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    Q&A - PSLE Math

    Scheduled Pinned Locked Moved Primary 6 & PSLE
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    • Y Offline
      YumYum
      last edited by

      MathIzzzFun:
      YumYum:

      Hi, one more Qn:


      Derrick and John shared a sum of money.
      Derrick received 2/7 of the sum of money.
      Both of them spent part of their money and saved the rest.
      The amount of money Derrick spent was 3/5 the amount he saved.
      The amount of money John spent was 1/9 the amount he saved.
      Express the amount of money John spent as a ratio of the amount John saved.
      thks!

      pls check the last sentence --- I think it is probably
      Express the amount of money Derrick spent as a ratio of the amount John saved.

      or

      Express the amount of money John spent as a ratio of the amount Derrick saved..

      cheers.


      Hi, apologies. My mistake, the last sentence is \"Express the amount of money Derrick spent as a ratio of the amount John saved.\"

      1 Reply Last reply Reply Quote 0
      • Y Offline
        YumYum
        last edited by

        MathIzzzFun:
        YumYum:

        Hi, can someone pls help with this Qn? thanks!


        http://i34.tinypic.com/121fyih.jpg\">


        unshaded area = 1/3 area of original rectangle.
        shaded area = 1/3 area of original rectangle = 28 cm2

        area of original rectangle = 84 cm2

        cheers.


        Thanks for yr usual help šŸ•ŗ

        1 Reply Last reply Reply Quote 0
        • ozoraO Offline
          ozora
          last edited by

          help needed. looks simple but my answer is fraction which must be wrong.

          Tom had 295 more sweets than John.
          After Tom gave away 2/5 of the sweets he had and John gave away 2/3 of the sweets, Tom had 329 more sweets than John.
          how many sweets did they have altogether at first?

          1 Reply Last reply Reply Quote 0
          • ozoraO Offline
            ozora
            last edited by

            Hi,


            Speed of Van = 180 / 3 = 60km/h

            a) At the time of overtaking, both Van and Car have travelled the same distance,

            60(t) = 75 (t - 1/2)
            t = 2.5 hrs

            So, the time is 1400 hrs or 2pm when the Car overtakes the Van.

            b) Time taken for Car to reach B = 180 / 75 = 2.4hrs

            In 2.4hrs, the Van travelled = 60 x 2.4 = 144km

            Thus, the Van is 180-144=36 km away from B

            Regards[/quote] thanks got it correct the first part but should the answer in b) 6 km as the van has travelled extra of 0.5h[/quote]


            Hi,

            Yep, for Part (B), you are correct.

            Thanks[/quote]
            thanks but without your guide, i also got stuck

            1 Reply Last reply Reply Quote 0
            • ozoraO Offline
              ozora
              last edited by

              ozora:
              help needed. looks simple but my answer is fraction which must be wrong.

              Tom had 295 more sweets than John.
              After Tom gave away 2/5 of the sweets he had and John gave away 2/3 of the sweets, Tom had 329 more sweets than John.
              how many sweets did they have altogether at first?
              I redo the model.
              is Tom's sweets = 523
              and John's sweets = 228.
              can anyone check if my answer is correct.

              1 Reply Last reply Reply Quote 0
              • O Offline
                Oldschool
                last edited by

                ozora:
                ozora:

                help needed. looks simple but my answer is fraction which must be wrong.

                Tom had 295 more sweets than John.
                After Tom gave away 2/5 of the sweets he had and John gave away 2/3 of the sweets, Tom had 329 more sweets than John.
                how many sweets did they have altogether at first?

                I redo the model.
                is Tom's sweets = 523
                and John's sweets = 228.
                can anyone check if my answer is correct.

                Hi,

                Nope.

                Maybe you want to change to LCM of 5 and 3, which is 15 for easier approach.

                Regards

                1 Reply Last reply Reply Quote 0
                • P Offline
                  php
                  last edited by

                  ozora:
                  ozora:

                  help needed. looks simple but my answer is fraction which must be wrong.

                  Tom had 295 more sweets than John.
                  After Tom gave away 2/5 of the sweets he had and John gave away 2/3 of the sweets, Tom had 329 more sweets than John.
                  how many sweets did they have altogether at first?

                  I redo the model.
                  is Tom's sweets = 523
                  and John's sweets = 228.
                  can anyone check if my answer is correct.

                  Using LCM 5,3 i.e. 15

                  Before
                  Tom -> 15units + 295
                  John -> 15units

                  Gave Away
                  Tom -> 2/5 (15units + 295) = 6units + 118
                  John -> 2/3 (15units) = 10units

                  Left
                  Tom -> 15units+295-6units-118 = 9units + 177
                  John -> 15units - 10units = 5 units

                  9units+177 - 5units = 329
                  4units = 152
                  1unit = 38

                  15units+295+15units = 38x30 + 295 = 1435

                  1 Reply Last reply Reply Quote 0
                  • MathIzzzFunM Offline
                    MathIzzzFun
                    last edited by

                    YumYum:
                    Hi, one more Qn:


                    Derrick and John shared a sum of money.
                    Derrick received 2/7 of the sum of money.
                    Both of them spent part of their money and saved the rest.
                    The amount of money Derrick spent was 3/5 the amount he saved.
                    The amount of money John spent was 1/9 the amount he saved.
                    Express the amount of money Derrick spent as a ratio of the amount John saved. thks!

                    Derrick's money : John's money = 2 : 5 --> 8u : 20u

                    Derrick's spending : Derrick's savings --> 3u : 5u
                    John's spending : John's savings --> 2u : 18u

                    Derrick's spending : John's savings = 3u : 18u = 1 : 6

                    cheers.

                    1 Reply Last reply Reply Quote 0
                    • ozoraO Offline
                      ozora
                      last edited by

                      php:
                      ozora:

                      [quote=\"ozora\"]help needed. looks simple but my answer is fraction which must be wrong.

                      Tom had 295 more sweets than John.
                      After Tom gave away 2/5 of the sweets he had and John gave away 2/3 of the sweets, Tom had 329 more sweets than John.
                      how many sweets did they have altogether at first?

                      I redo the model.
                      is Tom's sweets = 523
                      and John's sweets = 228.
                      can anyone check if my answer is correct.

                      Using LCM 5,3 i.e. 15

                      Before
                      Tom -> 15units + 295
                      John -> 15units

                      Gave Away
                      Tom -> 2/5 (15units + 295) = 6units + 118
                      John -> 2/3 (15units) = 10units

                      Left
                      Tom -> 15units+295-6units-118 = 9units + 177
                      John -> 15units - 10units = 5 units

                      9units+177 - 5units = 329
                      4units = 152
                      1unit = 38

                      15units+295+15units = 38x30 + 295 = 1435[/quote]Saw my mistakes. thanks

                      1 Reply Last reply Reply Quote 0
                      • Suz855S Offline
                        Suz855
                        last edited by

                        Need help with following speed qns


                        Q1) A car started travelling from Town A to Town B at 9a.m. At the same time, the lorry started travelling from Town B to Town A. The car had a speed of 20km/h faster than the lorry. The car passed the lorry 45km away from the midpoint. Given that the car reached Town B at 3p.m., what time would the lorry reached Town A? :?

                        Q2) At 11a.m., Mr T left from Town X & drove towards Town Y at an ave speed of 80km/h. 15 min later, Mr R left Town Y and drove along the same route as Mr T towards Town X. After travelling 120km, Mr R passed Mr T.
                        a) What was the ave speed at which Mr R travelled?
                        b) How far apart were there at 3.20p.m.? Express your answer as a fraction.
                        :sad: :imdrowning: :frustrated:




                        Thanks

                        1 Reply Last reply Reply Quote 0

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