MathIzzzFun:Despair:Dear all, I require help with this Speed question.
A truck started its journey from Village Tiku to Village Chuka at 16 30. At the same time, a bus started travelling from Village Chuka to Village Tiku.
The ratio of the truck's speed to the bus's speed is 8:3. At 17 00 the two vehicles passed each other. The truck increased its speed and reached Village Chuka at 17 20 while the bus increased its speed by 18km/h.
When the truck reached Village Chuka, the bus is still 40 km away from Village Tiku.
What is the distance between the two villages?
Thank you in advance.
Hi
May I know the source of this problem sum? The setter probably adapted the problem by changing the numbers..firstly, after the truck and bus passed each other, the truck reduced its speed rather than increased its speed because if it had continued at original speed, it would hve reached the destination in 3/8 x 30min = 11.25min.
Ratio of distance travelled by truck n bus = 8u : 3u, total distance 11u.
after truck and bus passed each other, truck took 20 min to reach Chuka,and the bus is still 40 km from Tiku.
If bus had continued its original speed, the distance it would travel = 20/30 x 3u =2u, since the bus's speed is increased by 18km/h, it would travel 18x20/60 = 6km more, ie it travelled a distance of 2u + 6km after passing the truck, and it was 40km from Tiku.
Distance from Tiku to the \"meeting point\" = 8u
8u = 2u + 6km + 40km, 6u = 46km, 11u = 11/6 x 46 km = 84 1/3 km
Distance between Tiku and Chuka = 84 1/3 km.
cheers.
Hi, sorry, I do not know the source
But I think it must be from some Preliminary Paper. This was a question from my teacher. I will check with her tomorrow and get back to you.
Thank you once more for solving my question.