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    Q&A - P5 Math

    Scheduled Pinned Locked Moved Primary 5
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    • K Offline
      KP2
      last edited by

      Hi , need help with this one . Many thanks in advance


      Jim bought some chocolates and gave half to them to Ken. Ken bought some sweets and gave half of them to Jim.

      Jim ate 12 sweets and Ken ate 18 chocolates. After that, the number of sweets and chocolates Jim had were in the ratio 1:7 and the number of sweets and chocolates Ken had were in the ratio 1:4.

      How many sweets did Ken buy?

      1 Reply Last reply Reply Quote 0
      • M Offline
        Maths Hub
        last edited by

        KP2:
        Hi , need help with this one . Many thanks in advance


        Jim bought some chocolates and gave half to them to Ken. Ken bought some sweets and gave half of them to Jim.

        Jim ate 12 sweets and Ken ate 18 chocolates. After that, the number of sweets and chocolates Jim had were in the ratio 1:7 and the number of sweets and chocolates Ken had were in the ratio 1:4.

        How many sweets did Ken buy?
        The yellow boxes refer to the unchanged quantity.
        http://i47.tinypic.com/2s1ugwk.jpg\">

        Cheers! :salute:

        1 Reply Last reply Reply Quote 0
        • Z Offline
          zombie
          last edited by

          Hello, please help me to check if my answer and solution are acceptable.

          I'm a parent teaching my P5 boy maths. :scratchhead: Thanks !

          If Mr Ibrahim buys 3 plates and 5 cups, he will have $6 left. If he wants to buy 5 plates and 3 cups, he will need another $4. Given that a cup costs $1.50, how much does he have?

          My solution

          Let x be the total amount he has
          3p + 7.50 = x - 6 (x5)
          5p + 4.50 = x + 4 (x3)

          15p + 37.50 = 5x - 30
          15p + 13.50 = 3x + 12
          24.00 = 2x – 42

          24 + 42 = 2x

          66 ÷ 2 = x
          X = 33

          Answer :he has $33

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          • M Offline
            Maths Hub
            last edited by

            zombie:
            Hello, please help me to check if my answer and solution are acceptable.

            I'm a parent teaching my P5 boy maths. :scratchhead: Thanks !

            If Mr Ibrahim buys 3 plates and 5 cups, he will have $6 left. If he wants to buy 5 plates and 3 cups, he will need another $4. Given that a cup costs $1.50, how much does he have?

            My solution

            Let x be the total amount he has
            3p + 7.50 = x - 6 (x5)
            5p + 4.50 = x + 4 (x3)

            15p + 37.50 = 5x - 30
            15p + 13.50 = 3x + 12
            24.00 = 2x – 42

            24 + 42 = 2x

            66 ÷ 2 = x
            X = 33

            Answer :he has $33
            Hi zombie,

            Depending on your child's school, algebraic method may or may not be accepted, even though it is correct.

            Allow me to offer another non-algebraic way:
            By drawing models,
            2 plates will cost $10 more than 2 cups.
            So each plate cost $5 more than each cup,
            which means the cost cost of each plate is $6.50.
            Therefore, he has $6.50 X 3 + 5 X $1.50 + $6 = $33. :snuggles:

            Cheers.

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            • Y Offline
              YumYum
              last edited by

              Hi, need help with qn:


              In may, the average number of participants in one pottery class was 24. In June, 5 new pottery classes were added. The average number of participants in all the pottery classes became 26. If there were 32 participants in each of the new pottery classes, find the total number of participants in all the pottery classes in June.

              Thanks!

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              • M Offline
                Maths Hub
                last edited by

                YumYum:
                Hi, need help with qn:


                In may, the average number of participants in one pottery class was 24. In June, 5 new pottery classes were added. The average number of participants in all the pottery classes became 26. If there were 32 participants in each of the new pottery classes, find the total number of participants in all the pottery classes in June.

                Thanks!
                Total extra members from the new classes that contribute to the rise in old average --> (32 - 26) X 5 = 30
                Rise in old average --> 26 - 24 = 2
                Original number of classes --> 30 / 2 = 15
                New number of classes --> 15 + 5 = 20
                Total number of participants --> 20 X 26 = 520

                Cheers.

                1 Reply Last reply Reply Quote 0
                • Z Offline
                  zombie
                  last edited by

                  This question is taken from Nanyang SA2, 2011 question 17 paper 2.

                  Can someone help me to solve ? Thanks !

                  At first, the ratio of the number of men to the number of women in a
                  cinema was 2:5. When 48 women and some men entered the cinema
                  the number of women increased by 12% and the total number of people
                  in the cinema increased by 20%.
                  (a) How many men were there at first?
                  (b) What percentage of the people in the cinema were men in the end?
                  Express your answer as a mixed number.

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                  • D Offline
                    dazzlego
                    last edited by

                    savoury sweet:
                    Hi everyone,kindly help to solve the following question. Thanks so much.


                    A grp of pupils claculated their average score for Science test. They noted that if anyone scored 14 marks and more, their average would be 90. If anyone scored 4 marks fewer, their average score would be 88. How many pupils are there in the grp?
                    Hi savoury sweet,

                    You can assume that the number of pupils is 1 unit
                    case 1: the total score -> 90 units - 14
                    case 2: the total score -> 88 units + 4
                    2 units -> 14 + 4 = 18
                    1 unit -> 18 ÷ 2 = 9

                    Cheers :celebrate:

                    1 Reply Last reply Reply Quote 0
                    • D Offline
                      dazzlego
                      last edited by

                      zombie:
                      Hello, helping my son to solve using agebra,

                      can someone tell me if the answer is correct ?

                      Can someone suggest other method? i was taught using Algebra in the 1970s. lost touch. Thanks :roll:

                      Mrs Lim bought some green apples for an average cost of $0.45. However, if she exchanges 4 green apples for 4 red apples, which cost $0.75 each, the average price of each apple would be $0.55
                      How many apples are there altogether ?

                      Let the total number of apples be X
                      X (0.45)+ (4x 0.75) \t= 0.55 X
                      0.45 (X - 4) + 3.00\t= 0.55 X
                      0.45 X -18 + 3.00\t= 0.55 X - 0.45 X
                      1.2\t= 0.10 X
                      12\t= X
                      there are 12 apples altogether
                      Hi zombie,

                      Generally it is correct. However don't rush the steps and don't miss all the details (decimal points, the character (X) must be writen after the number, etc)
                      Let the total number of apples be X
                      0.45 (X - 4) + 4 x 0.75 \t= 0.55 X
                      0.45 (X - 4) + 3.00\t= 0.55 X
                      0.45 X - 1.80 + 3.00\t= 0.55 X
                      0.45 X + 1.20 = 0.55 X
                      1.20\t= 0.10 X
                      12\t= X
                      there are 12 apples altogether


                      Cheers :celebrate:

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                      • P Offline
                        papilion
                        last edited by

                        Can someone please help to solve the question posted by @zombie ?

                        1 Reply Last reply Reply Quote 0

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