Q&A - PSLE Math
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Not use, never mind, I will try to solve it myself.

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As the photo can be only saved in iPad, cannot upload to computer leh!!
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Michaelia0816:
As the photo can be only saved in iPad, cannot upload to computer leh!!
Hi
Good Morning.
I am an old man, don’t know about ipad.
Ok, send your email through PM.
I’ll see if I can be of any help.
Best wishes -
I post in using twitter,
Go to
pic.twitter.com/rg7SCB5F -
tianzhu:
No need lah, I have already post another method of finding it.Michaelia0816:
As the photo can be only saved in iPad, cannot upload to computer leh!!
Hi
Good Morning.
I am an old man, don’t know about ipad.
Ok, send your email through PM.
I’ll see if I can be of any help.
Best wishes -
Morning Speedmaths,
Thank you. -
Tianzhu, I had already give u the website to go to the picture to see already, how? Can solve? Do you know what it is referring to actually?
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Hi everyone,
This is my first time posting here. Can anyone help to solve this?
Jim bought some chocolates and gave half of it to Ken. Ken bought some sweets and gave half of it to Jim. Jim ate 12 sweets and Ken ate 18 chocolates. The ratio of Jim’s sweets to chocolates became 1:7 and the ratio of Ken’s sweets to chocolates became 1:4. How many sweets did Ken buy?
Thank you. -
elenatay:
Hi, it would be faster to give you the answer here than going to another pages, I have taken their answer for their posts,Hi everyone,
This is my first time posting here. Can anyone help to solve this?
Jim bought some chocolates and gave half of it to Ken. Ken bought some sweets and gave half of it to Jim. Jim ate 12 sweets and Ken ate 18 chocolates. The ratio of Jim's sweets to chocolates became 1:7 and the ratio of Ken's sweets to chocolates became 1:4. How many sweets did Ken buy?
Thank you.
sorry for the copyright, i think it alright as i am doing so for helping.
Suggested solutions
Draw a model to show \"after eating\" scenario,
Ratio of Jim's sweets to chocolate (1:7)
Sweets []
Chocos [][][][][][][]
Ratio of Ken's sweets to chocolate (1:4)
Sweets [] +12 (+12 refers to the sweets eaten by Jim)
Chocos [][][][] (+12x4) - x 4 times
Both amount of Chocolates are the same,so
(7-4) units = (12x4) + 18 (18 chocolates were eaten by Ken)
3 units = 66
1 unit = 22
Amount of sweets bought by Ken->(unit +12)x2=(22+12) x 2 =68
Or use algebra which is easier.
Assume that sweets that Ken bought was S and chocolates that bought by Jim was C.
Before both of them ate, they had:
Ken -> 0.5C + 0.5S
Jim -> 0.5C + 0.5S
as each of them gave 1/2 to each other.
Jim ate 12 sweets and the ratio of Jim's sweets to chocolates became 1:7.
(0.5S-12)/0.5C = 1/7
3.5S-84=0.5C
Ken ate 18 chocolates and the ratio of Ken's sweets to chocolates became 1:4.
0.5S/(0.5C-18 ) = 1/4
(0.5C-18 ) / 0.5S = 4
0.5C-18 = 2S
3.5S-84-18=2S
3.5S-2S = 84+18
1.5S = 102
S = 102/1.5 = 68
Amount of sweets bought by Ken-> 68 -
and also welcome elenatay to here!
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