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    Q&A - P5 Math

    Scheduled Pinned Locked Moved Primary 5
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    • J Offline
      Jamesbond
      last edited by

      A group of 24 children sold some tickets for a charity show. Each ticket was sold at $5. Each boy sold 5 tickets and each girl sold 3 tickets. The boys collected $40 more than the girls.

      a) How many girls were there in the group?
      b) How many tickets were sold altogether?

      TIA

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      • P Offline
        PapayaDad
        last edited by

        Assume 12B and 12G

        So Boys sold 60 tickets ; girls sold 36 tickets
        So boys get $300 ; girls get $180
        Boys get 120 more ; we need to reduce this to 40 only ie need to reduce 80

        If we reduce 1 boy ; we reduce five tickets ; which is reduce $25
        But there will be one more girl ; ie 3 more tickets ; which is $15 more.
        So the difference is reduce by $40

        So we need to reduce 2 boys from our initial assumption.


        Answer 10 boy 14 girls

        Check
        10B = 50 tickets = $250
        14G = 42 tickets = $210
        Correct, boys collected $40 more.
        There are 14 girls.
        Total tickets sold is 92

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        • C Offline
          ChewingPencilLine
          last edited by

          tianzhu:
          veraclari:

          HI SORRY shd be Jane's spending. . Fjanks for helping in e questions. . But girl asking me how to draw model too... really got me siah.. model me cannot. .. ha ha h


          Hi

          Good Morning.

          There are alternative ways to present the MD.I've shown two options.

          Hope your girl will find it useful.

          Best wishes

          http://farm9.staticflickr.com/8115/8607173179_2eb41f9ca3_z.jpg\">

          Just going to point out that you are assuming that they spent everything they brought. You might think this a moot point but I was confounded when I first read this question, ._.

          Cheers.

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          • V Offline
            veraclari
            last edited by

            Wow Thanks All for ur help! The model part is really killing me.. really appreciate the MD here which makes everything so clear.. now shd ask my girl to attempt e other MD for e first qn on pears and plums again as we re both clueless nd couldn't draw one that incorporated everything. . 😉

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            • J Offline
              Jamesbond
              last edited by

              PapayaDad:
              Assume 12B and 12G

              So Boys sold 60 tickets ; girls sold 36 tickets
              So boys get $300 ; girls get $180
              Boys get 120 more ; we need to reduce this to 40 only ie need to reduce 80

              If we reduce 1 boy ; we reduce five tickets ; which is reduce $25
              But there will be one more girl ; ie 3 more tickets ; which is $15 more.
              So the difference is reduce by $40

              So we need to reduce 2 boys from our initial assumption.


              Answer 10 boy 14 girls

              Check
              10B = 50 tickets = $250
              14G = 42 tickets = $210
              Correct, boys collected $40 more.
              There are 14 girls.
              Total tickets sold is 92
              :thankyou: PapayaDad.

              1 Reply Last reply Reply Quote 0
              • J Offline
                Jamesbond
                last edited by

                A box contained a number of 20 cent and 50 cent coins in the ratio 3:4. When ten 50 cent coins were taken out and replaced by 20 cent coins, the ratio became 7:5. Find the sum of money in the box at first?

                Pl help.

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                • MathIzzzFunM Offline
                  MathIzzzFun
                  last edited by

                  Jamesbond:
                  A box contained a number of 20 cent and 50 cent coins in the ratio 3:4. When ten 50 cent coins were taken out and replaced by 20 cent coins, the ratio became 7:5. Find the sum of money in the box at first?

                  Pl help.
                  possible approaches - cross-multiply/UP, units, MD.

                  Using units:

                  10 x $0.50 = 25 x $0.20
                  --> 10 fifty-cent coins were replaced by 25 twenty-cent coins

                  At first
                  number of 50c --> 20 units + 10
                  number of 20c (= 3/4 number of 50c) --> 15 units + 7.5

                  In the end,
                  number of 50c --> 20 units
                  number of 20c (=7/5 number of 50c) --> 28 units

                  since 25 twenty-cent coins were added, we have:

                  15 units + 7.5 + 25 = 28 units
                  1 unit --> 2.5

                  Sum of money in the box at first
                  = sum of money in the box in the end
                  = 20 x 2.5 x $0.50 + 28 x 2.5 x $0.20
                  = $39

                  cheers.

                  1 Reply Last reply Reply Quote 0
                  • S Offline
                    snowball
                    last edited by

                    4/7 of Ming’s mass is equal to 2/5 of Rob’s mass.

                    If Ming puts on 6 kg and Rob loses 12kg, the two men will have the same mass.
                    a) Draw a clearly labelled model to solve the problem.
                    b) What is Rob’s mass?

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                    • S Offline
                      snowball
                      last edited by

                      In January, Mrs Wong spent 2/5 of her salary on rent and $120 on parking fees.

                      She spent 1/4 of her remaining salary on food and $480 on shopping.
                      She saved the remaining $1896.
                      How much was Mrs Wong’s salary for January ?

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                      • M Offline
                        MathsOlympiadtrainer
                        last edited by

                        snowball:
                        In January, Mrs Wong spent 2/5 of her salary on rent and $120 on parking fees.

                        She spent 1/4 of her remaining salary on food and $480 on shopping.
                        She saved the remaining $1896.
                        How much was Mrs Wong's salary for January ?
                        This is a working backwards qn.
                        3/4 of her remaining salary-> 480+1896= 2376
                        4/4 of her remaining salary-> 2376/3 * 4= 3168

                        3/5 of her salary-> 3168+120 = 3288
                        5/5 of her salary-> 3288/3 * 5 = 5480

                        Hope that helps.

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