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    Q&A - PSLE Math

    Scheduled Pinned Locked Moved Primary 6 & PSLE
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    • Suz855S Offline
      Suz855
      last edited by

      ginginboy:
      Hi,


      I need help to solve the following P6 qns for my P6 boy. Appreciate your help anybody who can help in solving them. Thank you very much...
      Qns 1:
      Boy B had some 20-cent and 50-cent coins. The number of 20-cent coins was 3/7 of the number of 50-cent coins. If he saved another thirty coins of each type, the number of 20-cent coins would become 9/11 of the number of 50-cents coins.
      What is the total value of the 20-cent coins that Boy B had at first?

      20 cent ----50 cent ...(diff)
      3u --------- 7u--------4u
      +30-------+30 (since we add the same no. of coins, diff remain unchanged)
      9-----------11--------2
      X2--------x2--------x2
      18u---------22u

      15u-->30
      1u-->2

      No. Of 20 cent coins at first -->3x2=6, thus total value will be 6x0.2=$1.20



      Qns 2:
      Rachel made chocolate, mint and sugar doughnuts for sale. She made 80 more chocolate doughnuts than mint doughnuts. The number of mint doughnuts made was 24 more than the number of sugar doughnuts. She sold 3/4 of the chocolate doughnuts, 1/3 of the mint doughnuts and 1/2 of the sugar doughnuts. In the end, there were 416 doughnuts left. How many mint doughnuts did Rachel made?

      1 Reply Last reply Reply Quote 0
      • Suz855S Offline
        Suz855
        last edited by

        ginginboy:
        Hi,


        I need help to solve the following P6 qns for my P6 boy. Appreciate your help anybody who can help in solving them. Thank you very much...
        Qns 1:
        Boy B had some 20-cent and 50-cent coins. The number of 20-cent coins was 3/7 of the number of 50-cent coins. If he saved another thirty coins of each type, the number of 20-cent coins would become 9/11 of the number of 50-cents coins.
        What is the total value of the 20-cent coins that Boy B had at first?

        20 cent ----50 cent ...(diff)
        3u --------- 7u--------4u
        +30-------+30 (since we add the same no. of coins, diff remain unchanged)
        9-----------11--------2
        X2--------x2--------x2
        18u---------22u

        15u-->30
        1u-->2

        No. Of 20 cent coins at first -->3x2=6, thus total value will be 6x0.2=$1.20



        Qns 2:
        Rachel made chocolate, mint and sugar doughnuts for sale. She made 80 more chocolate doughnuts than mint doughnuts. The number of mint doughnuts made was 24 more than the number of sugar doughnuts. She sold 3/4 of the chocolate doughnuts, 1/3 of the mint doughnuts and 1/2 of the sugar doughnuts. In the end, there were 416 doughnuts left. How many mint doughnuts did Rachel made?

        1 Reply Last reply Reply Quote 0
        • H Offline
          happyheart
          last edited by

          Suz855:
          6a[boya][galsa]

          6b[galsb][boyb]
          6c[2unit][galsc]

          Total boys -->5u
          BoyC-->2u
          BoyA+boyB-->5u-2u=3u
          GalA+galB-->3u
          Total pupils -->9u

          Fraction of pupils that are boys --> 5/9
          Cheers
          Thanks Suz855,
          how do you get total 9u for the boys?

          1 Reply Last reply Reply Quote 0
          • Suz855S Offline
            Suz855
            last edited by

            happyheart:
            Suz855:

            6a[boya][galsa]

            6b[galsb][boyb]
            6c[2unit][galsc]

            Total boys -->5u
            BoyC-->2u
            BoyA+boyB-->5u-2u=3u
            GalA+galB-->3u
            Total pupils -->9u

            Fraction of pupils that are boys --> 5/9
            Cheers

            Thanks Suz855,
            how do you get total 9u for the boys?

            Total number of units for p6a n p6b is 6units since inferred that each class must have 3u of pupils, given the 3 classes have equal number thus 3x3u = 9 u.... Cheers

            1 Reply Last reply Reply Quote 0
            • H Offline
              happyheart
              last edited by

              Suz855:
              happyheart:

              [quote=\"Suz855\"]6a[boya][galsa]

              6b[galsb][boyb]
              6c[2unit][galsc]

              Total boys -->5u
              BoyC-->2u
              BoyA+boyB-->5u-2u=3u
              GalA+galB-->3u
              Total pupils -->9u

              Fraction of pupils that are boys --> 5/9
              Cheers

              Thanks Suz855,
              how do you get total 9u for the boys?



              Total number of units for p6a n p6b is 6units since inferred that each class must have 3u of pupils, given the 3 classes have equal number thus 3x3u = 9 u.... Cheers[/quote]
              I get it now, thank you.

              1 Reply Last reply Reply Quote 0
              • M Offline
                Mary Joy
                last edited by

                Please help to solve this questions…


                1)Indriani had a bag of assorted candies.1/3 of the candies were lollipops and the rest were candy canes.She shared the lollipops equally among the boys such that each boy received 1/9 of the assorted candies.She then shared the candy canes equally among the girls such that each girl received 1/6 of the assorted candies.Find the number of boys and the number of girls.

                2)Adam and Rahman shared some beads.If Adam gave 1/3 of his share to Rahmad,Rahmad would have 70 more than Adam.If Adam gave 1/5 of his share to Rahmad,Rahmad would have 10 more than Adam.How many beads does Adam have at first?

                3)During the school holidays,Chris read 312 pages of a book at first.He read the remaining pages in 20 days,with the same number of pages each day.During these 20 days,he read 1/12 of the book in 6 days.How many pages of the book did he read in the 6 days?

                1 Reply Last reply Reply Quote 0
                • M Offline
                  Mary Joy
                  last edited by

                  Please help to solve this questions…


                  1)Indriani had a bag of assorted candies.1/3 of the candies were lollipops and the rest were candy canes.She shared the lollipops equally among the boys such that each boy received 1/9 of the assorted candies.She then shared the candy canes equally among the girls such that each girl received 1/6 of the assorted candies.Find the number of boys and the number of girls.

                  2)Adam and Rahman shared some beads.If Adam gave 1/3 of his share to Rahmad,Rahmad would have 70 more than Adam.If Adam gave 1/5 of his share to Rahmad,Rahmad would have 10 more than Adam.How many beads does Adam have at first?

                  3)During the school holidays,Chris read 312 pages of a book at first.He read the remaining pages in 20 days,with the same number of pages each day.During these 20 days,he read 1/12 of the book in 6 days.How many pages of the book did he read in the 6 days?

                  1 Reply Last reply Reply Quote 0
                  • MathIzzzFunM Offline
                    MathIzzzFun
                    last edited by

                    Mary Joy:
                    Please help to solve this questions...


                    1)Indriani had a bag of assorted candies.1/3 of the candies were lollipops and the rest were candy canes.She shared the lollipops equally among the boys such that each boy received 1/9 of the assorted candies.She then shared the candy canes equally among the girls such that each girl received 1/6 of the assorted candies.Find the number of boys and the number of girls.
                    Number of boys = 1/3 ÷ 1/9 = 3
                    Number of girls = 2/3 ÷ 1/6 = 4

                    cheers.

                    1 Reply Last reply Reply Quote 0
                    • MathIzzzFunM Offline
                      MathIzzzFun
                      last edited by

                      Mary Joy:
                      Please help to solve this questions...



                      2)Adam and Rahman shared some beads.If Adam gave 1/3 of his share to Rahmad,Rahmad would have 70 more than Adam.If Adam gave 1/5 of his share to Rahmad,Rahmad would have 10 more than Adam.How many beads does Adam have at first?
                      same as this question -
                      \"If David after giving 1/3 of his money to Ken, Ken will have $70 more than David.
                      If David after giving 1/5 of his money to Ken, Ken will have $10 money than David. How much does David have initially?\"

                      - http://www.kiasuparents.com/kiasu/forum/viewtopic.php?f=69&t=280&start=8620

                      cheers.

                      1 Reply Last reply Reply Quote 0
                      • MathIzzzFunM Offline
                        MathIzzzFun
                        last edited by

                        Mary Joy:
                        Please help to solve this questions...



                        3)During the school holidays,Chris read 312 pages of a book at first.He read the remaining pages in 20 days,with the same number of pages each day.During these 20 days,he read 1/12 of the book in 6 days.How many pages of the book did he read in the 6 days?
                        1/12 = 6/72
                        6 days --> 6/72 book
                        1 day --> 1/72 book
                        20 days --> 20/72 book
                        1-20/72 = 52/72

                        52/72 book --> 312 pages
                        1/72 book --> 6 pages

                        6 days --> 6/72 book --> 36 pages

                        cheers.

                        1 Reply Last reply Reply Quote 0

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