Q&A - P4 Math

[Poppet]

Jeremy has some sweets.If he puts 4 sweets in each bag,there will be 15 sweets left over.He puts 6 sweets in each bag,there will be 3 sweets left over.How many sweets does Jeremy have?


Can someone help? :xedfingers:

[Poppet]

Hi there,


Anyone can help me on following 5 very challenging questions, thanks in advance :boogie:

Qn 1. Mary had 350 more trading cards than John. After each of them received 50 trading cards from their cousin, Mary had three times as many trading cards as John. How many trading cards did John have at first?

Qn 2. Wendy bought an equal number of apples and oranges for a party. The apples were sold at 4 for $3 and the oranges were sold at 3 for $2. She paid $5 more for the apples. How many fruits did she buy altogether?

Qn 3. Bala opened up a book and added the page numbers of the two facing pages. He found the answer to be 119. He then decided to multiply the page numbers of these two pages. What is the product of the two page numbers?

Qn 4. Ali had $190 more than Baba at first. After Baba had spent $50, Ali had 4 times as much money as Baba had left. How much did Ali have at first?

Qn 5. Charlie and Mr Brown had the same number of buttons. If Charlie gives 500 buttons to Mr Brown, Mr Brown would have 6 times as many buttons as Charlie. How many buttons did Charlie have at first?

[Poppet]

Appreciate if anyone can help me in the following two questions. :?


Qn1. Amos and Lynn have 120 pears altogether. After Amos gave 17 pears to Lynn, they each have the same number of pears.
(a) How many pears do they each have at the end?
(b) How many pears does Amos have at first?


Qn2. Chandra and Tricia had the same amount of money at first. Tricia then spent $14 and Chandra received $20 from his parents. In the end, Chandra had twice as much money as Tricia. How much money did Chandra have at first?

[Funz]

quekcc:

Funz:

Need help with the following.


The name STEVEN is written over and over again like this
STEVENSTEVENSTEVENSTEVEN.......

How many times will the letter E appear up to the 999th position?

Do I take 999/6, multiply by 2 since E appears twice then plus 1 as there is a remainder meaning E appears 1 more time?

900 = 150 x 6
90 = 15 x 6

999 = 150 x 6 + 15 x 6 + 1 x 6 + 3

So there are 150 + 15 + 1 \"STEVEN\", and that will take up 996 letters, the next 3 letters are \"STE\".

There will be 166 x 2 + 1 = 333 \"E\".

Thanks! Got the same answer. I did it this way instead.

999/6 = 166 R3

166*2 = 332

332+1 since there is another E from the remainder of 3. So answer is 333

[gonzo]

Multiples of 4: 4,8,12,16,20

Add 15: 19, 23, 27, 31, 35
Multiples of 6: 6,12,18,24,30
Add 3: 9,15, 21,27,33

Common number is 27.

[BigDevil]

quekcc:

Bunny27:

Hi,
Can someone kindly help me on the question ?

1. Chenli has a collection of coins. When she put the coins in piles of fours or fives, she has 2 coins left over each time. When she puts them in piles of 6s, she has no coins left over. What is the smallest number of coins that Chenli can have?

Thanks!

1. The number n is a multiple of 6.
2. The number (n + 2) is a multiple of 4 and 5, i.e. it must end with 0.
3. implies that n must end with 8.

Smallest multiple of 6 ended with 8 will be 18.

Ans: 18 coins.

18 coins in piles of 5 will have 3 coins left over, not 2.

Condition 2 should be (n - 2) is multiple of both 4 & 5, so n must end with \"2\".

Answer: 42 coins

[cathycho]

BigDevil,


Condition 2 should be (n - 2) is multiple of both 4 & 5, so n must end with "2". Why must end with 2?

Why not n+2 since 2 coins left over each time?

[cathycho]

How to do this question?


Mr Tong bought some candy bars. If shard by 3 children, there was no remainder left, but when shared the candy bars by 5 children, there were 3 candy left over. What is the min no. Of candy bars Mr To g bought?

[MathIzzzFun]

cathycho:

How to do this question?


Mr Tong bought some candy bars. If shard by 3 children, there was no remainder left, but when shared the candy bars by 5 children, there were 3 candy left over. What is the min no. Of candy bars Mr To g bought?

the \"standard\" approach is the list the multiple of 3 and multiple of 5+3 and look for the smallest number that matches.
multiples of 3 --> 3, 6, 9, 12, 15, 18, 21....
multiples of 5 + 3 --> 8, 13, 18, 23....

alternate approach:
If we remove 3 candy bars, the remaining number will be divisible by 3 & 5.
The smallest number that is divisible by 3 & 5 is 15.
The number of candy bars = 15 + 3 =18

cheers.

[cathycho]

MathIzzzFun,


Thanks for ur help. :lovesite: