tianzhu:Hi
Three interesting Speed questions.
Best wishes
Q1
Last Monday, Danny walked from home to market. For the first 5 minutes, he was walking at an average speed of 35m/min. When he realized that he was going` to be late by 4 minutes, he quickly increased his speed by 10m/min. As a result, he was early by 2 minutes. Find the distance between market and home.
Q2
Jacki’s mum leaves home at 12.35pm every day and arrives 25 minutes later at his school to pick him up. She always cycles at the same speed along the same route. One day Jacki was dismissed early at 12.30pm, so he started walking home at 6km/h, hoping to meet her along the way. He met her at x and got onto her bicycle. They reached home 15 minutes earlier than before. How far did Jacki walked before his mum picked him up?
Q3
Tony and Charles took part in a car race. Tony drove at a speed of 90km/h. Both of them did not change their speed throughout the race. When Charles had covered 1/3 the distance, Tony was 15km in front of him. Tony reached the finishing line at 9.35 a.m. At what time did Charles reach the finishing line?
Solution for question 1
New speed after 5 minutes------35 m/min+10 m/min=45 m/min
Slower Speed:Faster Speed
35 : 45
7 : 9
Slower speed time : Faster speed time
9 : 7
35 m/min (4 minutes late)
<---------------------------------------->
[----------------------------------]
^<-------------------->
45 m/min (2 minutes early)
5 min
(35 m/min)
Difference in time ------- 4 + 2 =6
2u--------6
1u--------3
9u--------27
27min + 5 min(The first five minutes he walked in 35 m/min) = 32 min
32 x 35 = 1120
The distance is 1120 m