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    O-Level Additional Math

    Scheduled Pinned Locked Moved Secondary Schools - Academic Support
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    • G Offline
      Guan Hui
      last edited by

      fully agreed=) not much secondary questions here though

      1 Reply Last reply Reply Quote 0
      • E Offline
        emerald
        last edited by

        Hi Guan Hui, pls help with the foll:


        Find the smallest no. x, such that when it is divided by the nos. from 2 to 10, the remainder is always one less than the divisor.

        TIA.

        1 Reply Last reply Reply Quote 0
        • G Offline
          Guan Hui
          last edited by

          emerald:
          Hi Guan Hui, pls help with the foll:


          Find the smallest no. x, such that when it is divided by the nos. from 2 to 10, the remainder is always one less than the divisor.

          TIA.
          haha thanks for asking=) out of business for quite long hehheh.
          from the question, the way to solve this is to find LCM from 2-10 and minus it by 1.

          the LCM is 2520( if you do not know the lcm method pls reply to this post i will do a video response for you emerald)

          so the answer is 2520-1=2519

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          • E Offline
            emerald
            last edited by

            Thanks once again. šŸ˜„

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            • G Offline
              Guan Hui
              last edited by

              you are welcome šŸ˜„

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              • O Offline
                OK Lor
                last edited by

                Hi Guan Hui,


                Please help:
                y in term of x for: 3^y = 4[3^(x-2)] - 1.

                Thanks.

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                • G Offline
                  Guan Hui
                  last edited by

                  HI oklor=D

                  Heres Your solution=)
                  http://www.postimage.org/image.php?v=gxHyAlJ

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                  • O Offline
                    OK Lor
                    last edited by

                    Guan Hui:
                    HI oklor=D

                    Heres Your solution=)
                    http://www.postimage.org/image.php?v=gxHyAlJ
                    Hi Guan Hui,
                    Thanks. The original question was:
                    Solve the simultaneous equation 64(4^y) = 16^x and 3^y = 4[3^(x-2)] - 1.

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                    • G Offline
                      Guan Hui
                      last edited by

                      Bonjour Oklor,

                      Heres the solution=)
                      http://www.postimage.org/image.php?v=TsFjbFS

                      http://www.postimage.org/image.php?v=PqhA1ci

                      http://www.postimage.org/image.php?v=gxJs6K0

                      http://www.postimage.org/image.php?v=TsFm7fr

                      http://www.postimage.org/image.php?v=gxJsyaA

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                      • O Offline
                        OK Lor
                        last edited by

                        Hi Sir,


                        Thanks.

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