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    O-Level Additional Math

    Scheduled Pinned Locked Moved Secondary Schools - Academic Support
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    • M Offline
      Michaelia0816
      last edited by

      Ty jieheng

      1 Reply Last reply Reply Quote 0
      • L Offline
        LOL123
        last edited by

        Thank you so much! I have 1 last question šŸ˜„


        The arrow diagram shows part of the mapping h(x)=12/ax+b, x≠-b/a
        Calculate the values of a and b. Hence find

        (i) the element that has an image of -2 under this mapping,
        (ii) the values of x for which h(x)=x

        I am in sec 2 this year. and yup, i am currently doing functions šŸ˜• http://i48.tinypic.com/25kq4hs.jpg\">

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        • S Offline
          shin88
          last edited by

          Pls help me on the following Qin. Thanks

          If 600 = 2^3 x 3 x 5^2. Find the smallest value of p such that 600p is a perfect cube.

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          • J Offline
            jieheng
            last edited by

            shin88:
            Pls help me on the following Qin. Thanks

            If 600 = 2^3 x 3 x 5^2. Find the smallest value of p such that 600p is a perfect cube.
            600 = 2^3 x 3 x 5^2

            To be a perfect cube , the index of the prime factors of 600p must be multiple of 3 ,

            600p = 2^3*3^3*5^3

            p = 3^2*5 = 45

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            • S Offline
              shin88
              last edited by

              Thanks for your solution. I understand how u get 2^3x3^3x5^3 but how to get 3^2x5 ?

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              • J Offline
                jieheng
                last edited by

                shin88:
                Thanks for your solution. I understand how u get 2^3x3^3x5^3 but how to get 3^2x5 ?

                600 = 2^3 x 3 x 5^2

                600p = 2^3 * 3^3 * 5^3
                2^3 * 3 * 5^2 * p =2^3 * 3^3 * 5^3

                p = 3^2*5 = 45

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                • S Offline
                  shin88
                  last edited by

                  Thanks a lot, I finally understand :rahrah:

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                  • 2 Offline
                    2DMommy
                    last edited by

                    Please help with this q :


                    Choose any 3 digits and make a 6 digit number by repeating the 3 digits in the same order (eg 123123). The number formed will always be divisible by 7,11 and 13.
                    A) explain why
                    B) what are the other factors of any such number formed ?

                    Thks !

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                    • W Offline
                      WTK
                      last edited by

                      Help please!


                      Find the greatest number that will divide 171, 255 and 304 so as to leave the same remainder in each case.

                      Kindly show the workings. Thank you.

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                      • J Offline
                        Jtutor
                        last edited by

                        2DMommy:
                        Please help with this q :


                        Choose any 3 digits and make a 6 digit number by repeating the 3 digits in the same order (eg 123123). The number formed will always be divisible by 7,11 and 13.
                        A) explain why
                        B) what are the other factors of any such number formed ?

                        Thks !
                        Hi 2DMommy,

                        A) 7x11x13 = 1001
                        1001x100 = 100100 (answer)
                        B) Other factors are 2^2 x 5^2

                        Hope the above is correct.

                        Cheers!
                        Jtutor

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