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    Q&A - PSLE Math

    Scheduled Pinned Locked Moved Primary 6 & PSLE
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    • S Offline
      Spongy
      last edited by

      :lovesite: Thank you very much master

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      • M Offline
        megamage1000
        last edited by

        Hi, i have a hard time resolving this question, Hope you will help me!


        In a photocopier shop, Copier A was turned on first, and it printed 240 pages.Then Copier B was turned on , and Copier A and Copier B continue printing together.For every 4 pages Copier A printed, Copier B printed 7 pages . Copier B printed 30 pages fewer than 2/7 of the total number of pages printed.

        Find the total number of pages printed.

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        • Y Offline
          Yu Xuan
          last edited by

          megamage1000:
          Hi, i have a hard time resolving this question, Hope you will help me!


          In a photocopier shop, Copier A was turned on first, and it printed 240 pages.Then Copier B was turned on , and Copier A and Copier B continue printing together.For every 4 pages Copier A printed, Copier B printed 7 pages . Copier B printed 30 pages fewer than 2/7 of the total number of pages printed.

          Find the total number of pages printed.
          Hi

          A --> 5 units + 30
          B --> 2 units - 30
          Total --> 7 units

          By removing the 240 printed earlier by A, both machine worked for the same amount of time and hence we can relate their output to their respective speed ratio;
          4 parts --> 5 units + 30 -240 = 5 units - 210
          7 parts --> 2 units - 30

          28 parts --> 35units - 1470
          28 parts --> 8units - 120
          draw a model to represent the 28 parts, you will see that,
          27 units --> 1470 - 120 = 1350
          1 unit --> 50
          7 units --> 50 x 7 = 350

          Yuxuan

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          • T Offline
            tianzhu
            last edited by

            megamage1000:
            Hi, i have a hard time resolving this question, Hope you will help me!


            In a photocopier shop, Copier A was turned on first, and it printed 240 pages.Then Copier B was turned on , and Copier A and Copier B continue printing together.For every 4 pages Copier A printed, Copier B printed 7 pages . Copier B printed 30 pages fewer than 2/7 of the total number of pages printed.

            Find the total number of pages printed.
            Hi

            A neat way is to use MD. Alternatively, you may also use “Units and Parts”.

            Use equivalent ratios to avoid working with decimals.

            For every 4 pages Copier A printed, Copier B printed 7 pages .

            Copier A ----- 4 units ------ 8 units
            Copier B ----- 7 units ------ 14 units

            Total number of pages ------- 7 parts.

            14 units + 30 ------- 2 parts

            7 units + 15 ------ 1 part

            49 units + 105 ------- 7 parts

            49 units + 105 ------ 240 + 8 units + 14 units

            27 units ------- 135
            1 unit ------- 5

            Total number of pages printed -------- (49*5) + 105 -------- 350.

            Best wishes

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            • R Offline
              rose michelle
              last edited by

              Chris had some M&M’s chocolates. He gave 3/10 of them to Ben and 2/5 of the remainder to Ken. He had 105 left. How many M&M’s chocolates had chris at first?

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              • R Offline
                rose michelle
                last edited by

                Chris had some M&M’s chocolates. He gave 3/10 of them to Ben and 2/5 of the remainder to Ken. He had 105 left. How many M&M’s chocolates had chris at first?

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                • P Offline
                  php
                  last edited by

                  rose michelle:
                  Chris had some M&M's chocolates. He gave 3/10 of them to Ben and 2/5 of the remainder to Ken. He had 105 left. How many M&M's chocolates had chris at first?

                  Ben --> 3/10, remaining --> 7/10
                  Ken --> 2/5 x 7/10 = 7/25, remaining --> 7/10 - 7/25 = 21/50

                  21 units --> 105
                  1 unit --> 105/21 = 5
                  50 units --> 50 x 5 = 250

                  Ans : 250

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                  • F Offline
                    fightingmom
                    last edited by

                    rose michelle:
                    Chris had some M&M's chocolates. He gave 3/10 of them to Ben and 2/5 of the remainder to Ken. He had 105 left. How many M&M's chocolates had chris at first?

                    Hi ,

                    You can use the Branching method:

                    Total
                    /. \\
                    Ben. Remainder
                    3/10. 7/10



                    Remainder
                    /. \\
                    Ken. Left
                    2/5. 3/5


                    3/5 = 105
                    3 units = 105
                    1 unit = 35
                    5 units = 175 = 7/10

                    7 units = 175
                    1 unit = 25
                    10 units = 250

                    Ans: 250

                    (sorry if you can't see well cos i can't align the numbers properly here )

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                    • S Offline
                      speedmaths.012624com
                      last edited by

                      rose michelle:
                      Chris had some M&M's chocolates. He gave 3/10 of them to Ben and 2/5 of the remainder to Ken. He had 105 left. How many M&M's chocolates had chris at first?

                      Hi,

                      Some P6 pupils may find fractions slightly more difficult to handle than whole numbers.

                      One method to solve this, without having too many fractions in the working, is “The Denominators are Your Friends Method”

                      The denominators here are 10 and 5.
                      10 x 5 = 50

                      Let Chris have 50u of chocolates at first.
                      (50u stands for 50 units, or 50 boxes for those used to the Model Method.)

                      http://i50.tinypic.com/359fksl.jpg\">

                      21u → 105 chocolates (left)
                      1u → 5 chocolates
                      50u → 250 chocolates (at first)

                      Hope this helps.

                      Cheers


                      speedmaths.com


                      PS.
                      Parents who wish to find out more about this method may wish to look at the “PSLE Maths Workshop for Parents” thread in the Happenings forum.

                      .

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                      • T Offline
                        tianzhu
                        last edited by

                        jarenchuatw:

                        Q2 XiaoMing and Mary each had a certain number of comics. Xiao Ming gave away 40% of his comics and another 15% of his remaining comics to Mary. Then Mary gave 2/3 of her comics to Sally. Xaioming found that he had thrice as many comics left as Mary. If Mary had 210 comics at first,
                        (a) how many comics did Xiao Ming have at first? (Answer: 500)
                        (b) how many comics did Sally receive from Mary? (Answer : 170)
                        Hi

                        Hope this helps.

                        Best wishes

                        http://farm9.staticflickr.com/8005/7207450038_e911da4ea0_z.jpg\">

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