Tutor MathsGuru: Ask me for your burning Maths questions!

[Kafer]

Hi i have one qn


John speed is ia x m/s.
Mary speed is y m/s
If john starts 2 sec later, he will take 8 secs to catch up with mary.
If john starts to run only when mary is 8m ahea 5 sec to catch up with her.
Form two eqn in x an y.

Can help?

[violin_lover]

8x=10y and 8+5y=5x

[Kafer]

violin_lover:

8x=10y and 8+5y=5x

Thanks! Can exlain how you workput the eqn?

[violin_lover]

Kafer:

violin_lover:

8x=10y and 8+5y=5x

Thanks! Can exlain how you workput the eqn?

Sure. But just to follow the \"tradition\", could you please tell us which level is the question pitch at and if possible, where did you encounter it?

[Kafer]

Hi, violin_lover, it is a sec level maths qn.

[violin_lover]

Kafer:

Hi i have one qn

John speed is ia x m/s.
Mary speed is y m/s
If john starts 2 sec later, he will take 8 secs to catch up with mary.
If john starts to run only when mary is 8m ahea 5 sec to catch up with her.
Form two eqn in x an y.
Can help?

In 10s, Mary travels 10y meter and in 8s, john travels 8x meter. Hence, 10y=8x.
Next, in the 5s, John travels 5x meter and the total distance travel is 8+5y. Thus, 5x=8+5y.

[Kafer]

violin_lover:

Kafer:

Hi i have one qn

John speed is ia x m/s.
Mary speed is y m/s
If john starts 2 sec later, he will take 8 secs to catch up with mary.
If john starts to run only when mary is 8m ahea 5 sec to catch up with her.
Form two eqn in x an y.
Can help?

In 10s, Mary travels 10y meter and in 8s, john travels 8x meter. Hence, 10y=8x.
Next, in the 5s, John travels 5x meter and the total distance travel is 8+5y. Thus, 5x=8+5y.

Thanks very much!

[ongmt]

A contractor needed to cover an entire hall with tiles, On the first day,he laid 319 tiles. He completed tiling the rest of the hall in 7 days using equal number of tiles each day, At the end of 4th day, he was able to tile 8/15 of the hall. How man tiles did the contractor us to cover the entire hall? :slapshead:

[MathIzzzFun]

ongmt:

A contractor needed to cover an entire hall with tiles, On the first day,he laid 319 tiles. He completed tiling the rest of the hall in 7 days using equal number of tiles each day, At the end of 4th day, he was able to tile 8/15 of the hall. How man tiles did the contractor us to cover the entire hall? :slapshead:

Hi

Total number of days to tile the hall --> 8 days
Day 1 --> 319 tile
8/15 of hall completed on day 4, so 7/15 (=28/60) of hall completed on remaining 4 days.
So, 1 day --> 7/60 of hall
Day 2 to Day 4 --> 3 days --> 21/60 of hall
319 tiles --> (60-21-28)/60 of hall
11/60 of hall --> 319 tiles
Total number of tiles --> 319/11 x 60 = 1740

cheers.

[Herbie]

Mary and ben took 49 hours to complete their sci project.

They worked separately on their own project.
If mary had worked 5 hours less an ben had worked 6 hours
More. Mary would hv put in 2 hours more than ben.
How many hous did mary put in for the sci project?