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    O-Level Additional Math

    Scheduled Pinned Locked Moved Secondary Schools - Academic Support
    809 Posts 301 Posters 488.7k Views 1 Watching
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    • R Offline
      red rose
      last edited by

      Need help to solve this.


      x - 2/x + 3 = 2x^2 + x - 10/x^2 + 6x + 9

      I only managed to get x = -2, but the answer key says the answer should be x = 2 or x = -2. Please advise.

      Thank you in advance.

      1 Reply Last reply Reply Quote 0
      • J Offline
        jtoh
        last edited by

        Hi red rose,


        I'm a little confused with the presentation of the question - limitations of typing out the question. šŸ˜› Could you please clarify if it's :

        x - 2/x + 3 or (x-2)/(x+3)

        Similarly for the right hand side? Thanks.

        1 Reply Last reply Reply Quote 0
        • R Offline
          red rose
          last edited by

          jtoh:
          Hi red rose,


          I'm a little confused with the presentation of the question - limitations of typing out the question. šŸ˜› Could you please clarify if it's :

          x - 2/x + 3 or (x-2)/(x+3)

          Similarly for the right hand side? Thanks.
          Hi! It's with brackets. Eg. (x-2) divided by (x+3)

          Thanks! šŸ˜„

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          • J Offline
            jtoh
            last edited by

            Thanks red rose. So the right hand side is (2x^2 + x - 10)/(x^2 + 6x + 9)?

            1 Reply Last reply Reply Quote 0
            • R Offline
              red rose
              last edited by

              jtoh:
              Thanks red rose. So the right hand side is (2x^2 + x - 10)/(x^2 + 6x + 9)?

              Yes! :thankyou:

              1 Reply Last reply Reply Quote 0
              • J Offline
                jtoh
                last edited by

                Hi red rose, I only managed to get x = -2 too. Could the answer sheet be wrong? Is this question from a workbook?

                1 Reply Last reply Reply Quote 0
                • R Offline
                  red rose
                  last edited by

                  jtoh:
                  Hi red rose, I only managed to get x = -2 too. Could the answer sheet be wrong? Is this question from a workbook?

                  Nope. It's from a Sec 2 IP school revision worksheet. Thanks for trying anyway. The curious thing is, +2 works too when substituted into the equation.
                  🤷

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                  • J Offline
                    jtoh
                    last edited by

                    red rose:
                    jtoh:

                    Hi red rose, I only managed to get x = -2 too. Could the answer sheet be wrong? Is this question from a workbook?


                    Nope. It's from a Sec 2 IP school revision worksheet. Thanks for trying anyway. The curious thing is, +2 works too when substituted into the equation.
                    🤷

                    Hmm... are we approaching the question wrongly from our archaic math training? Could your dd get the answer? I'll ask my dd to try it later. Is this the school's worksheet?

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                    • R Offline
                      red rose
                      last edited by

                      jtoh:
                      red rose:

                      [quote=\"jtoh\"]Hi red rose, I only managed to get x = -2 too. Could the answer sheet be wrong? Is this question from a workbook?


                      Nope. It's from a Sec 2 IP school revision worksheet. Thanks for trying anyway. The curious thing is, +2 works too when substituted into the equation.
                      🤷

                      Hmm... are we approaching the question wrongly from our archaic math training? Could your dd get the answer? I'll ask my dd to try it later. Is this the school's worksheet?[/quote]My dd got -2, which was why she approached me to see if I had another approach.

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                      • J Offline
                        jtoh
                        last edited by

                        Me suspects the answer key could be wrong. šŸ™‚ I've PM you.

                        1 Reply Last reply Reply Quote 0

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