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    Q&A - P4 Math

    Scheduled Pinned Locked Moved Primary 4
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    • T Offline
      tianzhu
      last edited by

      elisammom:
      I used the guess and check method but the answer is not right.

      The correct answer is 36, just like chloecube done.

      I like to know why guess and check method is wrong in this question. Thanks
      Hi

      Yes, you may use GC.

      For every 4 beads that A has, B has 2 more beads than her; this means if A has 4 beads, B has 6 beads.

      Try it and you should arrive at 24 beads (A) and 36 beads(B).

      A common method used by students is “Grouping concept”.

      Another way, observe that for every incremental step, there is a difference of 10 beads (total number)

      4, 6 ----- 10
      8, 12 ------ 20

      We are looking for 60.

      60 is 6 times as many as 10

      Hence multiply initial numbers by 6.

      4*6 -----24
      6*6 ------ 36

      Best wishes

      1 Reply Last reply Reply Quote 0
      • R Offline
        ruohoo97
        last edited by

        Yeh, I see. Thanks a lot!

        1 Reply Last reply Reply Quote 0
        • C Offline
          chloecube
          last edited by

          Maths is interesting and fun if we can grab the concepts. its challenging and fun solving them

          but i find it hard to put it across to my kids sometimes, they dun seem to understand or see it at my level

          1 Reply Last reply Reply Quote 0
          • E Offline
            elisammom
            last edited by

            tianzhu:
            elisammom:

            I used the guess and check method but the answer is not right.

            The correct answer is 36, just like chloecube done.

            I like to know why guess and check method is wrong in this question. Thanks

            Hi

            Yes, you may use GC.

            For every 4 beads that A has, B has 2 more beads than her; this means if A has 4 beads, B has 6 beads.

            Try it and you should arrive at 24 beads (A) and 36 beads(B).

            A common method used by students is “Grouping concept”.

            Another way, observe that for every incremental step, there is a difference of 10 beads (total number)

            4, 6 ----- 10
            8, 12 ------ 20

            We are looking for 60.

            60 is 6 times as many as 10

            Hence multiply initial numbers by 6.

            4*6 -----24
            6*6 ------ 36

            Best wishes


            Thanks tianzhu
            Ops I make a cal error;( yes now I see it;)

            1 Reply Last reply Reply Quote 0
            • C Offline
              Cheerfuldad
              last edited by

              Hi all,


              Please help!

              Q. There are some chickens and horses at a farm. Altogether, there are 41 heads and 118 leags. How many chickens are there?

              TIA

              1 Reply Last reply Reply Quote 0
              • S Offline
                snowball
                last edited by

                1st step :

                find the different ( 4 legs - 2 legs) = 2 legs

                2nd step :
                assume all 41 heads belongs to the animal that has the lesser no. of legs ie.chickens

                thus, 41 heads x 2 legs = 82 legs

                3rd step:
                118 legs - 82 legs = 18 ( this is the no. of horse )

                final step:
                41-18=23 ( this is the no. of chickens )

                1 Reply Last reply Reply Quote 0
                • M Offline
                  Mychildren
                  last edited by

                  Hi, snowball, the third step 118-82 = 36 why is it 18?


                  Hi, cheerfuldad, I used guess and check:
                  Chicken21x2=42 Horse20x4 =80 Total heads 41 but legs 122 so not correct.
                  Chicken22x2=44 Horse19x4=76 Total heads 41 but legs 120 so not correct.
                  Chicken23x2=46 Horse18x4=72 Total heads 41 and legs 118 so this is the answer.

                  1 Reply Last reply Reply Quote 0
                  • S Offline
                    snowball
                    last edited by

                    snowball:
                    1st step :

                    find the different ( 4 legs - 2 legs) = 2 legs

                    2nd step :
                    assume all 41 heads belongs to the animal that has the lesser no. of legs ie.chickens

                    thus, 41 heads x 2 legs = 82 legs

                    3rd step: sorry, overlooked a step
                    118 legs - 82 legs = 36
                    36 divide by the difference ie = 2
                    , to get 18 ( this is the no. of horse )

                    final step:
                    41-18=23 ( this is the no. of chickens )
                    i used to use \"guess n check\" method, but sometimes my girl failed to get the correct guess even after the 4th or 5th attempt, so i switched to the above method :imcool:

                    1 Reply Last reply Reply Quote 0
                    • K Offline
                      kaimono
                      last edited by

                      Pls help to solve this problem using units. thanks

                      There were twice as many blue clips as yellow clips in the box.
                      After giving away 66 blue chips and 8 yellow clips, there were thrice as many yellow clips as blue clips left in the box.
                      How many clips were there in the box at first?

                      1 Reply Last reply Reply Quote 0
                      • MathIzzzFunM Offline
                        MathIzzzFun
                        last edited by

                        Cheerfuldad:
                        Hi all,


                        Please help!

                        Q. There are some chickens and horses at a farm. Altogether, there are 41 heads and 118 leags. How many chickens are there?

                        TIA
                        Hi

                        using area model, which is basically the assumptive method in model drawing...

                        http://www.flickr.com/photos/62167097@N02/6963704884/in/photostream

                        cheers.

                        1 Reply Last reply Reply Quote 0

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