu
              last edited by

              ttyh:
              2 boys can sell as many durains as 3 girls. If 6 boys and 7 girls sold 192 durians altogether, how many durians did each boy sell?

              Hi

              You may use “Number*Value”

              Use a common multiple of 6 (2 and 3)

              2 boys ----- 6 units
              1 boy ------ 3 units

              3 girls ------ 6 units
              1 girl ------- 2 units

              6 boys and 7 girls sold 192 durians altogether

              (6*3) + (7*2) ------ 192
              32 units ------ 192
              1 unit ------ 6

              1 boy ------ 3 units ------- 18

              Best wishes

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              • C Offline
                cmm
                last edited by

                Sue has more than 50 hairpins.

                If she puts them in packets of 7, she has 5 hairpins left.
                If she puts them in packets of 9, she has 6 hairpins left.
                How many hairpins does Sue have?

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                • A Offline
                  alan000
                  last edited by

                  http://i42.tinypic.com/69p8jk.gif\">

                  cmm:
                  Sue has more than 50 hairpins.

                  If she puts them in packets of 7, she has 5 hairpins left.
                  If she puts them in packets of 9, she has 6 hairpins left.
                  How many hairpins does Sue have?
                  Dear cmm,

                  Hope this helps.

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                  • C Offline
                    cmm
                    last edited by

                    Many thanks, alan000!!!

                    1 Reply Last reply Reply Quote 0
                    • B Offline
                      BigDevil
                      last edited by

                      tianzhu:


                      http://farm6.staticflickr.com/5092/5424577928_4b58b5019e_z.jpg\">
                      Hi tianzhu,

                      Like CNS, I'm quite confused.

                      44 cars, 0 bicycle ----> 44 * 4 = 176 wheels
                      43 cars, 1 bicycle ----> 43 * 4 + 1 * 2 = 174 wheels

                      So why do you say that \"for every increase in 1 bicycle, the difference in the number of wheels drops by 6\"? Isn't it 176 - 174 = 2 wheels??

                      :? :?

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                      • T Offline
                        tianzhu
                        last edited by

                        BigDevil:

                        Like CNS, I'm quite confused.

                        44 cars, 0 bicycle ----> 44 * 4 = 176 wheels
                        43 cars, 1 bicycle ----> 43 * 4 + 1 * 2 = 174 wheels

                        So why do you say that \"for every increase in 1 bicycle, the difference in the number of wheels drops by 6\"? Isn't it 176 - 174 = 2 wheels??
                        Hi

                        There are 44 cars and bicycles. There are 128 more car wheels than bicycles. How many cars and bicycles are there?

                        43 cars ------ (43*4) ----- 172
                        1 bicycle ----- (1*2) ------ 2

                        Difference in number of wheels ------ (172-2) -------170

                        176 – 170 ------6

                        Please compare with this question.

                        There are 44 cars and bicycles. There are 128 wheels altogether. How many cars and bicycles are there?

                        In this case the difference is 2.

                        Best wishes

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