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    Q&A - PSLE Math

    Scheduled Pinned Locked Moved Primary 6 & PSLE
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    • R Offline
      Ready2WORK
      last edited by

      Ready2WORK:
      paranoid:

      http://i49.tinypic.com/2qwcsr9.jpg\">


      Question from NHPS Prelim 2012 :imdrowning:

      @paranoid,
      This is the working. Will attach image later if needed. Correct me if I am wrong.
      28+28+14+14=84
      28+14=42
      1/2*84*42=1764
      1/2*22/7*28(squared)=1232
      1764-1232=532
      532/4=133
      1/8*22/7*28(squared)=308
      308-133=175
      Answer: 175 😉

      @paranoid,
      Here is the image if needed.
      http://i49.tinypic.com/t8uhol.png\">
      The blue dots are all the same, and they are the areas, not lengths.
      The cm squares are not written. :salute:

      1 Reply Last reply Reply Quote 0
      • T Offline
        tianzhu
        last edited by

        kay22:
        http://i47.tinypic.com/347xpn8.jpg\">

        Hi

        Let the length (slanting) of one isosceles triangle be 1a.

        16a -------- 2y + 112

        a --------- y/8 + 7

        Perimeter of each isosceles triangle ------- 2(y/8 + 7) + y/4 --------- y/2 + 14

        If y=40

        Perimeter of each isosceles triangle ------- y/2 + 14 --------- 40/2+ 14 -------- 34

        Best wishes

        1 Reply Last reply Reply Quote 0
        • R Offline
          Ready2WORK
          last edited by

          tianzhu:
          kay22:

          http://i47.tinypic.com/347xpn8.jpg\">


          Hi

          Let the length (slanting) of one isosceles triangle be 1a.

          16a -------- 2y + 112

          a --------- y/8 + 7

          Perimeter of each isosceles triangle ------- 2(y/8 + 7) + y/4 --------- y/2 + 14

          If y=40

          Perimeter of each isosceles triangle ------- y/2 + 14 --------- 40/2+ 14 -------- 34

          Best wishes

          If the perimeter of each isosceles triangle is 34, then each side must be 11 one-third, so y would then be 11 one third times 4, which is then 45 one-third. Explain? :scratchhead:

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          • A Offline
            AJH
            last edited by

            tianzhu:
            AJH:

            [quote=\"tianzhu\"]
            But isn't 30% of students in the parade ground and 70% of students at the indoor sports hall = 180 + 280 = 460?

            Hi

            Good Morning.

            The number of boys and girls remains the same before and after the transfer. The total number of 1000 did not change at all.

            The number of girls stays the same that is 480 before and after.

            In this case

            Number of girls in the beginning ------- 480

            Number of girls in the end (after the transfer)

            Parade square ------- 3 parts ------ 3*55 ------- 165 (30% of 550)

            Indoor stadium -------- 7 units ------- 7*45 ------- 315 (70% of 450)

            Total number ------ 165 + 315 ------- 480

            Best wishes[/quote] :thankyou: for all the help you have given me.

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            • A Offline
              AJH
              last edited by

              Hi - PSLE Maths is this Friday. I want to thank everyone for your help.

              :thankyou: very much for your time and effort. I appreciate what all of you have done.

              1 Reply Last reply Reply Quote 0
              • R Offline
                Ready2WORK
                last edited by

                AJH:
                Hi - PSLE Maths is this Friday. I want to thank everyone for your help.

                :thankyou: very much for your time and effort. I appreciate what all of you have done.
                Yup! Good luck. For you and me. 😄 😄 :celebrate:

                1 Reply Last reply Reply Quote 0
                • K Offline
                  kiasuaunt
                  last edited by

                  I would also like to join my god-daughter to thank all of you for your kindness and generosity.We have benefitted much from this - you have all made this journey less painful and frustrating. :thankyou: and God Bless.

                  1 Reply Last reply Reply Quote 0
                  • P Offline
                    paranoid
                    last edited by

                    tianzhu:
                    paranoid:



                    Question from NHPS Prelim 2012

                    Hi

                    I’ve not much time for slide now.

                    Try to rearrange the shaded part.

                    Area of shaded part ------- Area of quadrant (r28) – area of triangle (1/2*28*28)

                    Best wishes

                    Hmm Tianzhu, how can it be proven that the shaded part A can be re-arranged to form a half-rugby like you mentioned? Someone else provided a different answer.

                    1 Reply Last reply Reply Quote 0
                    • R Offline
                      Ready2WORK
                      last edited by

                      paranoid:
                      tianzhu:

                      [quote=\"paranoid\"]

                      Question from NHPS Prelim 2012

                      Hi

                      I’ve not much time for slide now.

                      Try to rearrange the shaded part.

                      Area of shaded part ------- Area of quadrant (r28) – area of triangle (1/2*28*28)

                      Best wishes

                      Hmm Tianzhu, how can it be proven that the shaded part A can be re-arranged to form a half-rugby like you mentioned? Someone else provided a different answer.[/quote]I was thinking about that point too, but you can't be sure that it rearranges into a exact half-rugby. So that was probably not the solution. 😉

                      1 Reply Last reply Reply Quote 0
                      • T Offline
                        tianzhu
                        last edited by

                        paranoid:
                        Hmm Tianzhu, how can it be proven that the shaded part A can be re-arranged to form a half-rugby like you mentioned? Someone else provided a different answer.

                        Hi

                        When dealing with composite figures, one of the more efficient ways is to work with familiar shapes. Students should be pretty well versed in familiar shapes.

                        The answer to your question is 224 sq cm.

                        Hope this helps.

                        Best wishes

                        http://farm9.staticflickr.com/8462/8024994319_c3bfa77fea_z.jpg\">

                        1 Reply Last reply Reply Quote 0

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