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    Q&A - PSLE Math

    Scheduled Pinned Locked Moved Primary 6 & PSLE
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    • F Offline
      fightingmom
      last edited by

      MathIzzzFun:
      fightingmom:

      Hi,


      Please help with the following question :

      At 7am, Car A left Town X for Town Y while Car B left Town Y for Town X. At 3pm, the two cars passed each other. 5 hours later, Car A reached Town Y but Car B was still 150km away from Town X. Find the distance between Town X and Town Y.

      TIA!

      concept of combined speed

      When Car A and Car B meet, the total distance covered is XY and the total time taken is 8 hours (7am to 3pm).

      5 hours after passing each other, remaining distance to be covered = 150 km

      Both cars took 3 hours (8-5) to cover a total distance of 150 km,
      combined speed --> 150 km/3h = 50km/h (quite a slow speed considering that this is a combined speed)
      Total distance between XY = 50 km/h x 8h = 400 km

      cheers.

      This is the first time I came across \"combined speed\".

      :thankyou: so much for your help ! :salute:

      1 Reply Last reply Reply Quote 0
      • K Offline
        kiasuaunt
        last edited by

        Hi - pls help me with the md for this q:


        Ben n Mary went shopping with a total of $204. Ben had $12 more than Mary. Mary spent 4 times as much money as Ben and was left with half the amount of money that Ben had left.

        a) How much money did Ben bring along for shopping?

        b) How much money had Ben left after shopping?

        Thank you.

        1 Reply Last reply Reply Quote 0
        • S Offline
          speedmaths.012624com
          last edited by

          kiasuaunt:
          Hi - pls help me with the md for this q:


          Ben n Mary went shopping with a total of $204. Ben had $12 more than Mary. Mary spent 4 times as much money as Ben and was left with half the amount of money that Ben had left.

          a) How much money did Ben bring along for shopping?

          b) How much money had Ben left after shopping?

          Thank you.

          Hi,

          One possible Solution to Part (a)

          Ben n Mary went shopping with a total of $204
          Sum = $204

          Ben had $12 more than Mary
          Difference = $12

          Bigger number = (Sum + Difference) ÷ 2
          Sam → ($204 + $12) ÷ 2 = $108

          Hope this helps.

          Cheers

          speedmaths.com


          PS:
          Smaller number = (Sum - Difference) ÷ 2
          Mary → ($204 - $12) ÷ 2 = $96

          -

          1 Reply Last reply Reply Quote 0
          • S Offline
            speedmaths.012624com
            last edited by

            kiasuaunt:
            Hi - pls help me with the md for this q:


            Ben n Mary went shopping with a total of $204. Ben had $12 more than Mary. Mary spent 4 times as much money as Ben and was left with half the amount of money that Ben had left.

            a) How much money did Ben bring along for shopping?

            b) How much money had Ben left after shopping?

            Thank you.
            Hi,

            One possible Solution to Part (b)
            Using the Advanced Model Method
            (or Bags and Boxes Method)

            Sam → ($204 + $12) ÷ 2 = $108
            Mary → ($204 - $12) ÷ 2 = $96

            Let Sam put his $108 into 1 Bag and 2 Boxes.
            Let Mary put her $96 into 4 Bags and 1 Box.

            (Each of the 5 Bags contains the same amount of money.)
            (Each of the 3 Boxes contains the same amount of money.)

            Mary spent 4 times as much money as Ben.
            Mary spent her 4 Bags of money, and Ben spent his 1 Bag of money.

            Mary was left with half the amount of money that Ben had left.
            Mary had 1 Box of money left, and Ben had 2 Boxes of money left.

            Mary:
            $96 → 4 Bags + 1 Box…………….(Row 1)

            Sam:
            $108 → 1 Bag + 2 Boxes
            (x 4)
            $432 → 4 Bags + 8 Boxes…………(Row 2)

            Row 2 – Row 1
            $432 - $96 → $336 → 0 Bag + 7 Boxes
            7 Boxes → $336
            1 Box → $48
            2 Boxes → $96

            Ben had 2 Boxes of money left.
            Ben had $96 left.

            Hope this helps.

            Cheers

            speedmaths.com

            PS.
            Parents who wish to know more about the Advanced Model Method can check out our thread in the Happenings forum.

            .

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            • 2 Offline
              2DMommy
              last edited by

              2DMommy:
              Please help me with these two questions :


              1) Pasqual, Quincy , Robert and Sheridan had a total of 242 muffins. Each of them would have an equal number of muffins if Pasqual bought 10 more muffins, Quincy gave away 21 muffins, Robert increased the number of muffins he had by 2/3 and Sheridan decreased the number of muffins he had by 20%. How many muffins did each of them have ?

              2) 0.6 of Luqman's allowance is twice as much as 10% of Zachary's allowance. After Luqman's spends thrice as much as Zachary, Luqman's and Zachary left with $36 and $252 respectively. How much does Zachary and Luqman's each have at first?

              Thank you.
              Can someone please help me with the above two questions? Thank you !

              1 Reply Last reply Reply Quote 0
              • N Offline
                nounou
                last edited by

                :rahrah: :thankyou: :udaman: :goodpost: :lovesite:

                :thankyou: :thankyou:

                MathIzzzFun:
                Treelodge:

                Can some please help to do this Q? :imdrowning:
                :thankyou: :thankyou:

                Car A and Car B left Town Y at the same time, heading in the opposite direction. Car A headed for Town Z while CAr B left for Town X. The speed of Car B was 20km/h faster than Car A. After 1/2 h, Car A had completed 2/3 of its journey while Car B had completed 1/2 of its journey. The two cars were also 110km apart.
                a) Calculate the speed of Car A
                b) How far was Car B from Town X when Car A reached its destination?
                :?: :thankyou:

                after 1/2h, 20km x 1/2 =10 km --> Car B would have travelled 10 km more than Car A.
                Distance travelled by A --> 1 unit
                Distance travelled by B --> 1 unit + 10 (1/2 journey)
                Total 2 units + 10 --> 110
                1 unit --> 50 km
                A's speed = 50 km ÷ 1/2 = 100 km/h

                Fraction of journey travelled by A : B
                = 2/3 : 1/2
                = 1 : 3/4
                When A reached its destination, B would have travelled 3/4 of its journey ie it will still have 1/4 of the journey to travel
                1/2 journey --> 1 unit + 10 = 60 km
                1/4 journey --> 30 km

                Car B will be 30 km from X.

                cheers.

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                • N Offline
                  nounou
                  last edited by

                  Selamat Hari Raya :rahrah: 🕺

                  Please help to solve this Q: :imconstipated: :?: :gloomy:
                  How I love the smilies :rotflmao:

                  Roy left Point A for Point B, cycling at 8km/h. 1 hour later, Patrick, also heading for Point B, passed Point A cycling at a uniform speed. He caught up with Roy when he was 14 km away from Point B. How long did Patrick take to cycle from Point A to Point B which was 54km apart?
                  :thankyou: :thankyou: :thankyou:

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                  • R Offline
                    Robertpattinsonidle
                    last edited by

                    Please help me. how to solve these types of qsns? http://i47.tinypic.com/65v0aw.jpg\">

                    1 Reply Last reply Reply Quote 0
                    • MathIzzzFunM Offline
                      MathIzzzFun
                      last edited by

                      2DMommy:
                      Please help me with these two questions :


                      1) Pasqual, Quincy , Robert and Sheridan had a total of 242 muffins. Each of them would have an equal number of muffins if Pasqual bought 10 more muffins, Quincy gave away 21 muffins, Robert increased the number of muffins he had by 2/3 and Sheridan decreased the number of muffins he had by 20%. How many muffins did each of them have ?

                      2) 0.6 of Luqman's allowance is twice as much as 10% of Zachary's allowance. After Luqman's spends thrice as much as Zachary, Luqman's and Zachary left with $36 and $252 respectively. How much does Zachary and Luqman's each have at first?

                      Thank you.

                      Can someone please help me with the above two questions? Thank you !
                      Both questions could be solved quite easily with MD, I shall use the units approach due to time constraint.

                      Q1.
                      In the end, each will have 20u
                      At first,
                      P --> 20u -10
                      Q --> 20u + 21
                      R --> 12u
                      S --> 25u
                      Total --> 77u + 11 = 242
                      1u --> 33

                      At first, number of muffins each had :
                      P --> 650
                      Q --> 681
                      R --> 396
                      S --> 825

                      cheers.

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                      • MathIzzzFunM Offline
                        MathIzzzFun
                        last edited by

                        2DMommy:
                        Please help me with these two questions :



                        2) 0.6 of Luqman's allowance is twice as much as 10% of Zachary's allowance. After Luqman's spends thrice as much as Zachary, Luqman's and Zachary left with $36 and $252 respectively. How much does Zachary and Luqman's each have at first?

                        Thank you.

                        Can someone please help me with the above two questions? Thank you !

                        3/5 Luq's allowance = 2/10 Zac's allowance
                        3/5 Luq's allowance = 3/15 Zac's allowance
                        Luq's allowance : Zac's allowance --> 1 : 3

                        Luq's spending : Zac's spending --> 3u : 1u
                        Luq's allowance : Zac's allowance --> 3u + $36 : 1u + $252 = 1 : 3

                        So, 9u + $108 = 1u + $252
                        1u --> 18

                        Luq's allowance --> $90
                        Zac's allowance --> $270

                        cheers.

                        1 Reply Last reply Reply Quote 0

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