O-Level Additional Math
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the above method is very nice.
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Does your child need practice on Expansion and Factorisation, especially the more challenging questions? It is a key technique that needs to be honed for the O Levels.
Practice Hwa Chong Institution Expansion and Factorisation (Sec 2, IP) here.
http://mathtuition88.wordpress.com/2013/05/07/sec-2-ip-hci-revision-1-expansion-and-factorisation/ -
Need help to solve the following question.
Log (base 9) a = log (base 12) b =log (base 16) (a+b), find the value of a/b.
TIA -
PiggyLalala:
Dear Sir/Mdm,Need help to solve the following question.
Log (base 9) a = log (base 12) b =log (base 16) (a+b), find the value of a/b.
TIA
Please see my answer at http://mathtuition88.com/2013/05/12/o-level-logarithm-question-challenging/
Best wishes. -
mathtuition88:
:thankyou: very much for the solution. Was using the wrong approach- change of base n made a big mess... haha..
Dear Sir/Mdm,PiggyLalala:
Need help to solve the following question.
Log (base 9) a = log (base 12) b =log (base 16) (a+b), find the value of a/b.
TIA
Please see my answer at http://mathtuition88.com/2013/05/12/o-level-logarithm-question-challenging/
Best wishes.
I did not think of letting y = the log expression n change it into its exponential form.
Thank you so much. -
PiggyLalala:
:thankyou: very much for the solution. Was using the wrong approach- change of base n made a big mess... haha..
Dear Sir/Mdm,mathtuition88:
[quote=\"PiggyLalala\"]Need help to solve the following question.
Log (base 9) a = log (base 12) b =log (base 16) (a+b), find the value of a/b.
TIA
Please see my answer at http://mathtuition88.com/2013/05/12/o-level-logarithm-question-challenging/
Best wishes.
I did not think of letting y = the log expression n change it into its exponential form.
Thank you so much.[/quote]You are welcome, glad to help.
That question is quite creative, enjoyed solving it. -
My son asks me a Math question from his MY Revision Paper which I need help. Find it rather challenging! Or if there is something not right? Could anyone out there kindly help to solve, thanks in advance.
" A father in his will left all his money to his children as such: $1000 and 1/10 of what then remains to the first born; then $2000 and 1/10 of what then remains to the second; then $3000 and 1/10 of what then remains to the third born; and so no. When this was done each child had the same amount. How many children were there? " -
Qwertymum:
Father's money [-1000-][1U][-------------------9U-------------------]My son asks me a Math question from his MY Revision Paper which I need help. Find it rather challenging! Or if there is something not right? Could anyone out there kindly help to solve, thanks in advance.
\" A father in his will left all his money to his children as such: $1000 and 1/10 of what then remains to the first born; then $2000 and 1/10 of what then remains to the second; then $3000 and 1/10 of what then remains to the third born; and so no. When this was done each child had the same amount. How many children were there? \"
Father's money [-1000-][1U][--2000--][1P][-----------9P-----------]
Father's money = 1000 + 10U
the money that 1st child will receive = 1000 + 1U
the money that 2nd child will receive = 2000 + 1P
Each child will receive the same amount of money
1000 + 1U = 2000 + 1P
1U = 1000 + 1P ------------(1)
9U = 2000 + 10P ----------(2)
(1)*9 , 9U = 9000 + 9P ---(3)
(2) = (3) ,
2000 + 10P = 9000 + 9P
1P = 7000
From (1)
1U = 1000 + 1P = 1000 + 7000 = 8000
Father's money = 1000 + 10U = 1000 + 10*8 = 81000
the amount of money that each child will receive = 1000 + 1U = 9000
No of children = 81000 / 9000 = 9 -
jieheng:
Father's money [-1000-][1U][-------------------9U-------------------]Qwertymum:
My son asks me a Math question from his MY Revision Paper which I need help. Find it rather challenging! Or if there is something not right? Could anyone out there kindly help to solve, thanks in advance.
\" A father in his will left all his money to his children as such: $1000 and 1/10 of what then remains to the first born; then $2000 and 1/10 of what then remains to the second; then $3000 and 1/10 of what then remains to the third born; and so no. When this was done each child had the same amount. How many children were there? \"
Father's money [-1000-][1U][--2000--][1P][-----------9P-----------]
Father's money = 1000 + 10U
the money that 1st child will receive = 1000 + 1U
the money that 2nd child will receive = 2000 + 1P
Each child will receive the same amount of money
1000 + 1U = 2000 + 1P
1U = 1000 + 1P ------------(1)
9U = 2000 + 10P ----------(2)
(1)*9 , 9U = 9000 + 9P ---(3)
(2) = (3) ,
2000 + 10P = 9000 + 9P
1P = 7000
From (1)
1U = 1000 + 1P = 1000 + 7000 = 8000
Father's money = 1000 + 10U = 1000 + 10*8 = 81000
the amount of money that each child will receive = 1000 + 1U = 9000
No of children = 81000 / 9000 = 9
:thankyou: Wow! That's fast. Thanks a lot. -
Solving cubic equations is taught in Secondary 3 Additional Maths.
There are three methods:
1) Synthetic division
2) Comparing coefficients
3) Long division
I've two videos on demonstrating how to solve a cubic equation using the first two methods.
I believe this post will be useful for you.
http://www.singaporeolevelmaths.com/2013/04/21/amaths-solve-cubic-equation-by-synthetic-division-or-comparing-coefficients-video/
Cheers!
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