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    Tutor MathsGuru: Ask me for your burning Maths questions!

    Scheduled Pinned Locked Moved Primary Schools - Academic Support
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    • TancelT Offline
      Tancel
      last edited by

      My earlier posting came out wrongly. Sorry! 😓 Here's the amended version.


      Hi, i'm new here and happen to see this question being posted.

      My solution is: We should be finding time taken by Muthu to travel from B to A= 2x3u=450minutes=7.5 hrs

      Hence, time Muthu left Town B =7.5hrs before 2.45pm ( being the time Muthu reached town A) =7.15am

      Given that Muthu left Town B 45minutes after Ali left Town A, hence time Ali left Town A =6.30am ( 45 minutes before 7.15am )

      Please comment if am wrong. Thanks!

      1 Reply Last reply Reply Quote 0
      • MathIzzzFunM Offline
        MathIzzzFun
        last edited by

        Tancel:
        My earlier posting came out wrongly. Sorry! 😓 Here's the amended version.


        Hi, i'm new here and happen to see this question being posted.

        My solution is: We should be finding time taken by Muthu to travel from B to A= 2x3u=450minutes=7.5 hrs

        Hence, time Muthu left Town B =7.5hrs before 2.45pm ( being the time Muthu reached town A) =7.15am

        Given that Muthu left Town B 45minutes after Ali left Town A, hence time Ali left Town A =6.30am ( 45 minutes before 7.15am )

        Please comment if am wrong. Thanks!
        I have misread as Ali reached at 2. 45pm.

        Thanks for highlighting the error, your working is correct - Ali left at 6. 30am

        cheers.

        1 Reply Last reply Reply Quote 0
        • B Offline
          Bokwa
          last edited by

          Hi MathsGuru,


          Please help my child with these questions.

          Q: There were a total of 930 boys and girls at a carnival. After 4/5 of the boys and 3/4 of the girls left there were 120 more girls than boys that remained. How many boys were at the carnival at first?

          Q: 94 children took part on a lucky draw and 32 of them won a prize. 1/8 of the girls and 4/5 of the boys won a prize. How many girls did not win a prize.

          Please help…thanks alot.

          1 Reply Last reply Reply Quote 0
          • MathIzzzFunM Offline
            MathIzzzFun
            last edited by

            Bokwa:
            Hi MathsGuru,


            Please help my child with these questions.

            Q: There were a total of 930 boys and girls at a carnival. After 4/5 of the boys and 3/4 of the girls left there were 120 more girls than boys that remained. How many boys were at the carnival at first?

            Q: 94 children took part on a lucky draw and 32 of them won a prize. 1/8 of the girls and 4/5 of the boys won a prize. How many girls did not win a prize.

            Please help....thanks alot.
            Firstly, I m not mathsguru ...mathsguru is the user who started this thread.


            Q1.
            Number of boys remaining (1/5) --> 1 unit --------- total number of boys --> 5 units

            Number of girls remaining (1/4) --> 1 unit + 120 ----- total number of girls --> 4 units + 480

            Total number of boys and girls
            = 9 units + 480 --> 930
            1 unit --> 50

            Total number of boys at first --> 5 x 50 = 250

            Q2.
            1/8 girls + 4/5 boys --> 32
            4/32 girls + 4/5 boys --> 32
            1/32 girls + 1/5 boys --> 8

            32/32 girls + 5/5 boys --> 94
            27/32 girls + (5/32 girls + 5/5 boys) --> 94
            27/32 girls --> 94 - 5 x 8 = 54
            1/32 girls --> 2 ------- total number of girls --> 64
            Number of girls who did not win any prize = 7/8 x 64 = 56

            cheers.

            1 Reply Last reply Reply Quote 0
            • B Offline
              Bokwa
              last edited by

              Hi,


              Can someone please help me to solve these two questions?

              Q1: The ratio of Sasi’s age to his father’s age is 2:7 at present. In twelve years’ time, the ratio will become 2:5. Find Sasi’s present age.

              Q2: Ken and Clark went shopping. The ratio of money Ken had to what Clark had was 6:5. The amount each of them spent was in the ratio 3:2 respectively. Ken spent 1/4 of his money. What was the ratio of the amount Ken had left to the amount Clark had left?

              Thank you.

              1 Reply Last reply Reply Quote 0
              • MathIzzzFunM Offline
                MathIzzzFun
                last edited by

                Bokwa:
                Hi,


                Can someone please help me to solve these two questions?

                Q1: The ratio of Sasi's age to his father's age is 2:7 at present. In twelve years' time, the ratio will become 2:5. Find Sasi's present age.

                Q2: Ken and Clark went shopping. The ratio of money Ken had to what Clark had was 6:5. The amount each of them spent was in the ratio 3:2 respectively. Ken spent 1/4 of his money. What was the ratio of the amount Ken had left to the amount Clark had left?

                Thank you.
                Q1- age difference remains the same ... so equalize the difference in ratio parts

                at present, sasi's age : father's age = 2:7 --> 6u : 21u (difference = 15u)
                in 12 years' time, sasi's age : father's age = 2:5 --> 10u : 25u (difference = 15u)

                10u - 6u = 4u --> 12 years
                1u --> 3 years

                Sasi's present age --> 6 x 3 = 18 years old


                Q2.. Ken's spending : Clark's spending -> 3u : 2u
                Ken spent 1/4 of his money,
                so, At first, Ken's money : Clark's money -> 12u : 10u (ratio of 6:5)

                Money left, Ken : Clark --> 9u : 8u = 9 : 8

                cheers.

                1 Reply Last reply Reply Quote 0
                • E Offline
                  elishatan
                  last edited by

                  I need help! I don't know how to do this question.


                  http://i261.photobucket.com/albums/ii44/elishahy88/IMG_04051_zpsb7291b1a.jpg\">

                  1 Reply Last reply Reply Quote 0
                  • MathIzzzFunM Offline
                    MathIzzzFun
                    last edited by

                    elishatan:
                    I need help! I don't know how to do this question.


                    http://i261.photobucket.com/albums/ii44/elishahy88/IMG_04051_zpsb7291b1a.jpg\">
                    3/10 of A= = 2/5 of C
                    6/10 of A = 6/15 of C
                    A -> 10 units, shaded A -> 6 units, unshaded A -> 4 unuts
                    C-> 15 units, shaded C -> 6 units, unshaded C -> 9 units
                    shaded B -> 12 units (total shaded)
                    80% of B -> 12 units, B -> 15 units, unshaded B -> 3 units

                    can u continue from here?

                    cheers.

                    1 Reply Last reply Reply Quote 0
                    • E Offline
                      elishatan
                      last edited by

                      MathIzzzFun:
                      elishatan:

                      I need help! I don't know how to do this question.


                      http://i261.photobucket.com/albums/ii44/elishahy88/IMG_04051_zpsb7291b1a.jpg\">

                      3/10 of A= = 2/5 of C
                      6/10 of A = 6/15 of C
                      A -> 10 units, shaded A -> 6 units, unshaded A -> 4 unuts
                      C-> 15 units, shaded C -> 6 units, unshaded C -> 9 units
                      shaded B -> 12 units (total shaded)
                      80% of B -> 12 units, B -> 15 units, unshaded B -> 3 units

                      can u continue from here?

                      cheers.

                      Is it 10 + 15 + 15 - 12 = 28 (units that whole figure has)
                      Shaded: 6 + 6 = 12

                      Answer: 16/28

                      Is this correct?

                      1 Reply Last reply Reply Quote 0
                      • MathIzzzFunM Offline
                        MathIzzzFun
                        last edited by

                        elishatan:
                        MathIzzzFun:

                        [quote=\"elishatan\"]I need help! I don't know how to do this question.


                        http://i261.photobucket.com/albums/ii44/elishahy88/IMG_04051_zpsb7291b1a.jpg\">

                        3/10 of A= = 2/5 of C
                        6/10 of A = 6/15 of C
                        A -> 10 units, shaded A -> 6 units, unshaded A -> 4 unuts
                        C-> 15 units, shaded C -> 6 units, unshaded C -> 9 units
                        shaded B -> 12 units (total shaded)
                        80% of B -> 12 units, B -> 15 units, unshaded B -> 3 units

                        can u continue from here?

                        cheers.

                        Is it 10 + 15 + 15 - 12 = 28 (units that whole figure has)
                        Shaded: 6 + 6 = 12

                        Answer: 16/28

                        Is this correct?[/quote]yes... 4/7 in simplest form

                        cheers.

                        1 Reply Last reply Reply Quote 0

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