Me TIme for me is running along punggol waterway in the evening. Peaceful and quiet.

deon629:

Pls help. TIA.


Charlie had 148 pieces of $2 and $5 notes. She spent 60% of her $5 notes to buy a bag and then her mother gave her another six $2 notes. As a result, the number of $2 notes was thrice as many as the number of $5 notes left. Find the amount of money Charlie had left.

Let the number of 40% leftover $5 notes be 4u,
Then originally he would had 10u of $5 notes.

Since $2 notes is 3 times of leftover $5 notes, then the number of $2 notes is 12u. (From 4u x 3)

Including the six $2 notes his mother gave, the total number of notes he had before buying the bag is 154
10u + 12u = 154
22u = 154
u = 7

Number of $5 notes left = 4u =28
Value of $5 notes = 28 x 5 = $140

Number of $2 notes left = 12u = 84
Value of $2 notes = 84 x 2 = $168

Total value = $140 + $$168 = $308 ###

fillie_28:

On waiting list still got chance? My son only got waiting list, that is same as rejection letter?

Still got chance, as long as put in 1st choice when time comes for selection. There bound to have some students who will give up their SST CO for other schools CO.

wilburlim:

Thank you! I have one more question--


When she increased her spending by 30%, her savings decreased by 25%.

The above statement is mathematically saying this,
30% of $2500 = 1/4 of Saving at first

So \"saving at first\" is ________ ?

Hope you can solve from here.


Answer $5500

SOS mum:

Hi, ps help. Many tks and God Bless:)


Yee Leng has some twenty cents and fifty cents coins.
2/3 of the total value of the twenty cents coins is the same as 1/2 of the total value of the fifty cents coins. If Yee Leng spends 4 fifty cent coins, the value of the twenty cents coins and the value of the remaining fifty cents coins will be the same. How many twenty cents coins does Yee Leng have?

The value of 2/3 twenty cent equals to half of fifty cents value, can be modelled as
Value of 20c = 3u
Value of 50c = 4u[quote]Becoz 2/3 of 3u = 2u, which is half of the value of 50c coins. Therefore value of 50c is 2u x 2 = 4u[/quote]Spent 4 fifty cent is just another way of saying he spent $2.

4u - 3u = $2
1u= $2

Value of 20c = 3u = $6

Number of 20c coins = 6/0.2 = 30 ##.

Let pupils that goes to school by bus and car altogether be 100u,

Then those by bus will be 70u and
by cars will be 30u

30u (by cars) are 1/5 of the schools enrolment.
Therefore school enrolment is = 30u X 5 = 150u

Those who walk = 150u - 100u = 50u
50u = 1185
u = 23.7

school enrolment = 150u = 3555 ###

BigDevil:

Ender:

[quote=\"questionable_i\"]Can anyone help me with these questions? Thank you

http://i.imgur.com/PchjKFW.jpg\">

13)
(43+∠CDE) + (48 +∠DCE) = 180
∠CDE + ∠DCE = 180 - 43 - 48 = 89

(∠CDE + ∠DCE) + ∠CED = 180
89 + ∠CED = 180
∠CED = 180 - 89 = 101 ##

http://i63.tinypic.com/24loh3q.jpg\">
∠CED = 43 + 48 = 91

Ender made a calculation error.
180 - 89 = 91[/quote]Thanks for the correction... Reminds me to use calculator next time..

sushi88:

Q14, Catherine was 8 minutes faster than Betty, not longer.

My bad, read the question wrongly.

Answer should be 2) then,

questionable_i:

Can anyone help me with these questions? Thank you

http://i.imgur.com/2OP0dC4.jpg\">
http://i.imgur.com/AXeAlgL.jpg\">
http://i.imgur.com/ESQR98K.jpg\">

14) Straigth away we were givien Catherine swam 28 mins and Betty 37 mins (9 minute longer) That means it's either choice 1 or 2.

Betty ran 7.5km/h, that translate to 15/7.5 = 2hrs, which is 120mins. and Catherine is 8 minutes l̶o̶n̶g̶e̶r̶ faster, i.e. 1̶2̶8̶ 112 minutes.
Answer (̶1̶)̶ (2) ###

Note: Strikethrough the original mistake.

15)
Diameter is 4cm
One row, he can cut = 60/4 = 15 circles

one column he can cut h/4 circles

Total number of circles he can cut = 15 X h/4 = 3.75h ###

26)
AD : DC =? 3 : 2 => 6u and 4u respectively
AE = 3u and DF = 2u

Area of rectangle = 6u X 4u = 24u²

Area of Triangle = 1/2 X 3u X 2u = 3u²

Fraction 3u²/24u² => 1/8 ###

questionable_i:

Can anyone help me with these questions? Thank you

http://i.imgur.com/PchjKFW.jpg\">

12)
Total pupils in the beginning =>100u
boys = >40u
girls = > 60u

Remaining boys => 0.75 X 40u = 30u
Rwmaining girls => 0.9 X 60u = 54u

Total remaining => 30u + 54u = 84u

Percentage of remaining=> 84u/100u X 100 = 84% ##

13)
(43+∠CDE) + (48 +∠DCE) = 180
∠CDE + ∠DCE = 180 - 43 - 48 = 89

(∠CDE + ∠DCE) + ∠CED = 180
89 + ∠CED = 180
∠CED = 180 - 89 = 1̶0̶1̶ 91##