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    Q&A - PSLE Math

    Scheduled Pinned Locked Moved Primary 6 & PSLE
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    • K Offline
      kwcllf
      last edited by

      Hi please help.


      2 pieces of ribbon and 3 pieces of lace cost $10.
      3 pieces of ribbon and 2 pieces of lace cost $y.
      What is the total cost of 1 piece of ribbon and 1 piece of lace?
      Give the answer in terms of y.


      Thanks!

      1 Reply Last reply Reply Quote 0
      • F Offline
        fantasy1
        last edited by

        Hi

        does anyone know how to solve ?

        Thank You

        1 Reply Last reply Reply Quote 0
        • C Offline
          charsen
          last edited by

          kwcllf:
          Hi please help.


          2 pieces of ribbon and 3 pieces of lace cost $10.
          3 pieces of ribbon and 2 pieces of lace cost $y.
          What is the total cost of 1 piece of ribbon and 1 piece of lace?
          Give the answer in terms of y.


          Thanks!
          Hi
          This question can be solved using grouping method.

          You can find the price of 5 pieces of ribbon and 5 pieces of lace,which is
          $(10+y).
          So cost of one ribbon and 1lace is
          $(10+y)/5=(2+y/5)(ans)
          Cheers.

          1 Reply Last reply Reply Quote 0
          • M Offline
            Michaelia0816
            last edited by

            Could anyone kindly help me to solve the question below, thx you.


            Sani and Roney had a total of 398 game cards, Sani had 74 more game cards than Roney. After Roney had sold 25% fewer game cards than Sani, he had half as many game cards left as Sani. How many game cards had Roney left?

            1 Reply Last reply Reply Quote 0
            • R Offline
              rsorchid
              last edited by

              Pls help, Thanks.


              A florist had some roses, tulips and carnations. After selling some of them, there were 6 tulips for every 5 roses and 7 roses for every 3 carnations. After selling 168 roses, she had 456 tulips and carnations left. The number of tulips sold was the same as the number of carnations sold.
              a) How many roses had she at first?
              b) If the number of tulips was twice the number of carnations at first, what is the total number of tulips and carnations sold?

              1 Reply Last reply Reply Quote 0
              • T Offline
                tianzhu
                last edited by

                Michaelia0816:
                Could anyone kindly help me to solve the question below, thx you.


                Sani and Roney had a total of 398 game cards, Sani had 74 more game cards than Roney. After Roney had sold 25% fewer game cards than Sani, he had half as many game cards left as Sani. How many game cards had Roney left?
                Hi

                You may use MD or UP.

                Due to time constraints, I’ll skip the MD.

                At first
                Roney -------- 162
                Sani ------- 236

                Sold
                Roney -------- 3u
                Sani ------- 4u

                In the end
                Roney -------- 1p
                Sani ------- 2p

                3u + 1p ------ 162
                (x2)
                6u + 2p ------- 324


                4u + 2p ------- 236

                Equalize the parts.

                2u ------- 88

                1u ------- 44

                132 + 1p -------- 162

                1p ------- 30(Roney’s cards @end)

                Best wishes

                1 Reply Last reply Reply Quote 0
                • K Offline
                  kwcllf
                  last edited by

                  charsen:
                  kwcllf:

                  Hi please help.


                  2 pieces of ribbon and 3 pieces of lace cost $10.
                  3 pieces of ribbon and 2 pieces of lace cost $y.
                  What is the total cost of 1 piece of ribbon and 1 piece of lace?
                  Give the answer in terms of y.


                  Thanks!

                  Hi
                  This question can be solved using grouping method.

                  You can find the price of 5 pieces of ribbon and 5 pieces of lace,which is
                  $(10+y).
                  So cost of one ribbon and 1lace is
                  $(10+y)/5=(2+y/5)(ans)
                  Cheers.


                  Thanks charsen!

                  1 Reply Last reply Reply Quote 0
                  • DazzleD Offline
                    Dazzle
                    last edited by

                    Pls help. Q 9 from MGS Prelim 2012


                    Bottle A and bottle B both contain some juice.
                    If 1.3 litre of juice was poured into bottle A, the volume of juice in A will be 1.6 times that of the volume of the juice in bottle B.
                    If 480 ml of juice was poured into bottle B, the volume of juice in bottle B will be 1.8 times that of the volume of the juice in bottle A.

                    (a) What is the volume of juice in bottle A? (Ans. 1.1 litre)
                    (b) what is the difference in the volume of juice in both bottles? (Ans: 0.4 litre)

                    1 Reply Last reply Reply Quote 0
                    • T Offline
                      tianzhu
                      last edited by

                      rsorchid:
                      Pls help, Thanks.


                      A florist had some roses, tulips and carnations. After selling some of them, there were 6 tulips for every 5 roses and 7 roses for every 3 carnations. After selling 168 roses, she had 456 tulips and carnations left. The number of tulips sold was the same as the number of carnations sold.
                      a) How many roses had she at first?
                      b) If the number of tulips was twice the number of carnations at first, what is the total number of tulips and carnations sold?
                      Hi

                      A neat way is to use MD.

                      T:R ------ 6:5 -------42:35

                      R:C ------ 7:3 -------- 35:15

                      Since the share for roses is repeated, make it the same for both set of ratios

                      15 + 42 ------ 57

                      57 units -------- 456

                      1 unit ------- 8

                      (a)Number of roses left ------- 35*8 -------- 280

                      Number of roses@first -------- 280+168 -------- 448

                      (b) Draw 1 box to show number of tulips/carnation sold.

                      Number of tulips left ------- 42*8 -------- 336

                      Number of carnations left -------- 120

                      1 box + 336 ------- 1 box + 120 = 1 box + 120

                      1 box ------- 96

                      The total number of tulips and carnations sold ------- 96*2 ------- 192

                      Best wishes

                      1 Reply Last reply Reply Quote 0
                      • W Offline
                        whitety
                        last edited by

                        Hi, need help on this qn.


                        Lina bought some chocolate and vanilla muffins in the ratio 2:3. She packed the chocolate muffins into boxes of 3 and the vanilla muffins into boxes of 4. There were 6 more boxes of vanilla muffins than chocolate muffins. How many chocolate muffins did Lina buy?

                        Thanks!

                        1 Reply Last reply Reply Quote 0

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