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    Q&A - P5 Math

    Scheduled Pinned Locked Moved Primary 5
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    • O Offline
      Oracle
      last edited by

      Got it, MathIzzzFun, thank you.


      Is it possible to solve this question at all:

      The length of a rectangle is thrice its breadth. After its breadth is lengthened by 12cm and its length is shortened by 2cm, it will form a square. What is the area of the square after adjustment?

      1 Reply Last reply Reply Quote 0
      • J Offline
        Jamesbond
        last edited by

        Oracle:
        Got it, MathIzzzFun, thank you.


        Is it possible to solve this question at all:

        The length of a rectangle is thrice its breadth. After its breadth is lengthened by 12cm and its length is shortened by 2cm, it will form a square. What is the area of the square after adjustment?
        12+2=14
        14/2=7
        7+12=19
        7*3=21
        21-2=19
        19*19=361....
        Hope I am Correct 🕺

        1 Reply Last reply Reply Quote 0
        • T Offline
          tianzhu
          last edited by

          Oracle:

          The length of a rectangle is thrice its breadth. After its breadth is lengthened by 12cm and its length is shortened by 2cm, it will form a square. What is the area of the square after adjustment?
          Hi

          It helps to draw a simple sketch.

          Length of rectangle ----- 3u

          Breadth of rectangle ------ 1u

          After its breadth is lengthened by 12cm and its length is shortened by 2cm, it will form a square.

          3u – 2 ------- 1u + 12

          2u ------- 14

          1u ------- 7

          Side of square --------12+7 ------- 19

          From here, you may work out the area (19*19).

          Please refer to your PM for the WB solution.

          Best wishes

          1 Reply Last reply Reply Quote 0
          • E Offline
            elisammom
            last edited by

            Hi pls help. This is the 2011 CA1 Nanhua paper

            http://i46.tinypic.com/29bo9ro.jpg\">
            TIA

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            • T Offline
              tianzhu
              last edited by

              elisammom:
              Hi pls help. This is the 2011 CA1 Nanhua paper

              http://i46.tinypic.com/29bo9ro.jpg\">
              TIA
              Hi
              You may use \"Listing\"

              Total number of students for A, C,D and E ------- 77

              Find multiples of 5 and 7 after 77

              Multiples of 5 ------ 80,85,90,95

              Multiples of 5 + 1 ------ 81,86,91,96

              Multiples of 7 ------ 84, 91

              Multiples of 7 + 5 ------ 89, 96

              The common number is 96

              Least number of students in B ------- 96-77 ------- 19

              Hope this helps

              Best wishes

              1 Reply Last reply Reply Quote 0
              • S Offline
                Sharmum
                last edited by

                Hi,


                Please help…

                Q1) Limeng is 10 years old and his sister is 7 years old . In how many years’ time will their total age be 41 years?

                Q2) A basket with 65 sweets has a mass of 3200g . The same basket with 40 sweets has a mass of 2125g. Each sweet has the same mass . What is the mass of the basket?


                Many thanks!

                1 Reply Last reply Reply Quote 0
                • T Offline
                  Trina
                  last edited by

                  Please assist with this question:


                  There are 40 pupils in a class. Each boy donated $3 and each girl donated $2. The boys donated $30 more than the girls.
                  How many boys are there?
                  How many girls are there?

                  Thanks!

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                  • MathIzzzFunM Offline
                    MathIzzzFun
                    last edited by

                    Sharmum:
                    Hi,


                    Please help....

                    Q1) Limeng is 10 years old and his sister is 7 years old . In how many years' time will their total age be 41 years?

                    Q2) A basket with 65 sweets has a mass of 3200g . The same basket with 40 sweets has a mass of 2125g. Each sweet has the same mass . What is the mass of the basket?


                    Many thanks!
                    Q1.
                    Total age now --> 10+7=17
                    (41-17)/2 = 12 ...(both grow older by the same number of years)
                    Their total age will be 41 years in 12 years' time.

                    Q2.

                    Mass of (65-40)= 25 sweets --> 3200g - 2125g = 1075g
                    mass of 1 sweet --> 43g
                    Mass of basket --> 2125g - 40 x 43g = 405g

                    cheers.

                    1 Reply Last reply Reply Quote 0
                    • E Offline
                      elisammom
                      last edited by

                      tianzhu:
                      elisammom:

                      Hi pls help. This is the 2011 CA1 Nanhua paper

                      http://i46.tinypic.com/29bo9ro.jpg\">
                      TIA

                      Hi
                      You may use \"Listing\"

                      Total number of students for A, C,D and E ------- 77

                      Find multiples of 5 and 7 after 77

                      Multiples of 5 ------ 80,85,90,95

                      Multiples of 5 + 1 ------ 81,86,91,96

                      Multiples of 7 ------ 84, 91

                      Multiples of 7 + 5 ------ 89, 96

                      The common number is 96

                      Least number of students in B ------- 96-77 ------- 19

                      Hope this helps

                      Best wishes


                      Very clear! Thanks a lot!

                      1 Reply Last reply Reply Quote 0
                      • MathIzzzFunM Offline
                        MathIzzzFun
                        last edited by

                        Trina:
                        Please assist with this question:


                        There are 40 pupils in a class. Each boy donated $3 and each girl donated $2. The boys donated $30 more than the girls.
                        How many boys are there?
                        How many girls are there?

                        Thanks!
                        Assume all boys donated, total amount --> 40 x $3 = $120
                        $120 - $30 = $90 --- excess amount to be reduced by girls' donation
                        Number of girls = $90/($3+$2) = 18
                        Number of boys = 40-18 = 22

                        cheers.

                        1 Reply Last reply Reply Quote 0

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