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    Q&A - PSLE Math

    Scheduled Pinned Locked Moved Primary 6 & PSLE
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    • T
      tianzhu
      last edited by

      Michaelia0816:

      2) A forty- page newspaper, which consists of only one section, has a sheet with page 9 and page 10 missing. What other pages are missing?

      Pls done it by today as I am going to have math prelim the next day~.~
      Hi

      Try to see a pattern.This will help you in solving this question.

      If you need the solution, please let me know.I'll try to do the slide tomorrow.

      Best wishes

      1 Reply Last reply
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      • S
        speedmaths.012624com
        last edited by

        2DMommy:
        Please help me with these :


        Find the sum of 35 + 37 + 39 + 41 + 43 ........ + 231 + 233.

        What is the short cut to this question ?

        Thank you.
        Hi,

        One possible shortcut:
        (copied from the 2 books: Go For A* Vol 1a and Vol 2)

        Average = Sum / (Number of Terms)

        Sum = (Number of Terms) x Average

        Number of Terms = 100
        (there are 100 numbers from 35, 37, ... to 233)

        Average = (35 + 233) / 2 = 134

        Sum = 100 x 134 = 13400.

        Hope this helps.

        Cheers

        speedmaths.com

        .

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        • T
          tianzhu
          last edited by

          Tiramisu Coco:
          Hi, pls help with this qtn. Thks!


          http://m.flickr.com/photos/82618212@N07/7837766706/lightbox/
          Hi

          A similar question has been discussed in one of the earlier posts, but I can't locate it now.

          There are a few ways to solve it.

          One possible way.

          Radius of circle -------( a+b-c)/2 -------(18+24-30)/2 ------ 6 cm

          Best wishes

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          • A
            AJH
            last edited by

            Hi. I nd help with this ques.


            Brendan and Raidah saved $6475.60 altogether. 2/5 of Brendan’s savings was $341.50 more than 1/5 of Raidah’s savings. How much more money than Brendan did Raidah save?

            Can’t seem to get the ans - $1020.20. Thank you.

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            • MathIzzzFunM
              MathIzzzFun
              last edited by

              AJH:
              Hi. I nd help with this ques.


              Brendan and Raidah saved $6475.60 altogether. 2/5 of Brendan's savings was $341.50 more than 1/5 of Raidah's savings. How much more money than Brendan did Raidah save?

              Can't seem to get the ans - $1020.20. Thank you.
              1/5 of Raidah's savings --> 2 units,
              Raidah's savings --> 10 units
              2/5 of Brendan's savings --> 2 units + $341.50 = 2 x (1 unit + $170.75)
              Brendah's savings --> 5 units + $853.75

              Total --> 15 units + $853.75 = $6475.60
              5 units --> $1873.95

              Raidah's savings MINUS Brendan's savings
              = 5 units - $853.75
              = $1873.95 - $853.75 = $1020.20

              cheers.

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              • B
                Bunny27
                last edited by

                Hi, can someone pls help on this question


                1. Habri had some 20cents coins and 50cents coins.
                He spent 1/4 of his 20cents coins and 40% of his 50cents coins.
                The value of 20cents coins left was the same as the value of 50cents coins left. If the difference between the value of 20cents coins and the value of 50cents coins he had at first was $12, how much did Habri have at first?

                TIA

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                • E
                  ET-PH
                  last edited by

                  charsen:
                  superksmum:

                  Hi please help on this question (Henry Park Prelim 2011, question 16).


                  Mr Lee took 7 hours to travel from Town A to Town B while Mr Wong took 8 hours to travel from Town B to Town A. Both of them did not change their spped throughout the journey. Both of them started off at the same time and moved towards each other. 3 hours later, they were 110km apart. What was the speed Mr Lee was driving?

                  Thank you.

                  Hi
                  In 3 hours, lee drove 3/8 of the journey.At the same time,wong took 3/7 of the journey.So,we should make the denominators 8 and 7 to be 56 since the distance in both is common.

                  Lee travelled 24U and wong travelled 21U.
                  56u-24U-21U=11U
                  11U-110km
                  1U-110/11=10km
                  Distance lee travelled--->10x24=240km
                  Lee's speed------>240/3=80km/h(ANS)

                  Hi Charsen,

                  I stuck with this question too, can you explain how you get 3/8 of the journey for Lee and 3/7 of the journey for Wong. Thanks.

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                  • E
                    ET-PH
                    last edited by

                    Hi, I need help on HPPS 2011 Prelim Qn 17.


                    There were 1000 students at the parade ground and indoor sports hall. 40% of the 600 students at the parade ground were girls. 60% of the students at the indoor sports hall were girls. After some students in both the venues moved from one venue to the other, 30% of the students in the parade ground and 70% of the students at the indoor sports hall were girls. How many students were there in the indoor sports hall after the movement had taken place ? Thanks.

                    1 Reply Last reply
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                    • MathIzzzFunM
                      MathIzzzFun
                      last edited by

                      ET-PH:
                      Hi, I need help on HPPS 2011 Prelim Qn 17.


                      There were 1000 students at the parade ground and indoor sports hall. 40% of the 600 students at the parade ground were girls. 60% of the students at the indoor sports hall were girls. After some students in both the venues moved from one venue to the other, 30% of the students in the parade ground and 70% of the students at the indoor sports hall were girls. How many students were there in the indoor sports hall after the movement had taken place ? Thanks.

                      this was discussed - http://www.kiasuparents.com/kiasu/forum/viewtopic.php?f=69&t=280&start=7690

                      cheers.

                      1 Reply Last reply
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                      • MathIzzzFunM
                        MathIzzzFun
                        last edited by

                        ET-PH:
                        charsen:

                        Hi please help on this question (Henry Park Prelim 2011, question 16).


                        Mr Lee took 7 hours to travel from Town A to Town B while Mr Wong took 8 hours to travel from Town B to Town A. Both of them did not change their spped throughout the journey. Both of them started off at the same time and moved towards each other. 3 hours later, they were 110km apart. What was the speed Mr Lee was driving?

                        Thank you.
                        Hi
                        In 3 hours, lee drove 3/8 of the journey.At the same time,wong took 3/7 of the journey.So,we should make the denominators 8 and 7 to be 56 since the distance in both is common.

                        Lee travelled 24U and wong travelled 21U.
                        56u-24U-21U=11U
                        11U-110km
                        1U-110/11=10km
                        Distance lee travelled--->10x24=240km
                        Lee's speed------>240/3=80km/h(ANS)

                        Hi Charsen,

                        I stuck with this question too, can you explain how you get 3/8 of the journey for Lee and 3/7 of the journey for Wong. Thanks.

                        there is a typo error... Mr Lee travelled 3/7 of journey, Mr Wong travelled 3/8 of journey

                        Distance between AB --> 56 units
                        Mr Lee took 7 hours to travel from A to B,
                        so in 3 hours, distance travelled --> 3/7 x 56 units = 24 units

                        Mr Wong took 8 hours to travel from B to A
                        so, in 3 hours, distance travelled --> 3/8 x 56 units = 21 units

                        Total distance between A & B
                        = 21 units + 24 units + 110 km --> 56 units
                        11 units --> 110 km
                        1 unit --> 10 km
                        Mr Lee's speed --> distance AB/ time to travel AB = 56 x 10 / 7 = 80 km/h

                        cheers.

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