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    Q&A - PSLE Math

    Scheduled Pinned Locked Moved Primary 6 & PSLE
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    • M Offline
      Michaelia0816
      last edited by

      Thx, can Can I know the answer?I doing correction, and can't search it as mine do not have adore reader

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      • M Offline
        Michaelia0816
        last edited by

        Hey, I not sure,pls help pls

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        • S Offline
          Spongy
          last edited by

          Hi I need help thank you very much!


          1. Ann, Ben and Cindy had a total of 640 sweets. The ratio of Ben’s sweets to Cindy’s sweet was 5:4 at first. After Ann and Ben each gave 1/2 of their sweets away, the three children had 420 sweets left. How many sweets did Ann have at first?

          2. Jin walked from home to school. For the first 2 minutes, he was walking at an average speed of 40m/min. When he realised that he was going to be late by 3 minutes, he quickly inceased his speed by 10m/min. As a result, he was early by 1 minute. Find the distance between his home to his school.

          3. Tom, Faith and Gary took part in a 100m race. When Tom crossed the finishing line, he was ahead of Faith by 20m and ahead of Gary by 40m. Faith and Gary continued to race to the finishing line without changing their speed. How far was Gary from the finishing line when Faith completed the race?

          4. Peter had six more 50-cent coins than 20-cent coins. After he used eight 50-cent coins, the value of the 50-cent coins he had was $7.40 more than the value of 20-cent coins he had. How many coins did he have at first?

          5. Some plates and cups were packed into blue and red boxes. There were 12 more blue boxes than red boxes. Each blue box contained 120 plates and each red box contained 150 cups. Given that there were 120 fewer plates than cups in total, how many plates were there?

          6. 3/5 of Joel’s savings is equal to 2/3 of Mathew’s savings. The difference in their savings is equal to 1/5 of Ben’s savings. Joel saves $35 more than Ben.
          (a) Find the ratio of Joel’s savings to Mathew’s savings to Ben’s savings.
          (b) Find the total amount of saving of the 3 children.

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          • MathIzzzFunM Offline
            MathIzzzFun
            last edited by

            Spongy:
            Hi I need help thank you very much!



            6. 3/5 of Joel's savings is equal to 2/3 of Mathew's savings. The difference in their savings is equal to 1/5 of Ben's savings. Joel saves $35 more than Ben.
            (a) Find the ratio of Joel's savings to Mathew's savings to Ben's savings.
            (b) Find the total amount of saving of the 3 children.
            Hi

            wow.. that's quite a bunch..

            Q6..

            3/5 of Joel's savings = 2/3 of Mathew's savings
            6/10 of Joel's savings = 6/9 of Mathew's savings
            Joel's savings --> 10 units .......}
            Mathew's savings --> 9 units ...} difference = 1 unit
            Ben's savings --> 5 units
            a) Ratio of Joel's savings : Mathew's savings : Ben's savings
            = 10 : 9 : 5

            b) Joel saves $35 more than Ben
            5 units --> $35, 1 unit --> $7
            Total savings --> (10+9+5) x $7 = $168

            cheers.

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            • MathIzzzFunM Offline
              MathIzzzFun
              last edited by

              Spongy:
              Hi I need help thank you very much!


              5. Some plates and cups were packed into blue and red boxes. There were 12 more blue boxes than red boxes. Each blue box contained 120 plates and each red box contained 150 cups. Given that there were 120 fewer plates than cups in total, how many plates were there?
              Q5.
              Add 12 red boxes so that there are equal number of blue and red boxes.
              12 red boxes --> 150 x 12 = 1800 cups
              so, there are now 1800 + 120 = 1920 more cups than plates.
              for every red box and blue box,
              150 - 120 = 30 --> there are 30 more cups than plates
              1920/30 = 64 --> there are 64 boxes each
              Number of red boxes = 64 - 12 = 52
              Number of plates = 64 x 120 = 7680

              cheers.

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              • MathIzzzFunM Offline
                MathIzzzFun
                last edited by

                Spongy:
                Hi I need help thank you very much!


                4. Peter had six more 50-cent coins than 20-cent coins. After he used eight 50-cent coins, the value of the 50-cent coins he had was $7.40 more than the value of 20-cent coins he had. How many coins did he have at first?
                Q4.
                After using 8 50-cent coins, there are now 2 more 20-cents coins.
                Add 2 more 50-cent coins so that there are equal number of 50-cent & 20-cent coins.
                2 x $0.50 + $7.40 = $8.40, value of 50-cents coins is $8.40 more than 20-cent coins

                $8.40/$0.30 = 28
                Number of 20-cent coins = 28
                Number of 50-cent coins at first = 28 - 2 + 8 = 34
                Total number = 62 --> Peter had 62 coins at first.

                cheers.

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                • MathIzzzFunM Offline
                  MathIzzzFun
                  last edited by

                  Spongy:
                  Hi I need help thank you very much!




                  3. Tom, Faith and Gary took part in a 100m race. When Tom crossed the finishing line, he was ahead of Faith by 20m and ahead of Gary by 40m. Faith and Gary continued to race to the finishing line without changing their speed. How far was Gary from the finishing line when Faith completed the race?
                  Q3.
                  Distance run by Tom : Faith : Gary = 100 : 80 : 60 = 5 : 4 : 3

                  When Faith completes the race,
                  Faith : Gary = 4 : 3 = 100 : 75,
                  Gary has only completed 75m
                  100m - 75m = 25m, Gary was 25 m from the finishing line.

                  cheers.

                  1 Reply Last reply Reply Quote 0
                  • MathIzzzFunM Offline
                    MathIzzzFun
                    last edited by

                    Spongy:
                    Hi I need help thank you very much!



                    2. Jin walked from home to school. For the first 2 minutes, he was walking at an average speed of 40m/min. When he realised that he was going to be late by 3 minutes, he quickly inceased his speed by 10m/min. As a result, he was early by 1 minute. Find the distance between his home to his school.
                    Q2.
                    increased speed = 40m/min + 10m/min = 50m/min
                    original speed: increased speed = 40 : 50 = 4:5

                    ratio of time taken to reach school for the 2nd part of the journey at original speed : increased speed = 5units : 4units

                    Time taken to reach the school at increased speed is (3+1)= 4 min faster than at original speed
                    1 unit = 4 min, 5 units = 20 min
                    Distance to school = (20+2)x40 = 880 m.

                    cheers.

                    1 Reply Last reply Reply Quote 0
                    • MathIzzzFunM Offline
                      MathIzzzFun
                      last edited by

                      Spongy:
                      Hi I need help thank you very much!


                      1. Ann, Ben and Cindy had a total of 640 sweets. The ratio of Ben's sweets to Cindy's sweet was 5:4 at first. After Ann and Ben each gave 1/2 of their sweets away, the three children had 420 sweets left. How many sweets did Ann have at first?
                      Q1.
                      Total number of sweets given away by Ann & Ben = 640 - 420 = 220
                      Total number of sweets Ann & Ben had at first = 220 x 2 = 440
                      Number of sweets Cindy had = 640 - 440 = 200
                      Number of sweets Ben had at first = 5 * 200/4 = 250
                      Number of sweets Ann had at first = 440 - 250 = 190

                      cheers.

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                      • F Offline
                        Flipper123
                        last edited by

                        Thanks Cinman for helping with the rombus question. I think this is too difficult for a p6 student. Sigh…

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