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    Q&A - P4 Math

    Scheduled Pinned Locked Moved Primary 4
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    • H Offline
      HAPPYH
      last edited by

      sokk:
      Hi,


      I've a question that goes like this-

      Each digit can be used only once.
      Arrange the digits 2,4,7,8 and 9 in these boxes so as to get the largest and smallest possible products.

      Largest product. : [ ][ ][ ] x [ ][ ] =
      Smallest product : [ ][ ][ ] x [ ][ ] =

      The answer is
      872 x 94 = 81968 ( for the largest product)
      489 x 27 = 13203. (for the smallest product)

      The answer said that the method is by \"guess and check\". So wouldn't the students have a number of combinations to try out ?
      Is there a more direct method in doing this kind of question rather than by guess and check ?


      Thanks for helping me answer my question šŸ™‚
      Does anyone know the easier method / olympiad method to solve the above question? Thank you in advance.

      1 Reply Last reply Reply Quote 0
      • Xiao HuX Offline
        Xiao Hu
        last edited by

        :
        Xiao Hu:

        Hi Tianzhu, MathIzzzFun,


        I have some questions on \"estimation\" that I hope you can help answer. I did a search with \"estimation\" but after going through 4 pages that don't have anything relating to my question, I decided to ask it here.

        The question did not say estimate at which digit or which value.
        Estimate 7281x39.
        I think of 2 possible way to estimate
        (1) ~7300 x 40
        (2) ~7000 x 40
        Mentally, it's so much easier and quicker to say (2) is a \"better\" estimation.

        Anothe example:
        Estimate 246 x 39
        (1) ~250x40
        (2) ~200 x 40

        What's the rule or rules to teach our children when it comes to estimating?

        TIA,
        Xiao Hu

        Hi

        Estimation is taught so that the children understand how to do approximation. Students will not be asked to provide estimate of say 246 x 39 without given the bounds. For eg. a better estimate for 246 x 39 is 240 x 40 but normally we will approximate it to 250x 40 (which will provide the upper bound).
        Usually, choices will be provided for estimate of product of two numbers, or the question will specifically state whether the answer/number is to be rounded to 10 or 100. Ffor eg. Jenny had twelve stamp books with same number of stamps in each book. The total number of stamps Jenny had was 3500 when rounded to the nearest 10. How many stamps did Jenny have ?

        cheers.

        Hi MathIzzzFun,
        Thanks for your reply. Really appreciate your comments and giving an example of typical questions set. Very helpful!
        I think the questions given to him was a good exercise on estimation! A real life situation where you have to decide how best to estimate.
        Guess you are right, in exams, questions would probably state the boundaries.

        Thanks,
        Xiao Hu.

        1 Reply Last reply Reply Quote 0
        • C Offline
          chloecube
          last edited by

          found this in today Straits Time:


          There were 255 balls in Box A, B and C. 36 balls were transferred from A to B, and 19 balls ere transferred from B to C. as a result, the number of balls in each box is the same. how many balls were in Box B at first.

          Ans is 68.

          tried but cant get the correct answer.

          anyone cares to try?

          1 Reply Last reply Reply Quote 0
          • T Offline
            tianzhu
            last edited by

            chloecube:
            found this in today Straits Time:


            There were 255 balls in Box A, B and C. 36 balls were transferred from A to B, and 19 balls ere transferred from B to C. as a result, the number of balls in each box is the same. how many balls were in Box B at first.
            Hi

            Wow,Maths from the news.

            You may draw some pictorial aids to show the transfer of balls.

            The important point to note is that the total number of balls remains the same (255) before and after.

            In the end, the number of balls in A, B and C is the same.

            255/3 ----- 85 (number of balls in each box)

            Consider box B.

            36 balls in and 19 balls out

            Hence 85 – 36 +19 ------ 68

            Best wishes

            1 Reply Last reply Reply Quote 0
            • C Offline
              chloecube
              last edited by

              tianzhu:
              chloecube:

              found this in today Straits Time:


              There were 255 balls in Box A, B and C. 36 balls were transferred from A to B, and 19 balls ere transferred from B to C. as a result, the number of balls in each box is the same. how many balls were in Box B at first.

              Hi

              Wow,Maths from the news.

              You may draw some pictorial aids to show the transfer of balls.

              The important point to note is that the total number of balls remains the same (255) before and after.

              In the end, the number of balls in A, B and C is the same.

              255/3 ----- 85 (number of balls in each box)

              Consider box B.

              36 balls in and 19 balls out

              Hence 85 – 36 +19 ------ 68

              Best wishes

              Thks Tianzhu,

              the article is abt the stress that kids in Singapore are facing now, they then give a few examples of the Math question that our P2 and P4 are getting.
              after reading the article, i feel for the children, as quoted by one of the parent: \"the kid is learning how to cycle and juggle at the same time\"
              i wish something can be done to lessen their work load. Children shld have a beautiful memories of childhood and not buried in books all day long.

              if not for the help i got here, i doubt i ever solved those question

              1 Reply Last reply Reply Quote 0
              • C Offline
                Champion
                last edited by

                chloecube:

                Thks Tianzhu,

                the article is abt the stress that kids in Singapore are facing now, they then give a few examples of the Math question that our P2 and P4 are getting.
                after reading the article, i feel for the children, as quoted by one of the parent: \"the kid is learning how to cycle and juggle at the same time\"
                i wish something can be done to lessen their work load. Children shld have a beautiful memories of childhood and not buried in books all day long.

                if not for the help i got here, i doubt i ever solved those question
                Good Morning chloecube & Tianzhu :grphug:
                Totally agree with chloecube; I have learnt and am still learning about Maths. Am so thankful that I can tips from this P4 Maths thread :salute: :salute:

                1 Reply Last reply Reply Quote 0
                • NebbermindN Offline
                  Nebbermind
                  last edited by

                  Champion:
                  chloecube:


                  Thks Tianzhu,

                  the article is abt the stress that kids in Singapore are facing now, they then give a few examples of the Math question that our P2 and P4 are getting.
                  after reading the article, i feel for the children, as quoted by one of the parent: \"the kid is learning how to cycle and juggle at the same time\"
                  i wish something can be done to lessen their work load. Children shld have a beautiful memories of childhood and not buried in books all day long.

                  if not for the help i got here, i doubt i ever solved those question

                  Good Morning chloecube & Tianzhu :grphug:
                  Totally agree with chloecube; I have learnt and am still learning about Maths. Am so thankful that I can tips from this P4 Maths thread :salute: :salute:

                  I think these parents are stressed coz they r not happy with a band-1 or A grade...they wanna A* or perfect100. I believe there are usually only a couple of such difficult questions unless u r from a premium school. Even if u don't get them right and get the rest correct, u should still get band-1.

                  1 Reply Last reply Reply Quote 0
                  • B Offline
                    babies
                    last edited by

                    Hi any kind soul willing to help solving... :oops:


                    Q1: What is the smallest odd number that has only 3 factors?

                    Q2: Gary was given these numbers: 42, 50, 72, 84 and 96. Write down the sum of all the given numbers that have 2 and 6 as common factors.

                    :?: :? :?: :?

                    1 Reply Last reply Reply Quote 0
                    • T Offline
                      tianzhu
                      last edited by

                      babies:
                      Hi any kind soul willing to help solving... :oops:


                      Q1: What is the smallest odd number that has only 3 factors?

                      Q2: Gary was given these numbers: 42, 50, 72, 84 and 96. Write down the sum of all the given numbers that have 2 and 6 as common factors.

                      :?: :? :?: :?
                      Hi

                      In answering these questions, it may useful to get your child to read the chapter on Factors in the school textbook.

                      Q1) The answer is 9 (1,3,9).

                      Q2) The number 50 does not have 6 as a common factor.
                      The sum of 42, 72, 84 and 96 is 294

                      Best wishes

                      1 Reply Last reply Reply Quote 0
                      • B Offline
                        babies
                        last edited by

                        tianzhu:
                        babies:

                        Hi any kind soul willing to help solving... :oops:


                        Q1: What is the smallest odd number that has only 3 factors?

                        Q2: Gary was given these numbers: 42, 50, 72, 84 and 96. Write down the sum of all the given numbers that have 2 and 6 as common factors.

                        :?: :? :?: :?

                        Hi

                        In answering these questions, it may useful to get your child to read the chapter on Factors in the school textbook.

                        Q1) The answer is 9 (1,3,9).

                        Q2) The number 50 does not have 6 as a common factor.
                        The sum of 42, 72, 84 and 96 is 294

                        Best wishes

                        Hi tianzhu, thanks for your help,

                        But do you mind to explain in details for Q1 as I dont know how to get the steps done.

                        Thanks!

                        1 Reply Last reply Reply Quote 0

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