Q&A - P4 Math

[kgaihc]

I have a way to solve the following question, but too long-winded. I believe there should a better method. Can someone help? Thanks.


Ali had four times as many storybooks as Gopal. Maggie had 336 fewer storybooks than Ali. The three children had 780 storybooks. How many storybooks did the two boys have altogether?

[BigDevil]

http://i49.tinypic.com/34qmgqu.jpg\">


So what's your way of solving this question?

[kgaihc]

BigDevil:

http://i49.tinypic.com/34qmgqu.jpg\">


So what's your way of solving this question?

Wow.. you make it looks so simple.
My method:
1. Divide the 5 block into 10 smaller blocks (10u).
2. Put 1u to Ali and 1u to Maggie. So, Ali now has 9u.
3. Then, 780-336=444.
4. Then, 444/2= 222.
5. So, Ali = 9u = 222+336=558.
6. So, u = 558/9 = 62.
7. 2 boys = 10u = 10 x 62 = 620.

paiseh..

[BigDevil]

Don't have to be paiseh.


We are all learning so that we can help our child.

[Bunny27]

BigDevil:

Don't have to be paiseh.


We are all learning so that we can help our child.

Hi,
Can someone kindly help me on the question ?

1. Chenli has a collection of coins. When she put the coins in piles of fours or fives, she has 2 coins left over each time. When she puts them in piles of 6s, she has no coins left over. What is the smallest number of coins that Chenli can have?

Thanks!

[Funz]

Need help with the following.


The name STEVEN is written over and over again like this
STEVENSTEVENSTEVENSTEVEN…

How many times will the letter E appear up to the 999th position?

Do I take 999/6, multiply by 2 since E appears twice then plus 1 as there is a remainder meaning E appears 1 more time?

[Poppet]

Jeremy has some sweets.If he puts 4 sweets in each bag,there will be 15 sweets left over.He puts 6 sweets in each bag,there will be 3 sweets left over.How many sweets does Jeremy have?


Can someone help? :xedfingers:

[Poppet]

Hi there,


Anyone can help me on following 5 very challenging questions, thanks in advance :boogie:

Qn 1. Mary had 350 more trading cards than John. After each of them received 50 trading cards from their cousin, Mary had three times as many trading cards as John. How many trading cards did John have at first?

Qn 2. Wendy bought an equal number of apples and oranges for a party. The apples were sold at 4 for $3 and the oranges were sold at 3 for $2. She paid $5 more for the apples. How many fruits did she buy altogether?

Qn 3. Bala opened up a book and added the page numbers of the two facing pages. He found the answer to be 119. He then decided to multiply the page numbers of these two pages. What is the product of the two page numbers?

Qn 4. Ali had $190 more than Baba at first. After Baba had spent $50, Ali had 4 times as much money as Baba had left. How much did Ali have at first?

Qn 5. Charlie and Mr Brown had the same number of buttons. If Charlie gives 500 buttons to Mr Brown, Mr Brown would have 6 times as many buttons as Charlie. How many buttons did Charlie have at first?

[Poppet]

Appreciate if anyone can help me in the following two questions. :?


Qn1. Amos and Lynn have 120 pears altogether. After Amos gave 17 pears to Lynn, they each have the same number of pears.
(a) How many pears do they each have at the end?
(b) How many pears does Amos have at first?


Qn2. Chandra and Tricia had the same amount of money at first. Tricia then spent $14 and Chandra received $20 from his parents. In the end, Chandra had twice as much money as Tricia. How much money did Chandra have at first?

[Funz]

quekcc:

Funz:

Need help with the following.


The name STEVEN is written over and over again like this
STEVENSTEVENSTEVENSTEVEN.......

How many times will the letter E appear up to the 999th position?

Do I take 999/6, multiply by 2 since E appears twice then plus 1 as there is a remainder meaning E appears 1 more time?

900 = 150 x 6
90 = 15 x 6

999 = 150 x 6 + 15 x 6 + 1 x 6 + 3

So there are 150 + 15 + 1 \"STEVEN\", and that will take up 996 letters, the next 3 letters are \"STE\".

There will be 166 x 2 + 1 = 333 \"E\".

Thanks! Got the same answer. I did it this way instead.

999/6 = 166 R3

166*2 = 332

332+1 since there is another E from the remainder of 3. So answer is 333