2012 PSLE Discussions and Strategy
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chl72:
Yes, clever!
Hi James,James Ang:
A good and rigorous practice for P5/P6 level students is imperative to prepare them well for PSLE later on, eg in the new Casco 5A book, page 340, Q. 59 shows a commonly tested question type on ratio topic. I estimate that at most, fewer than 1 in 3 PSLE students can solve this type of Maths question even though they have learnt it in school, from books or elsewhere.
Sandra had some red and pink beads in the ratio 3:2. After she bought another 9 red beads and 36 pink beads, the ratio became 6:7. How many beads did Sandra have altogether at first?
Is the answer 85?
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James Ang:
Yes, clever! :)[/quote]Hee... 过奖了！ :lol:
Hi James,chl72:
[quote=\"James Ang\"]A good and rigorous practice for P5/P6 level students is imperative to prepare them well for PSLE later on, eg in the new Casco 5A book, page 340, Q. 59 shows a commonly tested question type on ratio topic. I estimate that at most, fewer than 1 in 3 PSLE students can solve this type of Maths question even though they have learnt it in school, from books or elsewhere.
Sandra had some red and pink beads in the ratio 3:2. After she bought another 9 red beads and 36 pink beads, the ratio became 6:7. How many beads did Sandra have altogether at first?
Is the answer 85?
Can share some more questions that a PSLE 'taker' should/MUST know? -
chl72:
Hee... 过奖了！ :lol:
Yes, clever!James Ang:
[quote=\"chl72\"]
Hi James,
Is the answer 85?
Can share some more questions that a PSLE 'taker' should/MUST know?[/quote]Hi chl72,
Wow...care to share how you derived your answer?? Thanks. -
Hi, give a try
R : P
3 : 2
+9 +36
6 : 7
R 21u 63
P 12u 216
Diff 9u 153
1u 17
5u x 17 = 85 -
Tinkerbelle:
Hi chl72,
Hee... 过奖了！ :lol:chl72:
[quote=\"James Ang\"]
Yes, clever!
Can share some more questions that a PSLE 'taker' should/MUST know?
Wow...care to share how you derived your answer?? Thanks.[/quote]Actually, mine is a stupid and long winded method. Old already, can only think about simultaneous equations. :lol:
R : P
3 : 2
+9 : +36
---------------
6 : 7
-> 3U+9=6P -> 1/2U+3/2=1P
2U+36=7P
2U+36=7(1/2U+3/2)
7/2U-2U=36-21/2
1U=17
17*5=85 -
Brenda10:
Thanks Brenda. Planning to ask DD to try later. Hope she can solve it.Hi, give a try
R : P
3 : 2
+9 +36
6 : 7
R 21u 63
P 12u 216
Diff 9u 153
1u 17
5u x 17 = 85 -
chl72:
Hi chl72,
Actually, mine is a stupid and long winded method. Old already, can only think about simultaneous equations. :lol:
R : P
3 : 2
+9 : +36
---------------
6 : 7
-> 3U+9=6P -> 1/2U+3/2=1P
2U+36=7P
2U+36=7(1/2U+3/2)
7/2U-2U=36-21/2
1U=17
17*5=85
No long-winded & stupid way to solve maths questions....just different approaches.....as long as the child understands and can derive the answer. Thanks for sharing. :lol: -
Just got ds to try and he also managed to solve it.
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Time flies fast, 6A math already completed. Very soon will move into 6B.
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Brenda10:
Time flies fast, 6A math already completed. Very soon will move into 6B.
Impressive ! Do u mean textbook or home assessment ?
Must get ds to buck up socks liao.. :oops:
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