Q&A - PSLE Math
-
Shimmer:
Hi1)At 9a.m, John was cycling from A to B . At the same time, Mary was cycling from Point B to A using the same route as John. Cycling at a speed of 4km/h faster than Mary, John would pass Mary 300 m away from midpoint.
A)What time did that pass each other?
B) If John took another 3 min to reach B, what time would Mary reach B?
I think similar questions were discussed before.
When John pass Mary, the meeting point X will be nearer to B, and John would have cycled 300m x 2 = 600m more than Mary.
Time taken to pass each other = 600m/(4km/h) = 9 min
They passed each other at 9.09am
John took 3min to cycle the distance BX, Mary took 9 min to cycle the same distance BX.
For distance AX, Mary will take 9/3 x 9 = 27 min
9.09am + 27min --> 9.36am
Mary reached A at 9.36am
cheers. -
Hi!
Faye baked some muffins to sell.
2/3 of them were chocolate muffins and the remaining were walnut muffins.
After she had sold 5/6 of the chocolate muffins and 400 walnut muffins, she had 1/6 of the muffins left.
a) How many muffins did she sell altogether?
b) What percentage of the muffins sold were walnut muffins?
Thanks -
Neat:
HiHi!
Faye baked some muffins to sell.
2/3 of them were chocolate muffins and the remaining were walnut muffins.
After she had sold 5/6 of the chocolate muffins and 400 walnut muffins, she had 1/6 of the muffins left.
a) How many muffins did she sell altogether?
b) What percentage of the muffins sold were walnut muffins?
Thanks
CM : WM = 2:1 --> 12u : 6u (total 18u)
Sold, CM --> 10u, WM --> 400, total sold --> 5/6 of total = 5/6 x 18u = 15u
10u + 400 = 15u, 1u --> 80
..can you continue from here ?
cheers. -
MathIzzzFun:
[quote]Hi! MathIzzzFun[/quote]Yes, I can.
HiNeat:
Hi!
Faye baked some muffins to sell.
2/3 of them were chocolate muffins and the remaining were walnut muffins.
After she had sold 5/6 of the chocolate muffins and 400 walnut muffins, she had 1/6 of the muffins left.
a) How many muffins did she sell altogether?
b) What percentage of the muffins sold were walnut muffins?
Thanks
CM : WM = 2:1 --> 12u : 6u (total 18u)
Sold, CM --> 10u, WM --> 400, total sold --> 5/6 of total = 5/6 x 18u = 15u
10u + 400 = 15u, 1u --> 80
..can you continue from here ?
cheers.
Thank you so much for your prompt reply.
:thankyou: -
MathIzzzFun:
Shimmer:
In the 6A and B,the total number of girls was 100% more than boys. The ratio of boy to girl in 6A is 3:4 and the ratio of boy to girl in 6B is 1:6. If there were 8 more girls in 6a than 6b, find the no. of pupils in 6a.
Hi
6A, Boys: Girls = 3:4 --> 9:12
6B, Boys: Girls = 1:6 --> 2:12
There were 8 more girls in 6A than 6B,
6A, Boys: Girls --> 9u + 6 : 12u + 8 -- total --> 21u + 14
6B, Boys: Girls --> 2u : 12u
Total number of girls was 100% more than boys,
24u + 8 = 2 x (11u +6)
1u --> 2
Total number of pupils in 6A --> 21 x 2 + 14 = 56
cheers.
Thanks so much KaisuGrandMaster ! -
Help needed for these 4 questions - many thanks in advance!
1. Roy,Sam and Ted had a sum of money. Roy had 80% of Sam’s money. Sam had 60% of Ted’s. After Roy gave $12 to sam, he had 5/7 of what Sam had. How much more money did Ted have than Sam in the end?
2. Jerry bought four times as many pencils as notebooks and spent a total of $21.60. He spent $2.40 more on the notebooks than the pencils. Given that a notebook costs $3.20 more than a pencil, find the cost of a pencil.
3. Ms Lee baked 24 more chocolate muffins than banan muffins. After she gave away 1/6 of the chocolate muffins and 3/8 of the banana muffins, she was left with 35 more chocolate muffins than banana muffins. How many chocolate muffins did she bake at first?
4. At first, ravi had $200 more than vincent. He gave 40% of his money to Vincent. vincent then gave 25% of his money to ravi. In the end, Vincent had $68 more than Ravi. How much did Vincent give Ravi? -
jonaandr:
Hi
4. At first, ravi had $200 more than vincent. He gave 40% of his money to Vincent. vincent then gave 25% of his money to ravi. In the end, Vincent had $68 more than Ravi. How much did Vincent give Ravi?
You may draw MD to show the transactions or choose to work using units.
At first
Ravi ----- 20 units + 200
Vincent ------20 units
I use 20 units instead of 10 units to avoid working with decimals during future transfer.
Ravi gave 8 units + 80 to Vincent. He was left with 12 units + 120
Vincent now had 28 units + 80
Vincent then gave 25% of his money to Ravi.
25% ------- 7 units + 20
In the end
Ravi --------- 19 units + 140
Vincent ------- 21 units + 60
19 units + 140 + 68 ------ 21 units + 60
1 unit ----- 74
Vincent gave (7*74) + 20 or 538 to Ravi.
Best wishes -
jonaandr:
Hi
3. Ms Lee baked 24 more chocolate muffins than banan muffins. After she gave away 1/6 of the chocolate muffins and 3/8 of the banana muffins, she was left with 35 more chocolate muffins than banana muffins. How many chocolate muffins did she bake at first?
A common multiple of 6 and 8 is 24
At first
Banana muffins ----- 24 units
Chocolate muffins ----- 24 units + 24
She gave away 1/6 of the chocolate muffins and 3/8 of the banana muffins
In the end
Banana muffins ----- 15 units
Chocolate muffins ----- 20 units + 20
She was left with 35 more chocolate muffins than banana muffins.
15 units + 35 ------ 20 units + 20
5 units ------ 15
1 unit ------ 3
Number of chocolate muffins at first ----- (24*3) + 24 ------ 96
Best wishes -
jonaandr:
Hi
2. Jerry bought four times as many pencils as notebooks and spent a total of $21.60. He spent $2.40 more on the notebooks than the pencils. Given that a notebook costs $3.20 more than a pencil, find the cost of a pencil.
This question has been discussed before.
You may use MD or present your solution using Number*Value in tabulated form.
Due to time constraints, I shall give you some pointers for you to draw the MD.
Amount spent on pencils ----- (21.6 - 2.4)/2 ----- 9.6
Amount spent on note books ----- 12
9.6/4 ----- 2.4
12 – 2.4 ----- 9.6
Each notebook costs $3.2 more than a pencil.
Number of notebooks ----- 9.6/3.2 ----- 3
Number of pencils ----- 12
Cost of 1 pencil ----- 9.6/12 ------ 0.8
Best wishes -
jonaandr:
Hi1. Roy,Sam and Ted had a sum of money. Roy had 80% of Sam's money. Sam had 60% of Ted's. After Roy gave $12 to sam, he had 5/7 of what Sam had. How much more money did Ted have than Sam in the end?
This question has been discussed before.
It’s helpful to draw some simple pictorial representation to show the relationships among the three people.
Consider Roy and Sam first
In the beginning
Roy had 80% of Sam's money.
Roy ----- 4 units ----- 16 units
Sam ----- 5 units ----- 20 units
Total ----- 9 units ----- 36 units
After the transfer of $12 from Roy to Sam.
Roy ----- 5 units ----- 15 units
Sam ----- 7 units ----- 21 units
Total ----- 12 units ----- 36 units
A common multiple is 36.Make the total number of units the same as the amount of money(Roy and Sam) stays the same.
1 unit ---- 12
At first, Sam had (20*12) or 240
60% ----- 240
100% ----- 400
At first, Ted had 400.
In the end Sam had (21*12) or 252
Ted's amount of money stays the same before and after.
Hence, Ted had (400-252) or 148 more than Sam in the end.
Best wishes
Hello! It looks like you're interested in this conversation, but you don't have an account yet.
Getting fed up of having to scroll through the same posts each visit? When you register for an account, you'll always come back to exactly where you were before, and choose to be notified of new replies (either via email, or push notification). You'll also be able to save bookmarks and upvote posts to show your appreciation to other community members.
With your input, this post could be even better 💗
Register Login