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    Tutor MathsGuru: Ask me for your burning Maths questions!

    Scheduled Pinned Locked Moved Primary Schools - Academic Support
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    • MathIzzzFunM Offline
      MathIzzzFun
      last edited by

      concern_mum:
      hi, can you show me in detail how to solve below question?


      The ratio of Atrirah's monety to Malek's money was 3:5
      After Malek spent $42, the ratio of Atirah's money to Malek's money became 9:8
      How much money did Malek have left?
      Hi

      Only Malek spent money, so Atrirah's money will remain the same. So, make Atrirah's share the same - drawing a model will help to \"see\".

      After Malek spent $42, Atrirah : Malek = 9u : 8u
      Before Malek spent the money, Atrirah : Malek = 3: 5 = 9u:15u
      So, Malek spent 15u-8u=7u = $42, 1u = $6.
      Malek had 15u left --> 15 x $ 6 = $90.

      cheers.

      1 Reply Last reply Reply Quote 0
      • MathIzzzFunM Offline
        MathIzzzFun
        last edited by

        concern_mum:
        hi, 1 more question i need help.


        There are twice as many 20 cent coin as 50 cents coins in a piggy bank. The total value of the coins is $63. How manu coins are there altogether.
        Hi

        There are twice as many 20 cents coin as 50 cents.
        Group 2x 20c and 1x50c into one group.
        Total amount in each group = 2x$0.20 + $0.50 = $0.90
        $63/ $0.90 = 70 --> there are 70 groups.

        Since there 3 coins (2 x 20c + 1x50c) in each group, total number of coins = 70 x 3 = 210

        cheers.

        1 Reply Last reply Reply Quote 0
        • C Offline
          concern_mum
          last edited by

          hi, i have another 2 questions that need your help.


          1. 608 children took part in a skipping competition. Altogether 110 Gold awards were presented to 1/5 of the boys and 1/7 of the grils. How many boys took part in the competition.

          2. The ratio of Steven’s cards to Benny’s cards was 3:4. After Steven bought another 9 cards and Benny lost 18 cards, the ratio became 3:2. Find the total number of cards Steven and Benny had at first.

          Thank you.

          1 Reply Last reply Reply Quote 0
          • E Offline
            Essential
            last edited by

            Dear concern mum some one posted this before. Please check

            1 Reply Last reply Reply Quote 0
            • C Offline
              concern_mum
              last edited by

              Hi, sorry to bother you. I couldn’t find this posted. Could you advise me when was the date it was posted?

              1 Reply Last reply Reply Quote 0
              • E Offline
                Essential
                last edited by

                I suppose is page 380.

                1 Reply Last reply Reply Quote 0
                • C Offline
                  concern_mum
                  last edited by

                  hi, i search from page 370 till 390 and still couldn’t find the solution.

                  1 Reply Last reply Reply Quote 0
                  • MathIzzzFunM Offline
                    MathIzzzFun
                    last edited by

                    concern_mum:
                    hi, i have another 2 questions that need your help.


                    1. 608 children took part in a skipping competition. Altogether 110 Gold awards were presented to 1/5 of the boys and 1/7 of the grils. How many boys took part in the competition.

                    2. The ratio of Steven's cards to Benny's cards was 3:4. After Steven bought another 9 cards and Benny lost 18 cards, the ratio became 3:2. Find the total number of cards Steven and Benny had at first.

                    Thank you.
                    Hi

                    q2 is similar to the one you posted earlier - \"Atrirah & Malek\".

                    Initially, Steven's cards : Benny's cards = 3u : 4u
                    After Steven bought 9 cards --> Steven's cards = 3u + 9
                    Benny lost 18 cards --> Benny's cards = 4u - 18
                    3u+9 : 4u-18 = 3:2

                    Cross-multiply --> 6u + 18 = 12u - 54, 6u = 72, 1u = 12 .. I think you can carry on from here.

                    q1 can be solved using the \"stars & moons\" method the students learned in P1-P3.

                    Girls = * * * * * * * } 608
                    Boys = # # # # # }

                    * + # = 110,
                    so * * = 608 - 5 x 110 = 58,
                    * = 29
                    # = 110 - 29 = 81

                    Boys = 5 # = 405

                    cheers.

                    1 Reply Last reply Reply Quote 0
                    • C Offline
                      concern_mum
                      last edited by

                      hi Guru, thank you for your clear explanation. Q1 seems to be a problem. I have a feeling that the information is insufficient for this question.

                      1 Reply Last reply Reply Quote 0
                      • MathIzzzFunM Offline
                        MathIzzzFun
                        last edited by

                        concern_mum:
                        hi Guru, thank you for your clear explanation. Q1 seems to be a problem. I have a feeling that the information is insufficient for this question.

                        Hi

                        u r welcome.. I am no guru la.. just trying to help out here.

                        q1 type of problem sums are quite common. for eg.

                        http://www.flickr.com/photos/62167097@N02/6160671185/in/photostream

                        http://www.flickr.com/photos/62167097@N02/6175230767/in/photostream

                        cheers.

                        1 Reply Last reply Reply Quote 0

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