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    Q&A - PSLE Math

    Scheduled Pinned Locked Moved Primary 6 & PSLE
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    • M Offline
      Michaelia0816
      last edited by

      How to solve such question?

      one apple cost $0.65 and one pear cost $0.75. Mrs Lee paid $28 for an equal number of apples and pears. How many fruits did she buy altogether?

      ( Source: Henry Park P6 Math)

      How to get the answer 40? Pls help, Tianzhu?

      1 Reply Last reply Reply Quote 0
      • N Offline
        niza6666.028774hotmail.028774com
        last edited by

        Hi, I need help on this question. Thanks for helping.

        Azman spent 9/14 of his money on 25 books and 8 pencils. The cost of a pencil is 1/4 that of a book. With the remainder of the money, he bought another 12 pencils and some books. How many books did he buy altogether?

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        • M Offline
          Michaelia0816
          last edited by

          Sorry, I already used GC to solve the question, ops… Wrong question!

          1 Reply Last reply Reply Quote 0
          • M Offline
            Michaelia0816
            last edited by

            mn:
            Hi, I need help on this question. Thanks for helping.

            Azman spent 9/14 of his money on 25 books and 8 pencils. The cost of a pencil is 1/4 that of a book. With the remainder of the money, he bought another 12 pencils and some books. How many books did he buy altogether?
            Hi Mn,
            I seemed to know how to answer this question!
            - Since a pencil is 1/4 of a book, you can take a pencil as 1u, and a book as 4u.

            25 books----25*4u=100u
            8 pencils----8*1u=8u

            9/14 of his money----100u+8u=108u
            5/14 of his money----60u

            The question said that he bought 12 pencils, so there is 12u.

            Units spent on books-----60u-12u=48u
            1 book is 4u
            12 books is 48u.

            25+12=37

            He bought 37 books altogether.

            🕺

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            • M Offline
              Michaelia0816
              last edited by

              [quote]Tianzhu, pls help!


              From Henry Park Primary, Math, Booklet B, Q29,

              A glass bottle filled with 6 identical ball-bearings weighs 1.05 kg. The same bottle when filled with 8 marbles weighs 830g. The mass of each ball-bearing is five times the mass of each marble. What is the mass of the empty glass?[/quote]Can somebody help? :?

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              • N Offline
                niza6666.028774hotmail.028774com
                last edited by

                Hi, can someone help me with this. TIA

                Mary put some red beads and blue beads in 2 jars. In Jar A, the ratio of the number of red beads to blue beads was 3:4. In Jar B, the number of red beads was twice the number of blue beads. Mary transferred half of the blue beads from Jar A to Jar B. The total number of beads in Jar A became 105 and the ratio of the number of red beads to the number of blue beads in Jar B became 5:6. What was the number of beads in Jar B after the transfer?

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                • MathIzzzFunM Offline
                  MathIzzzFun
                  last edited by

                  mn:
                  Hi, can someone help me with this. TIA

                  Mary put some red beads and blue beads in 2 jars. In Jar A, the ratio of the number of red beads to blue beads was 3:4. In Jar B, the number of red beads was twice the number of blue beads. Mary transferred half of the blue beads from Jar A to Jar B. The total number of beads in Jar A became 105 and the ratio of the number of red beads to the number of blue beads in Jar B became 5:6. What was the number of beads in Jar B after the transfer?
                  Hi

                  At first, in Jar A:
                  Red: blue --> 3u : 4u
                  half of blue was transferred to Jar B --> 2u transferred,
                  Left in Jar A, Red: Blue --> 3u : 2u -- total 5u --> 105
                  1u --> 21
                  Number of blue transferred to Jar B = 2 x 21 = 42

                  At first, in Jar B,
                  Red: Blue = 2 : 1 --> 10p : 5p
                  In the end, Red : Blue = 5 : 6 --> 10p:12p -- total 22p

                  So, 7p --> 42, 1p--> 6

                  Total number of beads in Jar B after transfer --> 6 x 22 = 132

                  cheers.

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                  • C Offline
                    cimman
                    last edited by

                    Michaelia0816:
                    How to solve such question?

                    one apple cost $0.65 and one pear cost $0.75. Mrs Lee paid $28 for an equal number of apples and pears. How many fruits did she buy altogether?

                    ( Source: Henry Park P6 Math)

                    How to get the answer 40? Pls help, Tianzhu?
                    if you are open to using algebra, here is a method:
                    just fill up the table, and you'll get your equation:

                    http://i49.tinypic.com/1z56ceu.png\">

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                    • M Offline
                      Michaelia0816
                      last edited by

                      thx cinman!

                      1 Reply Last reply Reply Quote 0
                      • M Offline
                        Michaelia0816
                        last edited by

                        Michaelia0816:
                        [quote]Tianzhu, pls help!


                        From Henry Park Primary, Math, Booklet B, Q29,

                        A glass bottle filled with 6 identical ball-bearings weighs 1.05 kg. The same bottle when filled with 8 marbles weighs 830g. The mass of each ball-bearing is five times the mass of each marble. What is the mass of the empty glass?
                        [/quote]Can somebody help?

                        1 Reply Last reply Reply Quote 0

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