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    Q&A - PSLE Math

    Scheduled Pinned Locked Moved Primary 6 & PSLE
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    • T Offline
      tianzhu
      last edited by

      Hi, lizawa

      Thanks for your help.

      1 Reply Last reply Reply Quote 0
      • T Offline
        tianzhu
        last edited by

        Q1) Alan had some apples. When he packed them into bags of seven apples, he would have 3 apples left. When he packed them into bags of nine apples, he would be short of 6 apples. What was the least number of apples that Alan had?


        This problem may be solved by listing and Guess and Check which are tedious.

        Wish to seek help from members who may be aware of any more effective method.

        1 Reply Last reply Reply Quote 0
        • corneyAmberC Offline
          corneyAmber
          last edited by

          is this ok?


          10+ (7* ?) = 10 + 78 = 66

          3 + (9
          ?) = 3 + 9*7 = 66

          if kids know their times table well, this is fast.

          1 Reply Last reply Reply Quote 0
          • T Offline
            tianzhu
            last edited by

            ks2me:
            is this ok?


            10+ (7* ?) = 10 + 7*8 = 66

            3 + (9* ?) = 3 + 9*7 = 66

            if kids know their times table well, this is fast.
            Hi ks2me

            Please elabrate more, why 10+, ......?

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            • corneyAmberC Offline
              corneyAmber
              last edited by

              pardon me if my brain thinks too simply... 😛



              i used the first sequence as (7+3) + 7 + 7 + 7........... so 10 + (7*?)

              and second as (9-6) + 9 + 9 + 9 .................. so 3 + (9*?)

              10 + (7*?) = 3 + (9*?)

              7 + (7* ?) = 9*?

              can do?

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              • S Offline
                suiyuan
                last edited by

                Thank you for your help.



                http://farm4.static.flickr.com/3229/2846445899_5a2f87b59a_o.jpg\">

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                • L Offline
                  lizawa
                  last edited by

                  Let AD be x cm

                  Let AB be y cm
                  \t
                  Perimeter of ABCD = 20cm
                  so, x+y = 20/2 = 10 cm

                  Area of big square = y2
                  Area of small square = x2

                  Area of 4 sqaures = 80 square cm
                  So area of 1 big + 1 small = 40 square cm

                  x2 + y2 = 40

                  x + y = 10
                  (x+y)(x+y) = 100
                  x2 + y2 + 2xy = 100
                  40 + 2xy = 100
                  2xy = 60
                  xy = 30

                  Area of shaded rectangle = xy = 30 square cm.

                  Is the answer correct ?

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                  • S Offline
                    suiyuan
                    last edited by

                    Hi lizawa


                    Thank You.
                    I am sorry, no answer was given.

                    1 Reply Last reply Reply Quote 0
                    • S Offline
                      suiyuan
                      last edited by

                      Thank You for your time.


                      1) Kenneth wants to rent a bicycle from Jim’s Bicycle Kiosk. The cost © of renting a bicycle for d hours is given by C = $(3d + 5). Find the cost of renting the bicycle if Kenneth wants to cycle for 4 hours. (2 marks)


                      2) After 20 minutes in a cross-country race, Alan has run 5/8 of the route while Bernard has covered only 3/8 of the distance. Both run at a uniform average speed each and Bernard runs 60m/min slower than Alan.
                      (a) Find the total distance of the race.
                      (b) If Bernard wants to finish at the same time as Alan, by how much should he increase his average speed for the remainder of the race? Express the answer in m/min
                      (5 marks)

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                      • ChiefKiasuC Offline
                        ChiefKiasu
                        last edited by

                        lizawa:
                        ...

                        (x+y)(x+y) = 100
                        x2 + y2 + 2xy = 100
                        40 + 2xy = 100
                        2xy = 60
                        xy = 30

                        Area of shaded rectangle = xy = 30 square cm.

                        Is the answer correct ?
                        *clap* *clap* That is the right answer. However, are children in P6 taught how to do an expansion of (x+y)^2 ? Without that step, it is impossible to solve the equation.

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