Q&A - P5 Math

[Jamesbond]

MathIzzzFun:

Jamesbond:

Oh so sorry mathizzfun.....typo error.. :slapshead: It is tan only....loads n loads of homework in beginning of P5 itself am struggling to help my ds in his work.....


Tans current age is 1/4 of Ronald's. In 24 years time Ronald's age will be 14 years less than twice tans age. What is Ronald's age now?

TIA....

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cheers.

Thank you Mathizzfun.

[Jamesbond]

Dawn and Minny had the same number of stickers at first. After Dawn gave 24 stickers to Minny. Minny had 5 times as many stickers as Dawn. How many stickers did Minny have at first?


Is some info missing in this sum…or is it possible to solve…My ds doubt…Pl help…

[ttyh]

What is the sum of all the odd numbers that are less than 100?

(Surely there is some sort of formula for this??)
Pls help! Thanks

[MathIzzzFun]

ttyh:

What is the sum of all the odd numbers that are less than 100?

(Surely there is some sort of formula for this??)
Pls help! Thanks

hi

here's a question which I give to my students when I introduce odd/even numbers sequence :

The following number pattern is formed by consecutive odd numbers:
1, 3, 5, 7, .............
a) Find the 6th number in the sequence
b) Find the 8th number in the sequence.
c) Find the 35th number in the sequence
c) Find the sum of the first 3 numbers.
d) Find the sum of the first 6 numbers.
e) Find the sum of the first 35 numbers.

This will let the students explore and see how are odd numbers related to square numbers.

cheers.

[MathIzzzFun]

Jamesbond:

Dawn and Minny had the same number of stickers at first. After Dawn gave 24 stickers to Minny. Minny had 5 times as many stickers as Dawn. How many stickers did Minny have at first?


Is some info missing in this sum....or is it possible to solve....My ds doubt....Pl help..

Hi

you can use MD or ratio ..
...concept --> total number of stickers remain the same...

In the end
Dawn's stickers : Minny's stickers --> 1u : 5u (total 6u)

at first
Dawn's stickers : Minny's stickers = 1:1 --> 3u : 3u (total 6u)

From above, observe that Dawn gave away 2u, and Minny received 2u

So, 2u --> 24, 1u--> 12
At first, Minny's stickers --> 3 x 12 = 36

cheers.

[heyhoe]

Hi,


I need help with this maths question:-
The Lim family of two adults and three children are 100 years old altogether. The sum of the father’s age and the son’s age is 51 years in total. The father is 3 years older than the mother. While the twin daughters are each 5 years younger than the brother. Can you work out everyone’s age?

[dazzlego]

heyhoe:

Hi,


I need help with this maths question:-
The Lim family of two adults and three children are 100 years old altogether. The sum of the father's age and the son's age is 51 years in total. The father is 3 years older than the mother. While the twin daughters are each 5 years younger than the brother. Can you work out everyone's age?

You can use this assumption using units and parts then work it out

Father's age = 1 unit
Mother's age = 1 unit - 3
Son's age = 1 part
Daughter's age = 1 part - 5

Father + Son :
1 unit + 1 part = 51

Mother + 2 Daughter :
(1 unit - 3) + (1 part - 5) + (1 part - 5) = 49
1 unit + 2 parts - 13 = 49
1 unit + 2 parts = 62

From those 2 equations,
1 part = 62 - 51 = 11 (Son)
11 - 5 = 6 (Twin Daughters)
51 - 11 = 40 (Father)
40 - 3 = 37 (Mother)

Hope it helps,
Cheers :celebrate:

[speedmaths.012624com]

ttyh:

What is the sum of all the odd numbers that are less than 100?

(Surely there is some sort of formula for this??)
Pls help! Thanks

Hi,

The solution below is copied from the book:
\"Go For A* - Volume 1A\"
published by Amazing Books.

Hope it helps.

Cheers


speedmaths.com


=

1 + 3 + 5 + ... + 99

1) First, find the Average of all these numbers:
Average = (First Number + Last Number) / 2
Average = (1 + 99) / 2 = 50

2) Next, find the Number of Terms (or how many numbers are there):
For a series of odd numbers starting with 1,
the Average is also equal to the Number of Terms
Number of Terms = 50

3) Sum = Average x Number of Terms
Sum = 50 x 50 = 2500


.

[heyhoe]

Hi dazzlego,


Thank you so much for the clear explanation.

dazzlego:

heyhoe:

Hi,

I need help with this maths question:-
The Lim family of two adults and three children are 100 years old altogether. The sum of the father's age and the son's age is 51 years in total. The father is 3 years older than the mother. While the twin daughters are each 5 years younger than the brother. Can you work out everyone's age?

You can use this assumption using units and parts then work it out

Father's age = 1 unit
Mother's age = 1 unit - 3
Son's age = 1 part
Daughter's age = 1 part - 5

Father + Son :
1 unit + 1 part = 51

Mother + 2 Daughter :
(1 unit - 3) + (1 part - 5) + (1 part - 5) = 49
1 unit + 2 parts - 13 = 49
1 unit + 2 parts = 62

From those 2 equations,
1 part = 62 - 51 = 11 (Son)
11 - 5 = 6 (Twin Daughters)
51 - 11 = 40 (Father)
40 - 3 = 37 (Mother)

Hope it helps,
Cheers :celebrate:

[Jamesbond]

MathIzzzFun:

Jamesbond:

Dawn and Minny had the same number of stickers at first. After Dawn gave 24 stickers to Minny. Minny had 5 times as many stickers as Dawn. How many stickers did Minny have at first?


Is some info missing in this sum....or is it possible to solve....My ds doubt....Pl help..

Hi

you can use MD or ratio ..
...concept --> total number of stickers remain the same...

In the end
Dawn's stickers : Minny's stickers --> 1u : 5u (total 6u)

at first
Dawn's stickers : Minny's stickers = 1:1 --> 3u : 3u (total 6u)

From above, observe that Dawn gave away 2u, and Minny received 2u

So, 2u --> 24, 1u--> 12
At first, Minny's stickers --> 3 x 12 = 36

cheers.

Ratio not yet started for my ds...can u explain in a diff way? Thx.