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    Q&A - PSLE Math

    Scheduled Pinned Locked Moved Primary 6 & PSLE
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    • C Offline
      cimman
      last edited by

      Nebbermind:
      tianzhu:



      Q1) Mrs Lim bought some bowls and plates. If she buys another 5 bowls, there are 60% as many bowls as plates. If she buys another 9 plates, there will be thrice as many plates as bowls. How many bowls did she buy? (CHS P5 SA2 2009)

      The issue here lies in one’s interpretation of the additional word “another”
      There are two different answers, depending on the assumptions one makes.

      Best wishes

      I did the add-then-add-again...and got a fraction of plates and bowls!! :oops:

      I think there should be some sort of quality control check on exam questions to make sure that there is no room for ambguity. Maths questions are starting to look like legal documents where the emphasis is on language.

      1 Reply Last reply Reply Quote 0
      • T Offline
        tianzhu
        last edited by

        Nebbermind:

        I did the add-then-add-again...and got a fraction of plates and bowls!! :oops:
        Hi

        I’m using these two questions to illustrate that the assumptions made by small in the NH question is not applicable to the CHS question.

        I have some red & blue ribbons in a bottle. If I add in 20 red ribbons, 60% of my ribbons are blue. If I add in another 60 blue ribbons, 75% of my ribbons are blue. How many ribbons have I in the bottle?

        This question is from NH CA1 2011
        http://www.orlesson.org/orp/11Ma/2011-P6-Math-CA1-NanHua.pdf
        The given answer is 180.

        Mrs Lim bought some bowls and plates. If she buys another 5 bowls, there are 60% as many bowls as plates. If she buys another 9 plates, there will be thrice as many plates as bowls. How many bowls did she buy? (CHS P5 SA2 2009)

        This question is from CHS SA2 2009
        http://www.orlesson.org/orp/09Ma/2009-Math-SA2-CHS.pdf
        The given answer is 13.

        Best wishes

        1 Reply Last reply Reply Quote 0
        • T Offline
          tianzhu
          last edited by

          Hi


          To get an answer of 180 in the NH question and 13 in the CHS question, you’ve to interpret that the “if” in a statement signifies the event didn’t really happen.

          For questions on “double if”, students work on the assumption that those scenarios didn’t happen. The two conditions are also independent or exclusive.

          Consider this question.

          Susan has some vanilla and chocolate sweets in her bag. If she adds 20 vanilla sweets into the bag, the percentage of vanilla sweets in the bag becomes 40%. If she adds 30 chocolate sweets, there will be 70% of chocolate sweets in the bag. How many vanilla and chocolate sweets does she have?

          Best wishes

          1 Reply Last reply Reply Quote 0
          • NebbermindN Offline
            Nebbermind
            last edited by

            tianzhu:
            Hi


            To get an answer of 180 in the NH question and 13 in the CHS question, you’ve to interpret that the “if” in a statement signifies the event didn’t really happen.

            For questions on “double if”, students work on the assumption that those scenarios didn’t happen. The two conditions are also independent or exclusive.

            Consider this question.

            Susan has some vanilla and chocolate sweets in her bag. If she adds 20 vanilla sweets into the bag, the percentage of vanilla sweets in the bag becomes 40%. If she adds 30 chocolate sweets, there will be 70% of chocolate sweets in the bag. How many vanilla and chocolate sweets does she have?

            Best wishes
            OK. let me try to get it right.

            For double 'if', ONLY use the 'original qty' as base for both computation. YA?

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            • W Offline
              Winx5015
              last edited by

              Hi,


              Got problem with this question. Ps help!

              Mother baked a total of 176 chocolate and vanilla cupcakes. After giving away 4/5 of the chocolate cupcakes and 2/3 of the vanilla cupcakes, she was left with 52 cupcakes altogether. How many chocolate cupcakes did she bake at first?

              Thanks!

              1 Reply Last reply Reply Quote 0
              • T Offline
                tianzhu
                last edited by

                Winx5015:
                Hi,


                Got problem with this question. Ps help!

                Mother baked a total of 176 chocolate and vanilla cupcakes. After giving away 4/5 of the chocolate cupcakes and 2/3 of the vanilla cupcakes, she was left with 52 cupcakes altogether. How many chocolate cupcakes did she bake at first?

                Thanks!
                Hi

                This question touches on simultaneous concept.

                You may use Units and Parts, letters of the alphabet or solve it the pictorial way.

                Please refer to some of the earlier posts for examples of such solution.

                I’ll use the alphabet way.

                Chocolate
                Gave ----- CCCC
                Left ----- C

                Vanilla
                Gave ----- VV
                Left ----- V

                She was left with 52 cupcakes altogether.
                C + V ----- 52

                CCCC + VV ----- 124 (176-52)

                CC + (CC+VV) ----- 124
                CC + 104 ----- 124
                CC ----- 20

                C ----- 10

                Chocolate ----- CCCCC ------- 50 at first.

                Best wishes

                1 Reply Last reply Reply Quote 0
                • W Offline
                  Winx5015
                  last edited by

                  Hi tianzhu,


                  :thankyou:

                  1 Reply Last reply Reply Quote 0
                  • NebbermindN Offline
                    Nebbermind
                    last edited by

                    tianzhu:
                    Winx5015:

                    Hi,


                    Got problem with this question. Ps help!

                    Mother baked a total of 176 chocolate and vanilla cupcakes. After giving away 4/5 of the chocolate cupcakes and 2/3 of the vanilla cupcakes, she was left with 52 cupcakes altogether. How many chocolate cupcakes did she bake at first?

                    Thanks!

                    Hi

                    This question touches on simultaneous concept.

                    You may use Units and Parts, letters of the alphabet or solve it the pictorial way.

                    Please refer to some of the earlier posts for examples of such solution.

                    I’ll use the alphabet way.

                    Chocolate
                    Gave ----- CCCC
                    Left ----- C

                    Vanilla
                    Gave ----- VV
                    Left ----- V

                    She was left with 52 cupcakes altogether.
                    C + V ----- 52

                    CCCC + VV ----- 124 (176-52)

                    CC + (CC+VV) ----- 124
                    CC + 104 ----- 124
                    CC ----- 20

                    C ----- 10

                    Chocolate ----- CCCCC ------- 50 at first.

                    Best wishes

                    Think this is one of those qn which u have to 'see' the pattern.

                    1) CCCCC + VVV = 176
                    2) C + V = 52
                    From here, (2) x 3, ie, CCC + VVV = 156

                    Therefore CC = 176 - 156 = 20, and CCCCC = (20/2) * 5 = 50

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                    • H Offline
                      homeworkmummy
                      last edited by

                      Hi pls help with the following question and thanks in advance.


                      1. Adrian, Brian and Charlie had some money. After spending a total of $2900, they each had the same amount of money left. Adrian spent 20% of his money, Brian spent 25% of his money and Charlie spent $464. What percentage of his money did Charlie spend?

                      2. Thomas has a total of 408 blue and yellow marbles. He lost 3/5 of his blue marbles and bought another 32 yellow marbles. As a result, the number of yellow marbles he had was 1/4 of the number of blue marbles. How many more blue marbles than yellow ones had he at first?

                      1 Reply Last reply Reply Quote 0
                      • MathIzzzFunM Offline
                        MathIzzzFun
                        last edited by

                        homeworkmummy:
                        Hi pls help with the following question and thanks in advance.


                        1. Adrian, Brian and Charlie had some money. After spending a total of $2900, they each had the same amount of money left. Adrian spent 20% of his money, Brian spent 25% of his money and Charlie spent $464. What percentage of his money did Charlie spend?

                        2. Thomas has a total of 408 blue and yellow marbles. He lost 3/5 of his blue marbles and bought another 32 yellow marbles. As a result, the number of yellow marbles he had was 1/4 of the number of blue marbles. How many more blue marbles than yellow ones had he at first?
                        Hi
                        Q1.
                        In the end,
                        Adrian --> 12u
                        Brian --> 12u
                        Charlie --> 12u

                        At first,
                        Adrian --> 12 u + 3u = 15u
                        Brian --> 12u + 4u = 16u
                        Charlie --> 12u + $ 464

                        3u + 4u + $ 464 --> $ 2900
                        7u --> $ 2436
                        1u --> $ 348

                        At first, Charlie's money --> 12 x $ 348 + $ 464 = $ 4640
                        $ 464/$ 4640 x 100% = 10%
                        Charlie spent 10% of her money.


                        Q2.

                        In the end,
                        Yellow marbles --> 1u
                        Blue marbles --> 4u

                        At first,
                        Yellow marbles --> 1u - 32
                        Blue marbles --> 4u/2 x 5 = 10u
                        10u + 1u - 32 --> 408
                        11u --> 440
                        1u --> 40

                        10u - (1u-32) = 9u + 32 = 9 x 40 + 32 =392
                        There were 392 more blue marbles than yellow marbles at first.

                        cheers.

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