Tutor MathsGuru: Ask me for your burning Maths questions!

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MathIzzzFun:

VivianChan:

Hi pls help


Ali left town A and travelled towards town B at speed of 90km/h.
45min later, Muthu left town B and travelled town A at speed of 120km/h.
Town X was halfway between town A and town B. Ali passed town X half an hour after Muthu had passed town X. Both speeds did not change throughout the journey. If Muthu reached town A at 2.45pm, at what time did Ali leave town A?

Thanks!

Time taken by Ali to travel from A to X = 4 x 75 min = 5h
Total time taken by Ali to travel fro A to X = 10h
10h before 2.45pm --> 4.45am
Ali left at 4.45am

Hi, i'm new here and happen to see this question being posted.

My solution is: We should be finding time taken by Muthu to travel from B to A= 2x3u=450minutes=7.5 hrs

Hence, time Muthu left Town B =7.5hrs before 2.45pm ( being the time Muthu reached town A) =7.15am

Given that Muthu left Town B 45minutes after Ali left Town A, hence time Ali left Town A =6.30am ( 45 minutes before 7.15am )

Please feel free to correct me if am wrong. Thanks a lot!


cheers.

[Tancel]

My earlier posting came out wrongly. Sorry! Here's the amended version.


Hi, i'm new here and happen to see this question being posted.

My solution is: We should be finding time taken by Muthu to travel from B to A= 2x3u=450minutes=7.5 hrs

Hence, time Muthu left Town B =7.5hrs before 2.45pm ( being the time Muthu reached town A) =7.15am

Given that Muthu left Town B 45minutes after Ali left Town A, hence time Ali left Town A =6.30am ( 45 minutes before 7.15am )

Please comment if am wrong. Thanks!

[MathIzzzFun]

Tancel:

My earlier posting came out wrongly. Sorry! Here's the amended version.


Hi, i'm new here and happen to see this question being posted.

My solution is: We should be finding time taken by Muthu to travel from B to A= 2x3u=450minutes=7.5 hrs

Hence, time Muthu left Town B =7.5hrs before 2.45pm ( being the time Muthu reached town A) =7.15am

Given that Muthu left Town B 45minutes after Ali left Town A, hence time Ali left Town A =6.30am ( 45 minutes before 7.15am )

Please comment if am wrong. Thanks!

I have misread as Ali reached at 2. 45pm.

Thanks for highlighting the error, your working is correct - Ali left at 6. 30am

cheers.

[Bokwa]

Hi MathsGuru,


Please help my child with these questions.

Q: There were a total of 930 boys and girls at a carnival. After 4/5 of the boys and 3/4 of the girls left there were 120 more girls than boys that remained. How many boys were at the carnival at first?

Q: 94 children took part on a lucky draw and 32 of them won a prize. 1/8 of the girls and 4/5 of the boys won a prize. How many girls did not win a prize.

Please help…thanks alot.

[MathIzzzFun]

Bokwa:

Hi MathsGuru,


Please help my child with these questions.

Q: There were a total of 930 boys and girls at a carnival. After 4/5 of the boys and 3/4 of the girls left there were 120 more girls than boys that remained. How many boys were at the carnival at first?

Q: 94 children took part on a lucky draw and 32 of them won a prize. 1/8 of the girls and 4/5 of the boys won a prize. How many girls did not win a prize.

Please help....thanks alot.

Firstly, I m not mathsguru ...mathsguru is the user who started this thread.


Q1.
Number of boys remaining (1/5) --> 1 unit --------- total number of boys --> 5 units

Number of girls remaining (1/4) --> 1 unit + 120 ----- total number of girls --> 4 units + 480

Total number of boys and girls
= 9 units + 480 --> 930
1 unit --> 50

Total number of boys at first --> 5 x 50 = 250

Q2.
1/8 girls + 4/5 boys --> 32
4/32 girls + 4/5 boys --> 32
1/32 girls + 1/5 boys --> 8

32/32 girls + 5/5 boys --> 94
27/32 girls + (5/32 girls + 5/5 boys) --> 94
27/32 girls --> 94 - 5 x 8 = 54
1/32 girls --> 2 ------- total number of girls --> 64
Number of girls who did not win any prize = 7/8 x 64 = 56

cheers.

[Bokwa]

Hi,


Can someone please help me to solve these two questions?

Q1: The ratio of Sasi’s age to his father’s age is 2:7 at present. In twelve years’ time, the ratio will become 2:5. Find Sasi’s present age.

Q2: Ken and Clark went shopping. The ratio of money Ken had to what Clark had was 6:5. The amount each of them spent was in the ratio 3:2 respectively. Ken spent 1/4 of his money. What was the ratio of the amount Ken had left to the amount Clark had left?

Thank you.

[MathIzzzFun]

Bokwa:

Hi,


Can someone please help me to solve these two questions?

Q1: The ratio of Sasi's age to his father's age is 2:7 at present. In twelve years' time, the ratio will become 2:5. Find Sasi's present age.

Q2: Ken and Clark went shopping. The ratio of money Ken had to what Clark had was 6:5. The amount each of them spent was in the ratio 3:2 respectively. Ken spent 1/4 of his money. What was the ratio of the amount Ken had left to the amount Clark had left?

Thank you.

Q1- age difference remains the same ... so equalize the difference in ratio parts

at present, sasi's age : father's age = 2:7 --> 6u : 21u (difference = 15u)
in 12 years' time, sasi's age : father's age = 2:5 --> 10u : 25u (difference = 15u)

10u - 6u = 4u --> 12 years
1u --> 3 years

Sasi's present age --> 6 x 3 = 18 years old


Q2.. Ken's spending : Clark's spending -> 3u : 2u
Ken spent 1/4 of his money,
so, At first, Ken's money : Clark's money -> 12u : 10u (ratio of 6:5)

Money left, Ken : Clark --> 9u : 8u = 9 : 8

cheers.

[elishatan]

I need help! I don't know how to do this question.


http://i261.photobucket.com/albums/ii44/elishahy88/IMG_04051_zpsb7291b1a.jpg\">

[MathIzzzFun]

elishatan:

I need help! I don't know how to do this question.


http://i261.photobucket.com/albums/ii44/elishahy88/IMG_04051_zpsb7291b1a.jpg\">

3/10 of A= = 2/5 of C
6/10 of A = 6/15 of C
A -> 10 units, shaded A -> 6 units, unshaded A -> 4 unuts
C-> 15 units, shaded C -> 6 units, unshaded C -> 9 units
shaded B -> 12 units (total shaded)
80% of B -> 12 units, B -> 15 units, unshaded B -> 3 units

can u continue from here?

cheers.

[elishatan]

MathIzzzFun:

elishatan:

I need help! I don't know how to do this question.


http://i261.photobucket.com/albums/ii44/elishahy88/IMG_04051_zpsb7291b1a.jpg\">

3/10 of A= = 2/5 of C
6/10 of A = 6/15 of C
A -> 10 units, shaded A -> 6 units, unshaded A -> 4 unuts
C-> 15 units, shaded C -> 6 units, unshaded C -> 9 units
shaded B -> 12 units (total shaded)
80% of B -> 12 units, B -> 15 units, unshaded B -> 3 units

can u continue from here?

cheers.

Is it 10 + 15 + 15 - 12 = 28 (units that whole figure has)
Shaded: 6 + 6 = 12

Answer: 16/28

Is this correct?