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    Q&A - PSLE Math

    Scheduled Pinned Locked Moved Primary 6 & PSLE
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    • corneyAmberC Offline
      corneyAmber
      last edited by

      Hv time for Q1 and Q2 first:


      http://i3.photobucket.com/albums/y74/miamia2004/P6Mathsavings-1.jpg\">

      http://i3.photobucket.com/albums/y74/miamia2004/P6MathStamps-1.jpg\">

      1 Reply Last reply Reply Quote 0
      • L Offline
        lizawa
        last edited by

        suiyuan:
        Thank you for your time.



        3) Terry walks to school at an average speed of 4km/h every day. One day, after walking a distance of 1km, he realised that his watch was slow. So, he ran at a constant speed and managed to reach the school just on time. Later, he calculated that if he had run at this speed right from the start of the journey, he would have reached school 5 minutes earlier. What was his running speed?
        Time taken to walk 1km = 1/4 hr
        Let the constant speed he ran be y km/h, remaining distance be x km
        Time taken = x/y hr
        Total time taken = (x/y + 1/4)hr

        If he runs at this speed from beginning, time taken = (x+1) / y hr. This is 1/12 hr (or 5 min) faster.

        (x+1) / y = (x/y+1/4) - 1/12
        Solve this equation, the \"x\" will be eliminated and
        y = 6km/h

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        • C Offline
          clover18
          last edited by

          Does anyone have feedback on Math program by Andrew Er or Learning Lab?

          1 Reply Last reply Reply Quote 0
          • A Offline
            AnnT2009
            last edited by

            [Moderator's note: Topics merged.]


            Hi,
            I chanced upon this website recently. Need help to solve this question,

            Amy took 3 hours to travel from Town P to Town Q. Pansy took 2 hours to travel from Town Q to Town P. Both of them started travelling at 9am. At what time did they pass each other?

            Thanks and happy new year.

            1 Reply Last reply Reply Quote 0
            • C Offline
              csc
              last edited by

              AnnT2009:
              Hi,

              I chanced upon this website recently. Need help to solve this question,

              Amy took 3 hours to travel from Town P to Town Q. Pansy took 2 hours to travel from Town Q to Town P. Both of them started travelling at 9am. At what time did they pass each other?

              Thanks and happy new year.
              Let me try.

              In 1 hour, Amy covered 1/3 of distance.
              In 1 hour , Pansy covered 1/2 of distance

              In 1 hour both covered 1/3 + 1/2 = 5/6 of distance

              5/6 of distance ====== 1 hour
              6/6 of distance ====== 1 1/5 hour = 1 hour 12 minutes

              Therefore , they passed each other at 10.12 am.

              Hope I'm right. 😎

              1 Reply Last reply Reply Quote 0
              • A Offline
                AnnT2009
                last edited by

                Hi csc,


                Your answer is the same as the assessment book.
                A little confused, why your calculation is based on 6/6?
                How to explain to kid?
                Thanks for enlightening a rusty mind.

                Thanks.

                1 Reply Last reply Reply Quote 0
                • C Offline
                  csc
                  last edited by

                  As Amy and Pansy are travelling in the opposite direction, when they meet, they would have covered the total distance from P to Q. That explain the 6/6 - whole distance.


                  Hope it helps.

                  1 Reply Last reply Reply Quote 0
                  • A Offline
                    AnnT2009
                    last edited by

                    Hi csc,


                    Sorry! Still confused, don’t they meet somewhere in the middle of the journey.

                    Thanks for your patience.

                    1 Reply Last reply Reply Quote 0
                    • 3 Offline
                      3Boys
                      last edited by

                      csc:
                      AnnT2009:

                      Hi,

                      I chanced upon this website recently. Need help to solve this question,

                      Amy took 3 hours to travel from Town P to Town Q. Pansy took 2 hours to travel from Town Q to Town P. Both of them started travelling at 9am. At what time did they pass each other?

                      Thanks and happy new year.

                      Let me try.

                      In 1 hour, Amy covered 1/3 of distance.
                      In 1 hour , Pansy covered 1/2 of distance

                      In 1 hour both covered 1/3 + 1/2 = 5/6 of distance

                      5/6 of distance ====== 1 hour
                      6/6 of distance ====== 1 1/5 hour = 1 hour 12 minutes

                      Therefore , they passed each other at 10.12 am.

                      Hope I'm right. 😎

                      Maybe I'm just old but I find this new way of doing math just completely crazy. :?

                      1 Reply Last reply Reply Quote 0
                      • T Offline
                        tianzhu
                        last edited by

                        Maths Questions from http://www.channelnewsasia.com/discussion/forum.htm


                        1. Two sisters, Melissa and Nicole, started brisk-walking at 6.45a.m. from their house to a nearby park. Melissa walked at an average speed of 90m/min while Nicole's average speed was 60m/min. After arriving at the park, Melissa rested for 10 minutes and then walked back home. If Melissa met Nicole at 7.40 a.m. on her return journey, what was the distance between their house and the park?

                        2. A group of people met at a party. Each person shook hands with everyone else. Mr Li shook hands with 3 times as many men as women. Mrs Li shook hands with 4 times as many men as women. How many men and how many women were there at the party?

                        1 Reply Last reply Reply Quote 0

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