oosh:

Hi,


Needed some help on this question.

Jimmy runs 4km/h faster than he walks. He walks 1 1/2hr and runs the rest of the time over a distance of 6Km. If Jimmy walks as fas as he runs, find the amount of time he spends running.

Answer given = 1/2hr but my answer is 3/4hr. Will greatly appreciate any assistance.

Hi, appreciate any help :thankyou:

mujin:

oosh:

Hi,


Pls help to solve this question:

Jimmy and Tony drove 45Km from the library to the swimming pool. Tony started his journey 24mins later than Jimmy. Both of them reached the swimming pool at the same time. If Jimmy's average speed was 50km/h, find Tony's average speed (Ans: 90Km/h)

TIA

Jimmy : 50km/h = 50km/60min
45/50x60min = 54 min (jimmy travelled for 54 min)

Tony travelled for 54-24 min = 30 min

45km/30min = 45km/0.5h = 90km/h

HI,

Thanks so much. :grphug:

MathIzzzFun:

oosh:

Please help


Sean earns a% more than Alice. Cathy earns 30% less than Alice. If Alice earns $1500, what is the total amount of money earned by Alice, Cathy and Sean?
(Answer: $(4050 + 15a)

TIA

Alice --> $1500
Cathy --> 0.7 x $1500 = $1050
Sean --> (1+a/100) x $1500 = $1500 + 15a
Total --> $(4050+15a)

cheers.

Hi,

Thanks for your kind help. :salute:

Hi,


Pls help to solve this question:

Jimmy and Tony drove 45Km from the library to the swimming pool. Tony started his journey 24mins later than Jimmy. Both of them reached the swimming pool at the same time. If Jimmy’s average speed was 50km/h, find Tony’s average speed (Ans: 90Km/h)

TIA

Please help


Sean earns a% more than Alice. Cathy earns 30% less than Alice. If Alice earns $1500, what is the total amount of money earned by Alice, Cathy and Sean?
(Answer: $(4050 + 15a)

TIA

Hi,


Needed some help on this question.

Jimmy runs 4km/h faster than he walks. He walks 1 1/2hr and runs the rest of the time over a distance of 6Km. If Jimmy walks as fas as he runs, find the amount of time he spends running.

Answer given = 1/2hr but my answer is 3/4hr. Will greatly appreciate any assistance.

MathIzzzFun:

oosh:

Hi


Would greatly appreciate some help on this question:

Abel and Ben can build a model aircraft together in 4 days. Ben and Calvin can do the same job together in 1 1/2 times as many days. Abel and Calvin can complete the same job together in twice the number of days Ben and Calvin can do together. If the three boys decide to work together, how long will they take to complete their job?
(Answer: 4 Days)

:thankyou:

Work needed to complete job --> 12 units
A+B --> 4 days --> 3 units/day
B+C --> 1.5 x 4 days = 6 days --> 2 units/day
A+C --> 12 days --> 1 unit/day

Adding...
2 x (A+B+C) --> 6 units/day
(A+B+C) --> 3 units /day
12 units ---> 12/3 = 4 days

A,B and C will take 4 days to complete the job.

cheers.

Hi, thanks so much for your explanation. I can understand this better.

Michaelia0816:

Hi oosh,


A+B---> 4 days
[B]+C---> 1.5 days
[A]+C---> 1.5 days*2= 3 days

Let see,
A took 1.5 days more than B.
B---> (4-1.5)/2=1.125 days to complete
A---> 1.125+1.5=2.625 days to complete
C--->3-2.625=0.375 days to complete
B+A+C---> 4.125 days
4.125 days~ 4 days ( as it is on the 4 days)

Hi Michaelia, thanks do much for your help but I'm a bit confused coz you mentioned that B + C = 1.5days but the question said that they took 1 1/2 times as many days to complete the job...


Thanks for any assistance.

Hi


Would greatly appreciate some help on this question:

Abel and Ben can build a model aircraft together in 4 days. Ben and Calvin can do the same job together in 1 1/2 times as many days. Abel and Calvin can complete the same job together in twice the number of days Ben and Calvin can do together. If the three boys decide to work together, how long will they take to complete their job?
(Answer: 4 Days)

:thankyou:

efficient housekeeper


lousy caregiver (block head)