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    Q&A - PSLE Math

    Scheduled Pinned Locked Moved Primary 6 & PSLE
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    • T Offline
      tianzhu
      last edited by

      megamage1000:
      Hi, i have a hard time resolving this question, Hope you will help me!


      In a photocopier shop, Copier A was turned on first, and it printed 240 pages.Then Copier B was turned on , and Copier A and Copier B continue printing together.For every 4 pages Copier A printed, Copier B printed 7 pages . Copier B printed 30 pages fewer than 2/7 of the total number of pages printed.

      Find the total number of pages printed.
      Hi

      A neat way is to use MD. Alternatively, you may also use “Units and Parts”.

      Use equivalent ratios to avoid working with decimals.

      For every 4 pages Copier A printed, Copier B printed 7 pages .

      Copier A ----- 4 units ------ 8 units
      Copier B ----- 7 units ------ 14 units

      Total number of pages ------- 7 parts.

      14 units + 30 ------- 2 parts

      7 units + 15 ------ 1 part

      49 units + 105 ------- 7 parts

      49 units + 105 ------ 240 + 8 units + 14 units

      27 units ------- 135
      1 unit ------- 5

      Total number of pages printed -------- (49*5) + 105 -------- 350.

      Best wishes

      1 Reply Last reply Reply Quote 0
      • R Offline
        rose michelle
        last edited by

        Chris had some M&M’s chocolates. He gave 3/10 of them to Ben and 2/5 of the remainder to Ken. He had 105 left. How many M&M’s chocolates had chris at first?

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        • R Offline
          rose michelle
          last edited by

          Chris had some M&M’s chocolates. He gave 3/10 of them to Ben and 2/5 of the remainder to Ken. He had 105 left. How many M&M’s chocolates had chris at first?

          1 Reply Last reply Reply Quote 0
          • P Offline
            php
            last edited by

            rose michelle:
            Chris had some M&M's chocolates. He gave 3/10 of them to Ben and 2/5 of the remainder to Ken. He had 105 left. How many M&M's chocolates had chris at first?

            Ben --> 3/10, remaining --> 7/10
            Ken --> 2/5 x 7/10 = 7/25, remaining --> 7/10 - 7/25 = 21/50

            21 units --> 105
            1 unit --> 105/21 = 5
            50 units --> 50 x 5 = 250

            Ans : 250

            1 Reply Last reply Reply Quote 0
            • F Offline
              fightingmom
              last edited by

              rose michelle:
              Chris had some M&M's chocolates. He gave 3/10 of them to Ben and 2/5 of the remainder to Ken. He had 105 left. How many M&M's chocolates had chris at first?

              Hi ,

              You can use the Branching method:

              Total
              /. \\
              Ben. Remainder
              3/10. 7/10



              Remainder
              /. \\
              Ken. Left
              2/5. 3/5


              3/5 = 105
              3 units = 105
              1 unit = 35
              5 units = 175 = 7/10

              7 units = 175
              1 unit = 25
              10 units = 250

              Ans: 250

              (sorry if you can't see well cos i can't align the numbers properly here )

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              • S Offline
                speedmaths.012624com
                last edited by

                rose michelle:
                Chris had some M&M's chocolates. He gave 3/10 of them to Ben and 2/5 of the remainder to Ken. He had 105 left. How many M&M's chocolates had chris at first?

                Hi,

                Some P6 pupils may find fractions slightly more difficult to handle than whole numbers.

                One method to solve this, without having too many fractions in the working, is “The Denominators are Your Friends Method”

                The denominators here are 10 and 5.
                10 x 5 = 50

                Let Chris have 50u of chocolates at first.
                (50u stands for 50 units, or 50 boxes for those used to the Model Method.)

                http://i50.tinypic.com/359fksl.jpg\">

                21u → 105 chocolates (left)
                1u → 5 chocolates
                50u → 250 chocolates (at first)

                Hope this helps.

                Cheers


                speedmaths.com


                PS.
                Parents who wish to find out more about this method may wish to look at the “PSLE Maths Workshop for Parents” thread in the Happenings forum.

                .

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                • T Offline
                  tianzhu
                  last edited by

                  jarenchuatw:

                  Q2 XiaoMing and Mary each had a certain number of comics. Xiao Ming gave away 40% of his comics and another 15% of his remaining comics to Mary. Then Mary gave 2/3 of her comics to Sally. Xaioming found that he had thrice as many comics left as Mary. If Mary had 210 comics at first,
                  (a) how many comics did Xiao Ming have at first? (Answer: 500)
                  (b) how many comics did Sally receive from Mary? (Answer : 170)
                  Hi

                  Hope this helps.

                  Best wishes

                  http://farm9.staticflickr.com/8005/7207450038_e911da4ea0_z.jpg\">

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                  • T Offline
                    tianzhu
                    last edited by

                    Michaelia0816:
                    Yay! My exam marks was back, 30 for paper 1 and almost got a* by a few marks! Scoring super well in paper 2!

                    Hi girl

                    Well done, keep it going.

                    Best wishes

                    1 Reply Last reply Reply Quote 0
                    • M Offline
                      Michaelia0816
                      last edited by

                      Thank! But I need help with a question:

                      John has 3 boxes of marbles. There are 2 more marbles in Box A than Box B. There are 18 marbles together in Box A and Box C. The total number of marbles in Box B and Box C is 9 more than the number of marbles in Box A. How many marbles does John have in all?

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                      • T Offline
                        tianzhu
                        last edited by

                        Michaelia0816:
                        Thank! But I need help with a question:

                        John has 3 boxes of marbles. There are 2 more marbles in Box A than Box B. There are 18 marbles together in Box A and Box C. The total number of marbles in Box B and Box C is 9 more than the number of marbles in Box A. How many marbles does John have in all?
                        Hi

                        You may use MD or use letters of the alphabet.

                        A ------- B + 2

                        A + C ------- 18

                        B + C ------- A + 9

                        B + C ------- (B + 2) + 9

                        C ------ 11
                        A ------- 7
                        B ------- 5

                        Total -------- 23

                        Best wishes

                        1 Reply Last reply Reply Quote 0

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