Hi can somebody help me with this qtn, thank you!
The volume of a block is 0.03 cubic metres, correct to the nearest 0.01 cubic metres. Find the greatest possible height of the block in metres.
Latest posts made by S-H
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RE: O-Level Elementary Math
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RE: O-Level Additional Math
Hi I can’t find where to put this question, this is a sec 2 maths question, can someone kindly help me with this, thank you!
(a) Solve the following inequality:-
4x - 3
------- < 5x + 2
7
(b) Write down the smallest integer that satisfies this inequality -
RE: Q&A - PSLE Math
Hi, can someone pls help, thks!
(a) solve the following inequality
4x-3
---------- < 5x + 2
7
(b) write down the smallest integer that satisfies this inequality -
RE: Q&A - PSLE Math
Can someone pls help, thanks!
(a) Solve the following inequality
4x-3
------- less than. 5x+2
7
(b) write down the smallest integer that satisfies this inequality -
RE: Q&A - PSLE Math
Jmaths.SG:
Understand, thank you very much!
Reduce 180 and 42 to multiples of prime numbers.S-H:
Please help the following qtn, thks!
Find the smallest positive integer, n, such that 42n is a multiple of 180
180 = 2 * 2 * 3 * 3 * 5
42 = 2 * 3 * 7
Some numbers must be multipled to 42 in order to become a multiple of 180.
These numbers must include at least one 2, one 3 and one 5, since these are missing from the prime numbers of 42.
The smallest n = 2*3*5 = 30.
Ans: 30 -
RE: Q&A - PSLE Math
Please help the following qtn, thks!
Find the smallest positive integer, n, such that 42n is a multiple of 180 -
RE: Q&A - PSLE Math
pirate:
Let the amount of work 1 man does in 1 day be U.S-H:
Hi Can someone help me with the following question, thank you!
5 men are hired to complete a job. If one more man is hired, the job can be completed 8 days earlier. Assuming that all the men work at the same rate, how many more men should be hired so that the job can be completed 28 days earlier?
Amount of work 5 men does in 1 day = 5U
Amount of work 6 men does in 1 day = 6U
Let the no. days required by 5 men to complete the job be D
Amount of work required to complete the job = 5U x D
5U x D = 6U x (D -
5UD = 6UD - 48U
48U = UD
48 = D
No. of days required by 5 men to complete the job = 48 days
Amount of work required to complete the job = 48 x 5U = 240U
To complete the job 28 days earlier = completing the job in 48 - 28 = 20 days
240U / 20 = 12U
No. of men required to complete the job in 20 days is 12
Therefore 12 - 5 = 7 more men should be hired to complete the job 28 days earlier.
Hi pirate,
Thank you for your help! :thankyou: -
RE: Q&A - PSLE Math
Hi Can someone help me with the following question, thank you!
5 men are hired to complete a job. If one more man is hired, the job can be completed 8 days earlier. Assuming that all the men work at the same rate, how many more men should be hired so that the job can be completed 28 days earlier? -
RE: Travel: Thailand - Bangkok
Hi, may I know what is his charges for a day tour (from morning 9am to 11pm) and also charges for airport transfer( for 4 adults). Thks!