Q&A - P4 Math

[snowball]

MathIzzzFun:

[Dear MathIzzzFun, please explain ( how to explain to the kids) why we need to change to same numerator TIA

so that we will get this model :

http://i48.tinypic.com/6plyj6.png\">

cheers.[/quote]
Dear MathIzzzFun, :thankyou: :please:

[AgonyMum]

Please help to solve these 2 questions using both model and equation methods.P4 standard

Thanks very much.

1. Fiona had 3 times as many stickers as dolls. After she gave away 7 stickers and 10 dolls, the number of stickers was 4 times the number of dolls. How many stickers and dolls did she have at first?

2.There were 5 times as many candies as sweets in a store. After 16 candies were sold and 16 sweets were brought into the store, the number of candies was 3 times the number of sweets. If each item cost 80 cents, how much money would be collected from the sale of the sweets?

[BigDevil]

http://i47.tinypic.com/2ez5qit.jpg\">

[dazzlego]

AgonyMum:

Please help to solve these 2 questions using both model and equation methods.P4 standard

Thanks very much.

1. Fiona had 3 times as many stickers as dolls. After she gave away 7 stickers and 10 dolls, the number of stickers was 4 times the number of dolls. How many stickers and dolls did she have at first?

2.There were 5 times as many candies as sweets in a store. After 16 candies were sold and 16 sweets were brought into the store, the number of candies was 3 times the number of sweets. If each item cost 80 cents, how much money would be collected from the sale of the sweets?

Hi AgonyMum,

The total at first and in the end must be the same
At first,
Candies = 5 units, Sweets = 1 unit (Total = 6 units)
Candies = 10 units, Sweets = 2 units (Total = 12 units)
In the end,
Candies = 3 units, Sweets = 1 unit (Total = 4 units)
Candies = 9 units, Sweets = 3 units (Total = 12 units)

1 unit -> 16
12 units ->192
192 x $0.80 = $153.60

Hope it is correct. I am sorry if it is not clear or incorrect. I am doing it in rush
Draw the model just in case you need to see the model

http://i46.tinypic.com/2010zgk.jpg\">

Cheers :celebrate:

[MathIzzzFun]

AgonyMum:

Please help to solve these 2 questions using both model and equation methods.P4 standard

Thanks very much.

1. Fiona had 3 times as many stickers as dolls. After she gave away 7 stickers and 10 dolls, the number of stickers was 4 times the number of dolls. How many stickers and dolls did she have at first?

2.There were 5 times as many candies as sweets in a store. After 16 candies were sold and 16 sweets were brought into the store, the number of candies was 3 times the number of sweets. If each item cost 80 cents, how much money would be collected from the sale of the sweets?

Q2.

http://i47.tinypic.com/zv3jpf.png\">

cheers.

[AgonyMum]

Thank you all so much for helping I am still trying to figure out the solutions.....lost right now.

Possible to solve using equation/ substitution/ algebra?
Thanks!

[BigDevil]

AgonyMum:

Thank you all so much for helping I am still trying to figure out the solutions.....lost right now.

Possible to solve using equation/ substitution/ algebra?
Thanks!

Fiona had 3 times as many stickers as dolls. S = 3D

After she gave away 7 stickers and 10 dolls, the number of stickers was 4 times the number of dolls.
S-7 = 4(D-10)

How many stickers and dolls did she have at first?
Substituting S,

3D - 7 = 4D - 40
D = 33
S = 33 x 3 = 99

[cimman]

AgonyMum:

Thank you all so much for helping I am still trying to figure out the solutions.....lost right now.

Possible to solve using equation/ substitution/ algebra?
Thanks!

hi AgonyMum,
have a look at this technique: http://www.kiasuparents.com/kiasu/forum/viewtopic.php?f=67&t=25121&start=1260

you can use the exact same technique for your problems.
First draw the table, then transfer all the values over to the table.

let me know if you need help in this area.

[optimistforum]

Hello friends


I have issues with DS1 (he will be 10 in summer 2013). The following two questions are symptomatic of his lack of problem-solving skills.

How do I communicate the following solutions to him. Are there other methods I can communicate and what would they be?

1) Mince costs £1.80 per 0.5Kg. Find the cost of mince weighing 600g.

Solution: £1.80 = 500g, so 100g = £1.80/5 = 36p
so 600 g = 6 X 36 = £2.16

2) A shopkeeper bought 6 balls for £1.32 and sold them to make a total profit of 48p. For how much did he sell each ball.

Solution: £1.32/6 = 22p intial cost for each ball.

profit of 48p for 6 balls = 48/6 = 8p profit per ball.

Therefore selling price of each ball is 22p + 8p = 30p

Regards
O

[dazzlego]

Hi optimistforum,


For Question 1, the way u solved it should be the best approach.
- Find the price for the nearest 100g ( common multiple)
I don't think it is necessary to mention the bold to the child
0.5 kg = 500g
500g --> £1.80 (Divide both sides by 5 to get 100g) (since 500g is 5x of 100g)
100g --> £1.80 / 5 = £0.36 (36p) (Multiply both sides by 6 to get 600g)
600g --> 36p x 6 = 216p (£2.16)


For Question 2, u may want to try this approach
- Find the total selling price for 6 balls
£1.32 + 48p = £1.80 (132p + 38p = 180p)

- Find the selling price for 1 ball
£1.80 / 6 = £0.30 (180p / 6 = 30p)

Hope it helps :celebrate:

optimistforum:

Hello friends

I have issues with DS1 (he will be 10 in summer 2013). The following two questions are symptomatic of his lack of problem-solving skills.

How do I communicate the following solutions to him. Are there other methods I can communicate and what would they be?

1) Mince costs £1.80 per 0.5Kg. Find the cost of mince weighing 600g.

Solution: £1.80 = 500g, so 100g = £1.80/5 = 36p
so 600 g = 6 X 36 = £2.16

2) A shopkeeper bought 6 balls for £1.32 and sold them to make a total profit of 48p. For how much did he sell each ball.

Solution: £1.32/6 = 22p intial cost for each ball.

profit of 48p for 6 balls = 48/6 = 8p profit per ball.

Therefore selling price of each ball is 22p + 8p = 30p

Regards
O