Q&A - PSLE Math

[kay22]

Please help...thanks a lot.


http://i50.tinypic.com/2rqkluc.jpg\">

[MathIzzzFun]

kay22:

Please help...thanks a lot.


http://i50.tinypic.com/2rqkluc.jpg\">

unshaded area = 1/2 area of rectangle
shaded area = area of quadrant - 1/2 area of rectangle

perimeter = circumference of quadrant + 2 x radius - 1/2 perimeter of rectangle + radius (diagonal)

cheers.

[kay22]

MathIzzzFun:

kay22:

Please help...thanks a lot.


http://i50.tinypic.com/2rqkluc.jpg\">

unshaded area = 1/2 area of rectangle
shaded area = area of quadrant - 1/2 area of rectangle

perimeter = circumference of quadrant + 2 x radius - 1/2 perimeter of rectangle + radius (diagonal)

cheers.

Thanks for the clarification...We are stuck at \" Radius (diagonal)\". It don't seem to be touching from one end to another.

[MathIzzzFun]

kay22:

MathIzzzFun:

[quote=\"kay22\"]Please help...thanks a lot.


http://i50.tinypic.com/2rqkluc.jpg\">

unshaded area = 1/2 area of rectangle
shaded area = area of quadrant - 1/2 area of rectangle

perimeter = circumference of quadrant + 2 x radius - 1/2 perimeter of rectangle + radius (diagonal)

cheers.

Thanks for the clarification...We are stuck at \" Radius (diagonal)\". It don't seem to be touching from one end to another.[/quote]draw the other diagonal n you see that the diagonal is equal to radius.

cheers.

[kay22]

[cheers.[/quote]


Thanks for the clarification...We are stuck at \" Radius (diagonal)\". It don't seem to be touching from one end to another.[/quote]

draw the other diagonal n you see that the diagonal is equal to radius.

cheers.[/quote]

Ok, great...Fully understand now! :thankyou:

[tianzhu]

i_am_not_a_parent:

I dun under stand the part that is highlighted in red.. I appreciate ur help

Hi

Please read the complete sentence.

Best wishes

[tianzhu]

zanen:

please help me. it was given by the relief teacher from my math teacher. the relief teacher dont know how to teach math ask me to find out by myself//

Hi

MathIzzzFun has already posted the solution. It’s on page 833.

Best wishes

[paranoid]

http://i49.tinypic.com/2qwcsr9.jpg\">


Question from NHPS Prelim 2012 :imdrowning:

[tianzhu]

paranoid:

Question from NHPS Prelim 2012

Hi

I’ve not much time for slide now.

Try to rearrange the shaded part.

Area of shaded part ------- Area of quadrant (r28) – area of triangle (1/2*28*28)

Best wishes

[Ready2WORK]

paranoid:

http://i49.tinypic.com/2qwcsr9.jpg\">


Question from NHPS Prelim 2012 :imdrowning:

@paranoid,
This is the working. Will attach image later if needed. Correct me if I am wrong.
28+28+14+14=84
28+14=42
1/2*84*42=1764
1/2*22/7*28(squared)=1232
1764-1232=532
532/4=133
1/8*22/7*28(squared)=308
308-133=175
Answer: 175