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    • RE: Q&A - PSLE Math

      Snowball99:
      carebear:

      [quote=\"stary\"]Hi all, need help for the following questions šŸ™‚


      1) Mrs Yeo had 20% more books than Mdm Lim. Miss Tang had 40% fewer books than Mrs Yeo. Mrs Yeo and Mdm Lim gave Miss Tang some books in the ratio of 1:2. As a result, Miss Tang had 50% more books than before. Given that Miss Tang had 96 more books than Mdm Lim in the end, how many books did Miss Yeo give to Miss Tang?

      2)Last Monday morning, Edward walked from home to school. For the first 2 minutes, he was walking at an average speed og 40m/min. When he realised that he was going to be late by 3 minutes, he quickly increased his speed by 10m/min. As a result, he was early be 1 minute. Find the distance between his home to his school.[/quote

      I think you should use the ratio of speed and time. (inversely related) for the 2nd question.

      Speed:
      4:5
      Time:
      5:4
      The difference between the times is 4 minutes.
      Thus, 1u time = 4 min
      So,
      5u= 20 min
      Distance= 40m/min for 20 min
      = 800m

      Cheers,
      Snowball99




      http://www.flickr.com/photos/63342911@N03/6093555012/

      [/quote]

      posted in Primary 6 & PSLE
      S
      Snowball99
    • RE: Q&A - PSLE Math

      carebear:
      stary:

      Hi all, need help for the following questions šŸ™‚


      1) Mrs Yeo had 20% more books than Mdm Lim. Miss Tang had 40% fewer books than Mrs Yeo. Mrs Yeo and Mdm Lim gave Miss Tang some books in the ratio of 1:2. As a result, Miss Tang had 50% more books than before. Given that Miss Tang had 96 more books than Mdm Lim in the end, how many books did Miss Yeo give to Miss Tang?

      2)Last Monday morning, Edward walked from home to school. For the first 2 minutes, he was walking at an average speed og 40m/min. When he realised that he was going to be late by 3 minutes, he quickly increased his speed by 10m/min. As a result, he was early be 1 minute. Find the distance between his home to his school.



      I think you should use the ratio of speed and time. (inversely related)


      Speed:
      4:5
      Time:
      5:4
      The difference between the times is 4 minutes.
      Thus, 1u time = 4 min
      So,
      5u= 20 min
      Distance= 40m/min for 20 min
      = 800m

      Managed to do 1st question only.


      http://www.flickr.com/photos/63342911@N03/6093555012/

      posted in Primary 6 & PSLE
      S
      Snowball99
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