Q&A - P4 Math

[cathycho]

How to do this question?


Mr Tong bought some candy bars. If shard by 3 children, there was no remainder left, but when shared the candy bars by 5 children, there were 3 candy left over. What is the min no. Of candy bars Mr To g bought?

[MathIzzzFun]

cathycho:

How to do this question?


Mr Tong bought some candy bars. If shard by 3 children, there was no remainder left, but when shared the candy bars by 5 children, there were 3 candy left over. What is the min no. Of candy bars Mr To g bought?

the \"standard\" approach is the list the multiple of 3 and multiple of 5+3 and look for the smallest number that matches.
multiples of 3 --> 3, 6, 9, 12, 15, 18, 21....
multiples of 5 + 3 --> 8, 13, 18, 23....

alternate approach:
If we remove 3 candy bars, the remaining number will be divisible by 3 & 5.
The smallest number that is divisible by 3 & 5 is 15.
The number of candy bars = 15 + 3 =18

cheers.

[cathycho]

MathIzzzFun,


Thanks for ur help. :lovesite:

[BigDevil]

cathycho:

BigDevil,


Condition 2 should be (n - 2) is multiple of both 4 & 5, so n must end with \"2\". Why must end with 2?

Why not n+2 since 2 coins left over each time?

Let's recap what is said in the question...
When she put the coins in piles of fours or fives, she has 2 coins left over each time.

When the number n is divided by 4 or 5, there is a remainder of 2.
If we take 2 away from n, then the end number is divisible by 4 and 5.
Thus, (n - 2) is multiple of both 4 and 5, not (n + 2).

For (n -2) to be divisible by 5, it must end with 5 or 0.
But any number ending with 5 cannot be a multiple of 4,
so (n -2) must end with 0. Meaning n must end with 2.

HTH.

[BigDevil]

Poppet:

Jeremy has some sweets.If he puts 4 sweets in each bag,there will be 15 sweets left over.He puts 6 sweets in each bag,there will be 3 sweets left over.How many sweets does Jeremy have?


Can someone help? :xedfingers:

gonzo:

Multiples of 4: 4,8,12,16,20
Add 15: 19, 23, 27, 31, 35
Multiples of 6: 6,12,18,24,30
Add 3: 9,15, 21,27,33

Common number is 27.

27 is certainly a valid answer to the question, but what troubled me is that if Jeremy still has 15 sweets left over, why didn't he keep filling more bags of 4 till he has only 3 left?

So I'm tempted to think that he has only a fixed number of bags.

Filling the bags with 4 sweets, he has 15 left.
Filling the bags with 6 sweets, he has 3 left.
So to put in 2 extra sweets into each bag, he used up 12 additional sweets.
Therefore, he has 12/2 = 6 bags.
Total number of sweets: (6 x 6) + 3 = 39

[cathycho]

BigDevil:

cathycho:

BigDevil,


Condition 2 should be (n - 2) is multiple of both 4 & 5, so n must end with \"2\". Why must end with 2?

Why not n+2 since 2 coins left over each time?

Let's recap what is said in the question...
When she put the coins in piles of fours or fives, she has 2 coins left over each time.

When the number n is divided by 4 or 5, there is a remainder of 2.
If we take 2 away from n, then the end number is divisible by 4 and 5.
Thus, (n - 2) is multiple of both 4 and 5, not (n + 2).

For (n -2) to be divisible by 5, it must end with 5 or 0.
But any number ending with 5 cannot be a multiple of 4,
so (n -2) must end with 0. Meaning n must end with 2.

HTH.

Finally, I understand! Thks for ur explanation..

[MathIzzzFun]

BigDevil:

Poppet:

Jeremy has some sweets.If he puts 4 sweets in each bag,there will be 15 sweets left over.He puts 6 sweets in each bag,there will be 3 sweets left over.How many sweets does Jeremy have?


Can someone help? :xedfingers:

gonzo:

Multiples of 4: 4,8,12,16,20
Add 15: 19, 23, 27, 31, 35
Multiples of 6: 6,12,18,24,30
Add 3: 9,15, 21,27,33

Common number is 27.

27 is certainly a valid answer to the question, but what troubled me is that if Jeremy still has 15 sweets left over, why didn't he keep filling more bags of 4 till he has only 3 left?

So I'm tempted to think that he has only a fixed number of bags.

Filling the bags with 4 sweets, he has 15 left.
Filling the bags with 6 sweets, he has 3 left.
So to put in 2 extra sweets into each bag, he used up 12 additional sweets.
Therefore, he has 12/2 = 6 bags.
Total number of sweets: (6 x 6) + 3 = 39

I agree with you. A similar question was discussed quite some time ago- http://www.kiasuparents.com/kiasu/forum/viewtopic.php?f=66&t=149&hilit=lim+has+some+sweets&start=1030.

cheers.

[BigDevil]

Thanks, MathIzzzFun.


Oh my...that was discussed as a P3 question??
Seems a bit too tough for P3...don't think my P4 DD would know how to solve this!

[BigDevil]

Aside from the above question, Poppet still has several questions which I merged into this thread:

http://www.kiasuparents.com/kiasu/forum/viewtopic.php?f=67&t=25121&p=957352#p957352
http://www.kiasuparents.com/kiasu/forum/viewtopic.php?f=67&t=25121&p=957354#p957354

Experts, please help!

[BigDevil]

Poppet:

Hi there,


Anyone can help me on following 5 very challenging questions, thanks in advance :boogie:

Qn 1. Mary had 350 more trading cards than John. After each of them received 50 trading cards from their cousin, Mary had three times as many trading cards as John. How many trading cards did John have at first?

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