Logo
    • Education
      • Pre-School
      • Primary Schools Directory
      • Primary Schools Articles
      • P1 Registration
      • DSA
      • PSLE
      • Secondary
      • Tertiary
      • Special Needs
    • Lifestyle
      • Well-being
    • Activities
      • Events
    • Enrichment & Services
      • Find A Service Provider
      • Enrichment Articles
      • Enrichment Services
      • Tuition Centre/Private Tutor
      • Infant Care/ Childcare / Student Care Centre
      • Kindergarten/Preschool
      • Private Institutions and International Schools
      • Special Needs
      • Indoor & Outdoor Playgrounds
      • Paediatrics
      • Neonatal Care
    • Forum
    • ASKQ
    • Register
    • Login

    O-Level Additional Math

    Scheduled Pinned Locked Moved Secondary Schools - Academic Support
    809 Posts 301 Posters 511.2k Views 1 Watching
    Loading More Posts
    • Oldest to Newest
    • Newest to Oldest
    • Most Votes
    Reply
    • Reply as topic
    Log in to reply
    This topic has been deleted. Only users with topic management privileges can see it.
    • D Offline
      dazzlego
      last edited by

      Need help to solve this question


      Find the possible value of X if |X+1| = 2X-3

      Thanks

      1 Reply Last reply Reply Quote 0
      • D Offline
        dazzlego
        last edited by

        Can someone tell me what is the answer for this question?


        Find the possible value of X if |X+1| = 2X-3

        Thanks

        1 Reply Last reply Reply Quote 0
        • V Offline
          verykiasumummy
          last edited by

          dazzlego:
          Need help to solve this question


          Find the possible value of X if |X+1| = 2X-3

          Thanks
          hi dazzlego,

          x=4, my ds1 told me that...

          x+1 = 2x-3
          1 = x-3
          4 = x
          x = 4

          1 Reply Last reply Reply Quote 0
          • N Offline
            neowanz
            last edited by

            verykiasumummy:
            dazzlego:

            Need help to solve this question


            Find the possible value of X if |X+1| = 2X-3

            Thanks

            hi dazzlego,

            x=4, my ds1 told me that...

            x+1 = 2x-3
            1 = x-3
            4 = x
            x = 4

            Pls do include this also,
            X+1= -(2x-3)
            3x=2
            X=2/3 (reject)

            Thks 🙂

            1 Reply Last reply Reply Quote 0
            • D Offline
              dazzlego
              last edited by

              neowanz:
              verykiasumummy:

              [quote=\"dazzlego\"]Need help to solve this question


              Find the possible value of X if |X+1| = 2X-3

              Thanks

              hi dazzlego,

              x=4, my ds1 told me that...

              x+1 = 2x-3
              1 = x-3
              4 = x
              x = 4

              Pls do include this also,
              X+1= -(2x-3)
              3x=2
              X=2/3 (reject)

              Thks :)[/quote]Yeah u should include that steps. Thanks neowanz and verykiasumummy :celebrate:

              1 Reply Last reply Reply Quote 0
              • E Offline
                edwin-tan
                last edited by

                dazzlego:
                Can someone tell me what is the answer for this question?


                Find the possible value of X if |X+1| = 2X-3

                Thanks
                X + 1 > 0

                Hence, 2X - 3 > 0

                In order for that to happen, X > 2

                Drop the absolute sign and just solve X + 1 = 2X - 3, X = 4

                1 Reply Last reply Reply Quote 0
                • D Offline
                  dazzlego
                  last edited by

                  edwin-tan:
                  dazzlego:

                  Can someone tell me what is the answer for this question?


                  Find the possible value of X if |X+1| = 2X-3

                  Thanks

                  X + 1 > 0

                  Hence, 2X - 3 > 0

                  In order for that to happen, X > 2

                  Drop the absolute sign and just solve X + 1 = 2X - 3, X = 4

                  Yeah, I solved it already yesterday.
                  It is not exactly X > 2 right? It is X > 3/2. That's why the other solution (i.e. X = 2/3) is invalid.

                  Thanks anyway. :hi5:

                  1 Reply Last reply Reply Quote 0
                  • D Offline
                    Daddy
                    last edited by

                    Hi,

                    Need someon help on this sec 1 question. Thanks

                    3 workers, Alpha, Beta and Charlie take 6 hrs, 7 hrs and 9 hrs respectively to paint a hall alone. All 3 of them decided to work together to complete the painting of the hall. After 2 hrs, Alpha and Beta left away. How long does it take for Charlie to complete the painting?

                    Thanks you…

                    1 Reply Last reply Reply Quote 0
                    • D Offline
                      dazzlego
                      last edited by

                      Daddy:
                      Hi,

                      Need someon help on this sec 1 question. Thanks

                      3 workers, Alpha, Beta and Charlie take 6 hrs, 7 hrs and 9 hrs respectively to paint a hall alone. All 3 of them decided to work together to complete the painting of the hall. After 2 hrs, Alpha and Beta left away. How long does it take for Charlie to complete the painting?

                      Thanks you...
                      Hi Daddy,

                      A can do 1/6 of the work in 1 hour
                      B can do 1/7 of the work in 1 hour
                      C can do 1/9 of the work in 1 hour
                      A,B,C can do 1/6 + 1/7 + 1/9 = 53/126 of the work in 1 hour
                      In 2 hours, A,B,C can do 106/126 of the work
                      Thus, C need to do 20/126 = 10/63 of the work by himself
                      10/63 ÷ 1/9 = 10/7 hours

                      Cheers :celebrate:

                      1 Reply Last reply Reply Quote 0
                      • D Offline
                        Daddy
                        last edited by

                        Thanks dazzlego,


                        I still not very clear on the hightlight

                        In 2 hours, A,B,C can do 106/126 of the work
                        Thus, C need to do 20/126 = 10/63 of the work by himself
                        10/63 ÷ 1/9 = 10/7 hours

                        Can I write the answer 1.43hrs instead of 10/7hrs?

                        Thanks.

                        1 Reply Last reply Reply Quote 0

                        Hello! It looks like you're interested in this conversation, but you don't have an account yet.

                        Getting fed up of having to scroll through the same posts each visit? When you register for an account, you'll always come back to exactly where you were before, and choose to be notified of new replies (either via email, or push notification). You'll also be able to save bookmarks and upvote posts to show your appreciation to other community members.

                        With your input, this post could be even better 💗

                        Register Login
                        • 1
                        • 2
                        • 54
                        • 55
                        • 56
                        • 57
                        • 58
                        • 80
                        • 81
                        • 56 / 81
                        • First post
                          Last post



                        Online Users

                        Statistics

                        3

                        Online

                        211.2k

                        Users

                        34.5k

                        Topics

                        1.8m

                        Posts
                        Popular Topics
                        New to the KiasuParents forum? Tips and Tricks!
                        P1 Registration 2027 Changes
                        DSA Discussions and Strategies
                        PSLE Discussions and Strategies
                        How much do you spend on the kids' tuition/enrichments?
                        SkillsFuture course recommendations

                          About Us Contact Us forum Terms of Service Privacy Policy