Q&A - PSLE Math

[whitety]

MathIzzzFun:

peggy:

Please help :

2.an equal number of men and women were at a party. The ratio of the number of woman who wore watches to the number of men who wore watches was 3:11. The ratio of the number of women to the number of men who did not wear watches was 5:3.

A. Find the ratio of the number of women who wore watches to the number of women who did not wear watches.

Many thanks.

Q2.
a)
wearing watches, women : men = 3 : 11 (difference of
not wearing watches, women : men = 5:3 (difference of 2)
--> difference must be the same since equal number of men and women

wearing watches, women : men = 3u : 11u
not wearing watches, women : men = 20u : 12u
women wearing watches : women not wearing watches = 3:20



Hi MathIzzzFun,

wearing watches, women : men = 3u : 11u need to x4? = 12u : 44u
not wearing watches, women : men = 20u : 12u
women wearing watches : women not wearing watches = 3:20
-> then answer will be 3:5, is my understanding wrong ?

Thanks!

[MathIzzzFun]

whitety:

MathIzzzFun:

[quote=\"peggy\"]Please help :

2.an equal number of men and women were at a party. The ratio of the number of woman who wore watches to the number of men who wore watches was 3:11. The ratio of the number of women to the number of men who did not wear watches was 5:3.

A. Find the ratio of the number of women who wore watches to the number of women who did not wear watches.

Many thanks.

Q2.
a)
wearing watches, women : men = 3 : 11 (difference of
not wearing watches, women : men = 5:3 (difference of 2)
--> difference must be the same since equal number of men and women

wearing watches, women : men = 3u : 11u
not wearing watches, women : men = 20u : 12u
women wearing watches : women not wearing watches = 3:20



Hi MathIzzzFun,

wearing watches, women : men = 3u : 11u need to x4? = 12u : 44u
not wearing watches, women : men = 20u : 12u
women wearing watches : women not wearing watches = 3:20
-> then answer will be 3:5, is my understanding wrong ?

Thanks![/quote]hope this MD helps...

http://i48.tinypic.com/2qledjr.png\">

cheers.

[whitety]

Hi MathIzzzFun,


Thank you very much!

[Winx5015]

Millions thanks to MathIzzzFun for solving my problems.


Have a nice day

[mummyL]

Mr Tok left for Town A for Town B at 11.30am. He travelled at an average speed of 75km/h. At 12.15pm, Ms Selva left Town A for Town B, travelling on the same route at an average speed of 100km/h.

(a) At what time would Ms Selva overtake Mr Tok? Ans 2.30pm
(b)After Ms Selva had overtaken Mr Tok, she took another 2 hours to reach Town B.What
was the distance between Town A and Town B? Ans 425km

[tianzhu]

mummyL:

Mr Tok left for Town A for Town B at 11.30am. He travelled at an average speed of 75km/h. At 12.15pm, Ms Selva left Town A for Town B, travelling on the same route at an average speed of 100km/h.

(a) At what time would Ms Selva overtake Mr Tok? Ans 2.30pm
(b)After Ms Selva had overtaken Mr Tok, she took another 2 hours to reach Town B.What
was the distance between Town A and Town B? Ans 425km

Hi

Your question is pretty similar to the earlier one posted by peggy.

Please refer to page 700 of this thread.

http://www.kiasuparents.com/kiasu/forum/viewtopic.php?f=69&t=280&start=6990

Distance travelled by Mr Tok from 1130 to 1215 ------- ¾*75 --------- 56.25

100 – 75 ------- 25

56.25/25 ------- 2h 15 minutes

From 1215, add 2h 15 minutes

Mr Selva overtakes Mr Tok at 2.30 pm

Mr Selva travelled for 4h 15 minutes (2h 15 minutes + 2h)

Distance between A and B ------ 4.25*100 ------- 425 km

Best wishes

[Winx5015]

http://i50.tinypic.com/11tvsqu.jpg[/img%20[IMG]http://i47.tinypic.com/35k0cao.jpg\"> ]

[MathIzzzFun]

Winx5015:

http://i48.tinypic.com/10n7waq.png\">

hope this helps ...

http://i47.tinypic.com/aai33p.png\">

cheers.

[Essential]

Good Day Tianzhu, please help as not sure how to solve this question . At first Alvin had twice as many trading cards as Steven . after Alvin had given away 285 of his trading cards , Steven had twice as many trading cards as Alvin . How many trading cards did they have altogether at first ?

[tianzhu]

Essential:

Good Day Tianzhu, please help as not sure how to solve this question . At first Alvin had twice as many trading cards as Steven . after Alvin had given away 285 of his trading cards , Steven had twice as many trading cards as Alvin . How many trading cards did they have altogether at first ?

Hi

At first

Alvin:Steven ------ 2:1 ------ 4:2

Only Alvin had given away 285 cards. Steven’s number of cards stays the same before and after.

Hence, make the number of units for Steven the same.

In the end

Alvin:Steven ------ 1:2

3 units ------- 285

1 unit ------ 95

Number of cards they had at first ------- 6*95 -------- 570

Best wishes