Q&A - P5 Math

[Jamesbond]

Edmund sold cups and bowls for parties. The ratio of the price of a cup to the price of a bowl is 2:3. The price of the cup was $0.50 less than the price of the bowl. In january, Edmund sold 3/5 of the items and collected $297 from the sales. 1/4 of the items sold in january were cups. Find the total no of items left after january?

pl help…

[tianzhu]

Jamesbond:

Edmund sold cups and bowls for parties. The ratio of the price of a cup to the price of a bowl is 2:3. The price of the cup was $0.50 less than the price of the bowl. In january, Edmund sold 3/5 of the items and collected $297 from the sales. 1/4 of the items sold in january were cups. Find the total no of items left after january?

pl help....

Hi

The ratio of the price of a cup to the price of a bowl is 2:3.

Cup:Bowl ----- 2:3

The price of the cup was $0.50 less than the price of the bowl.

Cup -----$1
Bowl ----- $1.5

Now you may work in dollars or change to cents. You may also use ”Number*Value” or “Grouping”

Edmund sold 3/5 of the items and collected $297 from the sales. 1/4 of the items sold in January were cups.

A common multiple of 3 and 4 is 12.

Cups ------ 3 u
Bowls ----- 9 u

3u*1 + 9u*1.5 ------ 297

1u ------ 18

Number of cups ------ 54(3*18)
Number of bowls ----- 162(9*18)

3/5 ------- 216 (54+162)

2/5 ------ 144 (Number of items left after January)

Best wishes

[Jamesbond]

tianzhu:

favianboy:

Anna, Bee Bee and Cari shared the cost of a gift for their friend. 2/5 of Cari's share was equal to 1/2 of Bee Bee's and Anna's share. 1/3 of Bee Bee share was equal to 1/3 of Cari and Anna share. If Anna paid $40 less than Cari, how much did the gift cost


Pls help

Hi

2/5 of Cari's share was equal to 1/2 of Bee Bee's and Anna's share.
Carl ------ 15 units
Bee Bee ----- 12 units

1/3 of Bee Bee’s share was equal to 1/3 of Cari and Anna’sshare.
1/3 of Bee Bee’s share ----- 4 units
1/3 of Cari and Anna’s share ----- 4 units

Anna paid $40 less than Cari
Carl paid 3 units
Anna paid 1 unit

2 units ----- 40
1 unit ------ 20

Cost of gift ------ 39*20 ------- 780

Best wishes

Hi Tianzhu, Can u pl clear my doubt. Those 12 units are for bee bee alone or for bee bee and anna together?

[Jamesbond]

tianzhu:

Oracle:

Thanks Tianzhu but i just need to understand why Wee Teck is given 3 units because the question says Robert paid 1/3 of the amount paid by Henry AND Wee Teck. By using 3 units to represent Wee Teck, we would be assuming that both Wee Teck and Henry paid equal amount which might mot be the case.


Your thoughts?

Hi

Please read your PM.

Best wishes

[tianzhu]

Jamesbond:

Hi Tianzhu, Can u pl clear my doubt. Those 12 units are for bee bee alone or for bee bee and anna together?

Hi Jamesbond

You are correct, it's for Bee Bee and Anna altogether.

I am sorry for the error.

Best wishes

[Jamesbond]

tianzhu:

Jamesbond:

Hi Tianzhu, Can u pl clear my doubt. Those 12 units are for bee bee alone or for bee bee and anna together?

Hi Jamesbond

You are correct, it's for Bee Bee and Anna altogether.

I am sorry for the error.

Best wishes

So is the answer 900? pl let me know. :nailbite:

[Jamesbond]

http://i46.tinypic.com/jgjyg0.jpg\">

Pl help...

[ChewingPencilLine]

Jamesbond:

http://i46.tinypic.com/jgjyg0.jpg\">

Pl help...

LOOK AT MATHIZZZFUN'S CORRECT ANSWER BELOW.

The drawing looks a bit odd... Why are there irregular unshaded patches?

Anyway, ignoring those, there are basically 3 shaded triangles within 3 rectangles (see attached picture below).

The top rectangle is 7cm by (7-3=4)cm.
Area = 7 x 4 = 28 cm square.
The bottom left rectangle is 3cm by (3+7=10)cm.
Area = 3 x 10 = 30 cm square
The last bottom right rectangle is 3cm by 5cm.
Area = 3 x 5 = 15 cm square

(If you have problem seeing why the rectangles are of the above sizes, feel free to ask.)

Therefore, to find the total area, find the area of the 3 triangles then sum them up!
1/2 x 28 = 14 cm square
1/2 x 30 = 15 cm square
1/2 x 15 = 7.5 cm square
14 + 15 + 7.5 = 36.5 cm square

http://i48.tinypic.com/dm79ec.png\">

[MathIzzzFun]

Jamesbond:

http://i46.tinypic.com/jgjyg0.jpg\">

Pl help...

http://i48.tinypic.com/x1loht.png\">

cheers.

[ChewingPencilLine]

MathIzzzFun:

Jamesbond:

http://i46.tinypic.com/jgjyg0.jpg\">

Pl help...

http://i48.tinypic.com/x1loht.png\">

cheers.

Ahh, I think my answer is slightly off because I presumed that the bottom right triangle is half of a 3cm by 5cm rectangle from looking at the diagram. Now that I think about it, that is not true (should be 2.8cm by 5cm, hmmm).

Thanks for submitting the right answer and catching me on my mistake ^_^.