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    Q&A - P5 Math

    Scheduled Pinned Locked Moved Primary 5
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    • W Offline
      wintay
      last edited by

      Gemini11:
      wintay:

      Can anyone help to solve the problem sum below. Thanks


      6 hats and 5 belts cost $150. 5 hats and 6 belts cost $147. What is the cost of one belt?

      Hi wintay here's another method, using elimination presented in a way which i think kids at P5 should be able to understand :evil:

      1) Given, 6 hats and 5 belts= $150 ( mutiple all by 5)
      we get... 30 belts and 25 belts= $750

      2) Given also, 5 hats and 6 belts= $147 ( mutiple all by 6)
      we get... 30 hats and 36 belts = $882

      3) since now we know...

      30 hats and 36 belts = $882
      30 belts and 25 belts= $750

      36- 25 belts is obviously = $882-$720
      so 11 belts = $132
      1 belt=$12

      --------------------------------------------------

      Hope it helps

      Gemini11 :evil:

      Hi Gemini,
      Thanks!!!

      1 Reply Last reply Reply Quote 0
      • T Offline
        tianzhu
        last edited by

        Hi


        I'll take Q2 first because I miss my ah ma.

        Best wishes.

        http://farm8.staticflickr.com/7210/6837707220_51b42ebf08_z.jpg\">

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        • T Offline
          tianzhu
          last edited by

          chokos:

          Qn3)
          Mark's current age is 1/4 of Ronald's. In 24 years' time, Ronald age will be 14 years less than twice Mark's age. What is Ronald age now?
          Model Answer: 20
          Hi

          Now
          Mark’s age ------ 1 unit
          Ronald’s age ------ 4 units

          In 24 years’ time
          Mark’s age ------ 1 unit + 24
          Ronald’s age ------ 4 units + 24

          Ronald age will be 14 years less than twice Mark's age.

          You may use MD or work using units depending on your preference.

          1 unit + 24 + 1 unit + 24 ------ 4 units + 24 + 14
          1 unit ----- 5

          4*5 ------ 20

          Ronald is 20 years old now.

          Best wishes

          1 Reply Last reply Reply Quote 0
          • T Offline
            tianzhu
            last edited by

            chokos:

            Qn 1)
            There are some crystal and glass marbles in a pouch. If 3 crystal marbles are removed from the pouch, the number of crystal marbles left will be 1/6 of the glass marbles left. If 5 glass marbles are removed from the pouch, the number of crystal marbles left will be 1/4 of the glass marbles left. How many marbles are there in the pouch at first?
            Model Answer: 62.5
            Hi

            Based on the question as worded, the answer is 62.5.

            At first
            Crystal marbles ----- 1 unit + 3
            Glass marbles ------ 6 units

            In the end
            Crystal marbles ----- 1 part
            Glass marbles ------ 4 parts

            Again, equalise the parts or cross multiply.

            (1 unit + 3)*4 ------- 6units - 5
            4 units + 12 ------- 6 units – 5

            2 units ------ 17
            1 unit ------ 8.5

            Crystal marbles ------- 11.5
            Glass marbles ------- 51
            Total number of marbles -------- 62.5

            Best wishes

            1 Reply Last reply Reply Quote 0
            • T Offline
              tianzhu
              last edited by

              zico:
              Is there a algerbra way to solve this?

              Hi

              Yes, there is.

              Best wishes

              1 Reply Last reply Reply Quote 0
              • 2 Offline
                2snoopy
                last edited by

                Is primary 5 students start to learn algebraic equation in school? If yes, then can use my method.

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                • C Offline
                  chokos
                  last edited by

                  Hi all,

                  Thanks for helping.
                  I need help to solve the following questions:

                  Q 1) Some pupils from 5K, 5L and 5M took part in a Social Studies quiz. 34 participants were from 5L and 5M. 21 participants were not from 5L and 19 participants were not from 5M. How many pupils from these 3 classes took part in the quiz? Model Answer: 37pupils

                  Q 2) Mrs Lee spent ½ of her money on some almond cookies and 2/5 of the remaining money on 6 slices of butter cake. Each slice of butter cake costs thrice as much as one almond cookie. How many almond cookies did she buy? Model Answer: 18 almond cookies.

                  Q3) Three sisters Lisa, Ming and Nora shared the cost of a present for their father. Lisa paid ¼ of the total share of Ming and Nora. Ming paid 1/9 of the total share of Lisa and Nora. Nora paid $60 more than Ming. How much did the present cost? Model Answer: $100

                  Q4) Jason and Kevin were given some money each. If Jason and Kevin spent $100 and $50 each day respectively. Jason would have $1300 when Kevin had spent all his money. If Jason and Kevin spent $50 and $100 each day respectively, Jason would have $3700 when Kevin had spent all his money. How much money was given to Jason at the beginning.
                  Model Answer: $4500

                  1 Reply Last reply Reply Quote 0
                  • S Offline
                    small
                    last edited by

                    wintay:
                    Can anyone help to solve the problem sum below. Thanks


                    6 hats and 5 belts cost $150. 5 hats and 6 belts cost $147. What is the cost of one belt?
                    Another way to solve this question.

                    Given that:
                    6 hats and 5 belts cost $150
                    5 hats and 6 belts cost $147

                    add togother become:
                    11 hats and 11 belts cost $297

                    divide by 11
                    1 hat and 1 belt cost $27

                    x 5
                    5 hats and 5 belts cost $135

                    Given that:
                    5 hats and 6 belts cost $147

                    1 belt ---- $147 - $135 = $12

                    1 Reply Last reply Reply Quote 0
                    • K Offline
                      KSgal
                      last edited by

                      chokos:
                      Hi all,

                      Thanks for helping.
                      I need help to solve the following questions:

                      Q 1) Some pupils from 5K, 5L and 5M took part in a Social Studies quiz. 34 participants were from 5L and 5M. 21 participants were not from 5L and 19 participants were not from 5M. How many pupils from these 3 classes took part in the quiz? Model Answer: 37pupils
                      5L + 5M: 34

                      21 not from 5L means that the 21 are from 5K + 5M

                      19 not from 5M means that the 19 are from 5K + 5L

                      Notice that if you add all the numbers up, you will get 2 5K, 2 5L and 2 5M.

                      So:

                      2 5K, 2 5L, 2 5M--34+21+19=74
                      No. of pupils from all 3 classes (1 5K, 1 5L, 1 5M)--74/2=37

                      Ans: 37 pupils

                      Hope this helps ^_^

                      1 Reply Last reply Reply Quote 0
                      • K Offline
                        KSgal
                        last edited by

                        chokos:

                        Q 2) Mrs Lee spent ½ of her money on some almond cookies and 2/5 of the remaining money on 6 slices of butter cake. Each slice of butter cake costs thrice as much as one almond cookie. How many almond cookies did she buy? Model Answer: 18 almond cookies.
                        Actually, I've got 45 for this question. Not too sure if I am correct. Here's my working:

                        Spent on butter cake--2/5 X 1/2(remainder) = 1/5 of total
                        1/5 of total worth of almond cookies--6 X 3 = 18

                        However, 1/2 was spent on almond cookies, not 1/5.

                        1/2=5/10 of total
                        1/5=2/10 of total

                        2/10--18 cookies
                        1/10--18/2=9 cookies
                        5/10--9 X 5= 45 cookies

                        My answer: 45 cookies

                        1 Reply Last reply Reply Quote 0

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