Q&A - P5 Math

[MathIzzzFun]

Oracle:

Thanks MathIzzzFun,


I got the first one but not quite sure about the second question, the part where you illustrated:

Adding all...
Jane + Kelly + Linda --> (120+80+160)/2 = 180
Linda --> 180-120 = 60
Jane --> 180 - 80 = 100
Kelly --> 180 - 160 = 20

Thing is, wouldn't there be duplication if we added them all?

And I have difficulty understanding the rational behind dividing the total by 2.

Please could you enlighten me further?

Thank you very much.

http://i47.tinypic.com/357frqx.png\">

Wishing all a Happy Chinese New Year !!

cheers.

[Oracle]

Haha, got it. Thanks very much!


Here’s wishing you and all the others on this thread a joyful & peaceful year ahead.

[Jamesbond]

http://i47.tinypic.com/25tz59k.jpg\">


Pl help.... :nailbite:

[MathIzzzFun]

Jamesbond:

http://i47.tinypic.com/25tz59k.jpg\">


Pl help.... :nailbite:

wow...still working on maths on CNY eve ? ... have a kit-kat...

4-3 =1
since there are 8 divisions from 3 to 4,
each division = 1/8 = 0.125
3 divisions = 3 x 0.125 = 0.375
3 + 0.375 = 3.375

Have a break !

Happy Chinese New Year to ALL KSPians !

cheers.

[Jamesbond]

MathIzzzFun:

Jamesbond:

http://i47.tinypic.com/25tz59k.jpg\">


Pl help.... :nailbite:

wow...still working on maths on CNY eve ? ... have a kit-kat...

4-3 =1
since there are 8 divisions from 3 to 4,
each division = 1/8 = 0.125
3 divisions = 3 x 0.125 = 0.375
3 + 0.375 = 3.375

Have a break !

Happy Chinese New Year to ALL KSPians !

cheers.

Thx for ur fast reply....Poor me... CA1 maths on 19th....

[Jamesbond]

Jar Y has 22 more sweets than Jar Z and Jar Z has 16 more sweets than Jar X. The total number of sweets in Jars Y and Z is 5 times the number of sweets in Jar X.

a) How many sweets are there altogether?
b) How many sweets should be transferred from Jar Y to the other two jars so that there is an equal number of sweets in all three jars?

Pl help..... :rotflmao:

[MathIzzzFun]

Jamesbond:

Jar Y has 22 more sweets than Jar Z and Jar Z has 16 more sweets than Jar X. The total number of sweets in Jars Y and Z is 5 times the number of sweets in Jar X.

a) How many sweets are there altogether?
b) How many sweets should be transferred from Jar Y to the other two jars so that there is an equal number of sweets in all three jars?

Pl help..... :rotflmao:

Jar X --> 1 unit
Jar Z --> 1 unit + 16
Jar Y --> 1 unit + 16 + 22 = 1 unit + 38

Jar Y + Jar Z --> 2 units + 54 = 5 units
3 units --> 54, 1 unit --> 18

Jar X --> 18
Jar Z --> 34
Jar Y --> 56
Total --> 108

108 / 3 = 36
Number transferred from Jar Y to
Jar X --> 36 - 18 = 18
Jar Z --> 36 - 34 = 2

cheers.

[Jamesbond]

MathIzzzFun:

Jamesbond:

Jar Y has 22 more sweets than Jar Z and Jar Z has 16 more sweets than Jar X. The total number of sweets in Jars Y and Z is 5 times the number of sweets in Jar X.

a) How many sweets are there altogether?
b) How many sweets should be transferred from Jar Y to the other two jars so that there is an equal number of sweets in all three jars?

Pl help..... :rotflmao:

Jar X --> 1 unit
Jar Z --> 1 unit + 16
Jar Y --> 1 unit + 16 + 22 = 1 unit + 38

Jar Y + Jar Z --> 2 units + 54 = 5 units
3 units --> 54, 1 unit --> 18

Jar X --> 18
Jar Z --> 34
Jar Y --> 56
Total --> 108

108 / 3 = 36
Number transferred from Jar Y to
Jar X --> 36 - 18 = 18
Jar Z --> 36 - 34 = 2

cheers.

:salute: :thankyou:

[Jamesbond]

Cali's spent $1485 on 9 identical handbags and 3 identical pairs of shoes. Sherlyn spent $ 867 less than Calise on 2 such handbags and 6 such pairs of shoes.what was the total cost of 3 such handbags and 2 such pairs of shoes?

Pl help :?

[MathIzzzFun]

Jamesbond:

Cali's spent $1485 on 9 identical handbags and 3 identical pairs of shoes. Sherlyn spent $ 867 less than Calise on 2 such handbags and 6 such pairs of shoes.what was the total cost of 3 such handbags and 2 such pairs of shoes?

Pl help :?

Elimination method :

9 handbags + 3 pairs of shoes --> $1485 -- (1)
2 handbags + 6 pairs of shoes --> $ 1485 - $ 867 = $618 -- (2)

(1)x2 --- 18 handbags + 6 pairs of shoes --> $ 2970 -- (3)
(3)-(2) -- 16 handbags --> $ 2970 - $ 618 = $ 2352
1 handbag --> $ 147
from (1) -- 1 pair of shoes --> $(1485-9 x 147)/3 = $ 54

3 handbags + 2 pairs of shoes --> 3 x $147 + 2 x $ 54 = $ 549

grouping method:

9 handbags + 3 pairs of shoes --> $1485
divide by 3 -- 3 handbags + 1 pair of shoes --> $495 --- (1)

2 handbags + 6 pairs of shoes --> $ 1485 - $ 867 = $618
divide by 2 -- 1 handbag + 3 pairs of shoes --> $309 -- (2)

(1)+(2) -- 4 handbags + 4 pairs of shoes --> $ 495 + $ 309= $ 804
divide by 4 -- 1 handbag + 1 pair of shoes = $ 201

from (2) -- 2 pairs of shoes --> $ 309 - $ 201 = $ 108
1 pair of shoes --> $ 54

3 handbags + 2 pairs of shoes
= $ 495 (from (1)) + $ 54 (1 pair of shoes)
= $ 549


cheers.