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    Q&A - PSLE Math

    Scheduled Pinned Locked Moved Primary 6 & PSLE
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    • T Offline
      tianzhu
      last edited by

      pixiedust:
      I think similar questions have been discussed before. Please point me in the right direction. Thank you !!!


      Mrs. Lim had some red and blue balloons in a bag. The number of red balloons was twice the number of blue balloons. She started removing balloons from the bag, each time taking out 4 red balloons and 6 blue balloons. After a while, only 120 red balloons were left in the bag. What was the total number of red and blue balloons in the bag at first ?
      Hi

      A neat way is to use MD, you may also use units.

      Draw two boxes to show the number of red balloons and one box to show the number of blue balloons.

      She started removing balloons from the bag, each time taking out 4 red balloons and 6 blue balloons.

      Number of balloons removed is in the ratio of 2 red:3 blue (4:6 ----- 2:3)

      Cut the blue box into 3 smaller units, Likewise, cut two units in one of the red box with the remainder showing 120.

      Now do a comparison.

      Red ----- 2 units + 120

      Blue ------- 3 units

      Remember, the number of red balloons was twice the number of blue balloons.

      6 units ------ 2 units + 120

      4 units ------ 120

      1 unit ------- 30

      Number of balloons@ first ------- 9 units ------ 270 (or 5 units + 120 ----- 270)

      Best wishes

      1 Reply Last reply Reply Quote 0
      • J Offline
        jarenchuatw
        last edited by

        Thanks Master MathizzzFun.


        Got one more question that is making my head crack…

        Motorcyclist A and B started a 360km race. They rode their bikes at the same speed for the first 120km. For the rest of the 240km, A rode at a faster speed. He arrive at the finishing point 1omins before B who was 40 km behind him. B did not chang his speed for the whole race. B completed the rae at 3.10pm

        a) At what time did they start the race?
        b) What was A’s average speed for the last 240 km in m/min?

        1 Reply Last reply Reply Quote 0
        • MathIzzzFunM Offline
          MathIzzzFun
          last edited by

          jarenchuatw:
          Thanks Master MathizzzFun.


          Got one more question that is making my head crack....

          Motorcyclist A and B started a 360km race. They rode their bikes at the same speed for the first 120km. For the rest of the 240km, A rode at a faster speed. He arrive at the finishing point 1omins before B who was 40 km behind him. B did not chang his speed for the whole race. B completed the rae at 3.10pm

          a) At what time did they start the race?
          b) What was A's average speed for the last 240 km in m/min?
          hi

          ..me not Master la... just helping around here..

          A reached the finishing point 10 min before B and B is 40 km behind
          --> B will take 10 min to cover 40 km, ie B's speed = 40 km/10 min = 240 km/h
          Total time taken for the 360 km = 360/240 h = 1.5 h = 1h 30 min
          1h 30 min before 3.10pm --> 1.40 pm
          They started the race at 1.40pm

          For the last 240 km, when A covered 240 km, B covered only 200 km
          So, A's speed = 240/200 x 240 km/h = 288 km/h

          cheers.

          1 Reply Last reply Reply Quote 0
          • J Offline
            jarenchuatw
            last edited by

            Thanks MathIzzzFun for the prompt reply.


            However, I could not quite understand part (b)…is there another way to explain it?

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            • MathIzzzFunM Offline
              MathIzzzFun
              last edited by

              jarenchuatw:
              Thanks MathIzzzFun for the prompt reply.


              However, I could not quite understand part (b)...is there another way to explain it?
              Hi

              for the last 240 km, time taken by B = 240/240 = 1h
              Time taken by A = 1h - 10min = 50 min
              A's speed = 240 km/50 min = 288 km/h

              cheers.

              1 Reply Last reply Reply Quote 0
              • J Offline
                jarenchuatw
                last edited by

                MathsIzzzFun…wow, that’s so much clearer…million tks again!

                1 Reply Last reply Reply Quote 0
                • E Offline
                  Essential
                  last edited by

                  Hi please help my DS for question 14 . John shifted the decimal point of a number twice to the left to obtain a new number . The difference between the new number and the original number was 136.62. A) how many times of the new number is the original number ? B) what is the sum of the 2 numbers ?

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                  • MathIzzzFunM Offline
                    MathIzzzFun
                    last edited by

                    Essential:
                    Hi please help my DS for question 14 . John shifted the decimal point of a number twice to the left to obtain a new number . The difference between the new number and the original number was 136.62. A) how many times of the new number is the original number ? B) what is the sum of the 2 numbers ?

                    Hi

                    decimal point shifted twice to the left = dividing by 100
                    so, new number is 1/100 of original number.
                    Difference = 99/100 of original number
                    original number = 136.62/99 x 100 = 138
                    .. with this, part b should be a breeze 😄

                    cheers.

                    1 Reply Last reply Reply Quote 0
                    • T Offline
                      tianzhu
                      last edited by

                      Essential:
                      Hi please help my DS for question 14 . John shifted the decimal point of a number twice to the left to obtain a new number . The difference between the new number and the original number was 136.62. A) how many times of the new number is the original number ? B) what is the sum of the 2 numbers ?

                      Hi

                      Original number ----- 100 units

                      New number ------ 1 unit

                      100 – 1 ----- 99

                      99 units ------- 136.62

                      1 unit ----- 1.38

                      Original number ----- 100 units ------- 138

                      New number ------ 1 unit ------ 1.38

                      The original number is 100 times the new number.

                      Sum of 2 numbers ------ 101 units ------- 139.38 (138 + 1.38)

                      Best wishes

                      1 Reply Last reply Reply Quote 0
                      • W Offline
                        Winx5015
                        last edited by

                        Hi, need help for the following questions.


                        (1) If Ahmad and Ben work together, they can complete a job in 8 days. If Ahmad were to work alone for 2 days, he can finish 3/20 of the job in 2 days. How many days will Ben take to complete the job if he were to work alone?

                        (2) Steve and Huiling took part in a walkathon which started at 6.30am. Steve's average speed was 15 m/min faster than Huiling. Both of them did not change their speed throughout the walkathon. When Steve reached the finishing line after 40 minutes, Huiling had only walked 8/9 of the distance.
                        (a) What time was it when Huiling completed the walkathon?
                        (b) Find Steve's average speed for the walkathon in m/min.

                        (3) At a concert, tickets were sold at $12, $30 and $50. The sales of $12 tickets made up 25% of the total amount of money collected. The sales of $30 tickets made up 60% of the total amount. given that 5 more $12 tickets were sold than the $30 tickets, how many $50 tickets were sold?

                        (4) At a funfair, the children can choose to ride on the Merry-Go-Round of the Train or both with their coupons. 7/10 of the children chose the Merry-Go-round, 45% chose to ride on the Train, and 10% of the children did not take any of the two rides. A total of 75 children went for both rides.
                        (a) How many children took ONE ride at the Merry-Go-Round only?
                        (b) How many children did not take any rides?

                        Thanks:)

                        1 Reply Last reply Reply Quote 0

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