Go for it:

Dear Diamond123, from the schools you have chosen, I assume you are staying in the west? Have you looked at Clementi Town?


Anyway, whichever school you choose, please consider the distance from your house. From my sons' experience, you may need to stay quite late in school sometimes, and staying near the school makes it easier and not so tiring for you.

The COP is ACSI and Nan Hua are quite high. If you study there, you may just be at the middle or even bottom of the cohort. Try to choose some schools that your TScore will allow you to be near the top of the cohort.

i don't think I mind being last (with a T-score of 250) in the FIRST class rather than first (@ T-score of 200) in the LAST class.

All schools are good. My sons graduated from Kent Ridge, which took in COP 188 at that time, with very low O Level results. It depends on the effort you put into your studies.

My personal experiences tell me that SCHOOLS (basically the TEACHERS) do make a difference. So go for Nan Hua where possible.

emoh:

diamond 123:

Dear parents,

I need advice from all of you as my parents have no experience on choosing secondary school and they have not given me much advice. Until now I still have no idea of which school I should choose. I have a PSLE T-score of 243. My dream school is Nan Hua High School. However, I still have no idea on filling up the rest of the choices. Can parents here advice what other school I should choose other than Nan Hua?
Is it ok if I choose ACSI as my second choice? (I know ACSI is 248 but I also know that I could
appeal to my first and second choice if I am being posted to my third choice). I intend to put Fuhua Secondary School as my 3rd choice which is quite safe to go in with my T-score. Can parents please advice any other school I could choose? Thank you.

Does not make sense to put ACS(I) after Nan Hua as likely ACS(I) COP would be higher.

Do u also want to consider SJI (242) and Commonwealth (237) before you put Fuhua (234) ?

Suggest that you drop ACS(I) and include a school with COP <= 233.

PiggyLalala:

Daddy

In a basket, there are some oranges and apples. 2/7 of the apples is equal to 3/4 of the oranges. If there are 260 more apples than oranges, how many apples and oranges are there in the basket?


TIA!

This is a very common sum and it is not difficult. The trick is to make the 2 numerators the same.
2/7 = 6/21 of the apples is equal to 3/4= 6/8 of the oranges.

X X X X X X x x x x x x x x x x x x x x x - apples
X X X X X X x x - oranges

therefore (15-2) units =260
13 units =260
1 unit = 20
Apples =21 units =420
Oranges =8 units =160

I think you should just use 21 - 8 = 13u --> 260
(Model is also not necessary)

ozora:

Need some help on this catholic high prelim paper http://i58.tinypic.com/293dclu.jpg\">

Thanks

Note: Perimeter of shaded figure 1 = perimeter of shaded figure 2

72/4 = 18 cm

18 x 18 = 324 sq cm

324 - 180 = 144 sq cm

144/2 = 72 sq cm

The area of the isosceles triangle is 72 sq cm.

wi11anna:

Pls help me with this question. Thank you!

http://i59.tinypic.com/675nqc.jpg\">

Shaded area is basically circle + 2 semicircles (= small circle) - parallelogram

3.14 x 6 x 6 =113.04

3.24 x 3 x 3 = 28.26

12 x 6 = 72

113.04 + 28.26 - 72 = 69.3

The area of the shaded parts is 69.3 sq cm.

Jerico:

Hi, Can someone please help ? Tks in adv !


http://i62.tinypic.com/2v11160.jpg\">

70/100 x 120 = 84

50/100 x 84 = 42

2 + 5 = 7

42/7 = 6

2 : 5 = 12 : 30 (to get total of 42)

M N. O
----------
120 100. 84
-12. - 30. - 42
----------------
108. 70. 42

108 - 70'= 38u --> $167.20

1u --> 167.20/38 = $4.40

42u --> 4.40 x 42 = $184.80

Olivia had $184.80 savings in the end.

Jerico:

Hi, Can someone please help ? Tks in adv !


http://i57.tinypic.com/2mmtyps.jpg\">

30 x 30 = 900

1/2 x 8 x 8 = 32

4 x 32 = 128

8 x 8 = 64

900 - 128 + 64 = 708

708 x 12 = 8496

The volume of figure 1 is 8496 cu cm.

Jerico:

Hi, Can someone please help ? Tks in adv !


http://i57.tinypic.com/2mmtyps.jpg\">

30 x 30 = 900

1/2 x 8 x 8 = 32

4 x 32 = 128

8 x 8 = 64

900 - 128 + 64 = 708

708 x 12 = 8496

The volume of figure 1 is 8496 cu cm.

Jerico:

Hi, Can someone please help ? Tks in adv !


http://i57.tinypic.com/2w3xms1.jpg\">

X Y
----------------
7u. 5u
- 84.5. - 21.5
----------------
1p. 3p
----------------

7u - 84.5 --> 1p
21u - 253.5 --> 3p

5u - 21.5 --> 3p

21u - 253.5 --> 5u -21.5
16u --> 253.5 - 21.5
1u --> 232/16 = 14.5

5u --> 14.5 x 5 = 72.5

3p --> 72.5 - 21.5 = 51 kg

The mass of rice in sack Y at the end was 51 kg.

Alchemist:

Sorry - Ender - still a little unclear. If the gap when the ball comes into contact is 7/2 - then should it not be 38-7. I can't understand why it's 38-7-7.


Thanks

Kangkangteo:

[quote=\"Alchemist\"]Hi - would appreciate if some one could help me with this maths sum.

http://i57.tinypic.com/e7b6t0.jpg\">

The question is : Figure 1 is formed by rectangular box measuring 38 cm by 15 cm. Two identical white balls are fixed to the box at a point. Ball A, which is the same size as the 2 identical white balls, rolls anti clockwise along the sides of Figure 1 as shown in Figure 2. Find the distance ball A has rolled along figure 1 when it returns to it original position.

Please note that I have edited the solution.

When ball A comes into contact with the white ball, there is a gap of 7/2 cm (radius) which I forgot to account for.

38 - 7 - 7 = 24

24 x 2 + 15 x 2 = 78 cm

3.14 x 7 = 21.98 cm

78 + 21.98 = 99.98 cm

[/quote]When ball A comes into contact with the white ball, it does not cover the diameter of white ball plus the 2 radii of ball A. So you need to - 7 - 7.